Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

Class 12 Chemistry 35 Years JEE Mains &Advance Past yr Paper

Created by: Abhishek Kapoor

JEE : Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

The document Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev is a part of the JEE Course Class 12 Chemistry 35 Years JEE Mains &Advance Past yr Paper.
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15. Calculate the quantity of electricity that would be required to reduce 12.3 g of nitrobenzene to aniline, if the current efficiency for the process is 50 per cent. If the potential drop across the cell is 3.0 volts, how much energy will be consumed?                 (1990 - 3 Marks)

 Ans:  115800 C, 347.4 kJ

Solution: 
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev


16. Zinc granules are added in excess to a 500 ml. of 1.0 M nickel nitrate solution at 25ºC until the equilibrium is reached. If the standard reduction potential of Zn2+ | Zn and Ni2+ | Ni are –0.75 V and –0.24 V respectively, find out the concentration of Ni2+ in solution at equilibrium.                   (1991 - 2 Marks)

Ans:  5.128´10-18 mol l-1

Solution: 
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

17. A current of 1.70 A is passed through 300.0 ml of 0.160 M solution of a ZnSO4 for 230 sec. with a current efficiency of 90%. Find out the molarity of Zn2+ after the deposition of Zn. Assume the volume of the solution to remain constant during the electrolysis.             (1991 - 4 Marks)

Ans:  0.154 M

Solution: 
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

18. For the galvanic cell.                                 (1992 - 4 Marks)

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev Calculate the EMF generated and assign correct polarity to each electrode for a spontaneous process after taking into account the cell reaction at 25ºC.

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 Ans:  – 0.037 V

Solution:
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

Since emf is negative this shows that the reaction is non- spontaneous.

NOTE: For the reaction to be spontaneous, its emf should be positive i.e. E = 0.037 V and its polarities should be reversed i.e. anode should be made cathode and vice-versa. So the galvanic cell is : Ag | AgBr(s), KBr || AgCl(s), KCl | Ag In other words, Ag | AgBr acts as anode and AgCl | Ag acts as cathode.

 

19. An aqueous solution of NaCl on electrolysis gives H2(g), Cl2(g) and NaOH according to the reaction :

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

A direct current of 25 amperes with a current efficiency of 62% is passed through 20 litres of NaCl solution (20% by weight). Write down the reactions taking place at the anode and the cathode. How long will it take to produce 1 kg of Cl2? What will be the molarity of the solution with respect to hydroxide ion? (Assume no loss due to evaporation.)                       (1992 - 3 Marks)

Ans:  48.69 hrs., 1.408 M

Solution: 
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

20.The standard reduction potential for the half-cell  Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

(i) Calculate the reduction potential in 8 M H+
  (ii) What will be the reduction potential of the half-cell in a  neutral solution? Assume all the other species to be at  unit concentration. (1993 - 2 Marks)

Ans:  (i) 0.887 V, (ii) 0.046 V

Solution: 
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

 21. Chromium metal can be plated out from an acidic solution  containing CrO3 according to the following equation.
  CrO3(aq) 6H (aq) 6e →Cr(s) 3H2O
Calculate (i) how many grams of chromium will be plated out  by 24,000 coulombs and (ii) how long will it take to plate out  1.5 g of chromium by using 12.5 amp current.                        (1993 - 2 Marks)

Ans: (i) 2.1554 g of Cr, (ii) 1336.15 sec

Solution: 

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

22. The standard reduction potential of the Ag+ /Ag electrode at 298 K is 0.799 V. Given that for AgI, Ksp = 8.7 × 10–17, evaluate the potential of the Ag+/Ag electrode in a saturated solution of AgI. Also calculate the standard reduction potential of the I/ AgI/Ag electrode.           (1994 - 3 Marks)

Ans:  0.325 V, – 0.149 V

Solution :
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev


23. The Edison storage cells is represented as
 Fe(s) | FeO(s) | KOH(aq) | Ni2O3(s) | Ni(s)
 The half-cell reactions are :

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

(i) What is the cell reaction ?
(ii) What is the cell e.m.f ? How does it depend on the concentration of KOH?
(iii) What is the maximum amount of electrical energy that can be obtained from one mole of Ni2O3?                               (1994 - 4 Marks)

Ans: (ii) 1.27 V, (iii) 2.45×105J

Solution :
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

24. Although aluminium is above hydrogen in the electrochemical series, it is stable in air and water. Explain.              (1994 - 1 Mark)

Solution :

The thin protective layer of oxides of aluminium is formed which protects the metal from further attack of water and air and make it stable.

 

25. An excess of liquid mercury is added to an acidified solution of 1.0 × 10–3 M Fe3+. It is found that 5% of Fe3+ remains at equilibrium at 25°C. Calculate  Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev  assuming that the only reaction that occurs is  

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev                   (1995 - 4 Marks)

 Ans:  0.792 V

Solution :
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

 

26. The standard reduction potential for Cu2+| Cu is +0.34 V. Calculate the reduction potential at pH = 14 for the above couple. Ksp of Cu(OH)2 is 1.0×10–19 (1996 - 3 Marks)

Ans:  – 0.22 V

Solution :

Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev
Subjective Questions of Electrochemistry, Past year Questions (Part - 2) - JEE Advance, Class 12 JEE Notes | EduRev

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