Torque - Class 11 Class 11 Notes | EduRev

Class 11 : Torque - Class 11 Class 11 Notes | EduRev

The document Torque - Class 11 Class 11 Notes | EduRev is a part of Class 11 category.
All you need of Class 11 at this link: Class 11


Ref: https://edurev.in/question/804023/Needed-a-Document-for-torque-Related-Rotational-Mo

What is Torque?

We can define torque as the measure of how much a force acting on an object causes that object to rotate. It is the twisting force that tends to cause rotation. The point where the object rotates is called as the axis of rotation. In physics, torque is simply the tendency of a force to turn or twist.

To explain torque in details let us consider the figure given below.

Torque - Class 11 Class 11 Notes | EduRev

We can see that the net force on the body is zero. Hence the body is in translational equilibrium. But the rod tends to rotate, this turning effect produced by force is known as moment of force or torque. Now we will consider the example of a door and try to formulate the equation for torque.

If we apply force closer to the hinge, then larger force is required to rotate the door. Also, it depends on the direction in which the force is being applied. If it is perpendicular to the line joining the hinge and the point of application of force then smaller force is required.

Torque Formula

From the above observation, we conclude that torque produced depends on the magnitude of the force and the perpendicular distance between the point about which torque is calculated and the point of application of force. So mathematically torque is represented as:

τ = F.r. sinθ

Torque - Class 11 Class 11 Notes | EduRev

Unit of torque is Newton–meter (N-m). The above equation can be represented as the vector product of force and position vector.

τ = r x F

So as it is a vector product hence torque also must be a vector. Using vector product notations we can find the direction of torque. We will consider an example to see how to calculate torque.

Examples Of Torque

Let us consider the situation given below:

Torque - Class 11 Class 11 Notes | EduRev

In the above diagram:

= 5N

r = 4m

sinθ = 30°

Putting these values we have,

τ = 5 x 4 x sin 30°

τ = 10 N-m

Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Content Category

Related Searches

Exam

,

practice quizzes

,

shortcuts and tricks

,

ppt

,

Sample Paper

,

Torque - Class 11 Class 11 Notes | EduRev

,

Torque - Class 11 Class 11 Notes | EduRev

,

video lectures

,

mock tests for examination

,

Viva Questions

,

Important questions

,

Objective type Questions

,

Summary

,

Previous Year Questions with Solutions

,

Torque - Class 11 Class 11 Notes | EduRev

,

Extra Questions

,

pdf

,

Semester Notes

,

study material

,

past year papers

,

Free

,

MCQs

;