The document Torque on Current Loop, Magnetic Dipole Notes | EduRev is a part of the Course Physics Class 12.

**Torque On Current Loop**

Let us consider a rectangular loop such that it carries a current of magnitude I. If we place this loop in a magnetic field, it experiences a torque but no net force, quite similar to what an electric dipole experiences in a uniform electric field.

Let us now consider the case when the magnetic field B is in the plane with the rectangular loop. No force is exerted by the field on the arms of the loop that is parallel to the magnets, but the arms perpendicular to the magnets experience a force given by F_{1},

**F _{1}=lbB**

This force is directed into the plane.

Similarly, we can write the expression for a force F_{2} which is exerted on the arm CD,

**F _{2}=lbB = F_{1}**

We see that the net force on the loop is zero and the torque on the loop is given by,

Where ab is the area of the rectangle. Here, the torque tends to rotate the loop in the anti-clockwise direction.

Let us consider the case when the plane of the loop is not along the magnetic field. Let the angle between the field and the normal to the coil be given by θ. We can see that the forces on the arms BC and DA will always act opposite to each other and will be equal in magnitude. Since these forces are the equal opposite and collinear at all points, they cancel out each other’s effect and this results in zero-force or torque. The forces on the arms AB and CD are given by F_{1} and F_{2}. These forces are equal in magnitude and opposite in direction and can be given by,

**F _{1 }=_{ }F_{2 }= lbB**

These forces are not collinear and thus act as a couple exerting a torque on the coil. The magnitude of the torque can be given by,

The magnetic moment of a current loop can be defined as the product of the current flowing in the loop and the area of the rectangular loop. Mathematically,

**m = IA**

Here, A is a vector quantity with the magnitude equal to the area of the rectangular loop and the direction is given by the right-hand thumb rule. In the equation written earlier, we can see that the torque exerted on a current-carrying coil placed in a magnetic field can be given by the vector product of the magnetic moment and the magnetic field.

**τ = mxB**

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