**Question 1: The method of orientation used, when the plane table occupies a position not yet located on the map, is called as [2017 : 1 Mark, Set-II]**

(a) traversing

(b) radiation

(c) levelling

(d) resection

**Answer: (d)**

**Solution: ****1. Traversing:** 'Traverse’ means to pass across. Traversing refer to the framework of series of lines forming an open or closed polygon.

**2. Radiation:** It is a method of locating a point by drawing a radial line from the plane table station to the station under consideration.

**3. Levelling:** It is the method of determining the difference of elevations or levels of different points on the earth’s surface.

**4. Resection: **It is the method of locating a station occupied by the plane table when the position of that station has not been plotted earlier on the sheet when the plane table occupied other station

**Question 2: The VPI (vertical point of intersection) is 100 m away (when measured the horizontal) from the VPC (vertical point of curvature). If the vertical curve parabolic, the length of the curve (in meters and measured along the horizontal) is ________. [2017 :1 Mark, Set-II]**

**Solution:**

**Question 3: A circular curve of radius R connects two straights with a deflection angle of 60°. The tangent length is [2016 : 1 Mark, Set-II]**

**(a) 0.577 R **

**(b) 1.155 R **

**(c) 1.732 R **

**(d) 3.464 R**

**Answer: (a)**

**Solution:**

Tangent length

**Question 4: In a survey work, three independent angles, X, Y and Z were observed with weights W**_{x}, W_{Y}, W_{z}, respectively. The weight of the sum of angles X, Y and Z is given by [2015 : 2 Marks, Set-T]

**Answer: (a)**

**Solution: **Various laws of weight

Let there be quantities A and B with weight W_{a} and W_{b} respectively

**Question 5: The chainage of the intersection point of two straights is 1585.60 m and the angle of intersection is 140°. If the radius of a circular curve is 600.00 m, the tangent distance (in m) and length of the curve (in m), respectively are [2014 : 2 Marks, Set-II] **

**(a) 418.88 and 1466.08 **

**(b) 218.38 and 1648.49 **

**(c) 218.88 and 418.82 **

**(d) 418.88 and 218.38**

**Answer: (c)**

**Solution: **

Δ = 180° - 140° = 40°

Length of the curve

Tangent distance (7) is the distance between

P-C to P.I (also the distance from P.I to P. T)

⇒ T = T_{1}V

= 600 tan 20° = 218.88 m

**Question 5: A tacheometer was placed at point P to estimate the horizontal distances PQ and PR. The corresponding stadia intercepts with the telescope kept horizontal, are 0.320 m and 0.210 m, respectively. The ∠QPR is measured to be 61° 30' 30". If the stadia multiplication constant = 100 and stadia addition constant = 0.10 m, the horizontal distance (in m) between the points Q and R is ______. [2014 : 2 Marks, Set-II]**

**Answer: **

PQ = ks + C

= 100(0.32) + 0.1 = 32.1 m

PR = ks + C

= 100(0.21) + 0.1 = 21.1 m

Applying the cosine rule