Theory - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math Class 9 Notes | EduRev

Mathematics (Maths) Class 9

Created by: Indu Gupta

Class 9 : Theory - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math Class 9 Notes | EduRev

The document Theory - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math Class 9 Notes | EduRev is a part of the Class 9 Course Mathematics (Maths) Class 9.
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Objective:

To show that the area of parallelogram is product of its base and height.

Theory:

A parallelogram is a simple quadrilateral with two pairs of parallel sides.

Theory - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math Class 9 Notes | EduRev

Properties:

  1. The opposite or facing sides of a parallelogram are of equal length.

  2. The opposite angles of a parallelogram are of equal measure.

  3. Opposite sides of a parallelogram are parallel (by definition) and so will never intersect.

  4. The area of a parallelogram is twice the area of a triangle created by one of its diagonals.

  5. Area of the parallelogram = base x height.

Example:

Theory - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math Class 9 Notes | EduRev
Find the area of parallelogram ABCD with base 24 m and height 17 m.

Solution :

 Area of the parallelogram = base x height = 24 X 17 =408
 ∴ The area of parallelogram ABCD is 408 m2

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