JEE Exam > JEE Videos > Mathematics (Maths) for JEE Main & Advanced > Straight Lines Solved Examples for JEE
Straight Lines Solved Examples for JEE Video Lecture | Mathematics (Maths) for JEE Main & Advanced
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FAQs on Straight Lines Solved Examples for JEE Video Lecture - Mathematics (Maths) for JEE Main & Advanced
| 1. How do you find the equation of a straight line given two points on it? |  |
Ans. To find the equation of a straight line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$, you can use the formula $y - y_1 = \frac{y_2 - y_1}{x_2 - x_1} (x - x_1)$.
| 2. What is the slope-intercept form of the equation of a straight line? | |
Ans. The slope-intercept form of the equation of a straight line is $y = mx + b$, where $m$ is the slope of the line and $b$ is the y-intercept.
| 3. How can you determine if two lines are parallel or perpendicular to each other? | |
Ans. Two lines are parallel if they have the same slope, and they are perpendicular if the product of their slopes is -1.
| 4. What is the distance between a point and a line in the coordinate plane? | |
Ans. The distance between a point $(x_0, y_0)$ and a line $Ax + By + C = 0$ is given by the formula $\frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}}$.
| 5. How do you find the equation of a line parallel or perpendicular to a given line passing through a specific point? | |
Ans. To find the equation of a line parallel to a given line with slope $m$, you can use the formula $y = mx + b$, where $b$ is the y-intercept determined by the point it passes through. For a line perpendicular to the given line, the slope will be $-\frac{1}{m}$.
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Oct 23, 2024 Last updated |
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