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**TYPE 1-** **To find out the position of the letter according to the given condition.****Note:**if we are moving to the left hand side of any letter that

Means positions are decreasing and if we are moving

Towards right hand side of the series that means

Positions of the letters are increasing.

**(1) Which letter is 5 ^{th} to the right of 12^{th} letter from let hand side on the series ?**

12+5 = 17

Letter 17

Therefore,

14 + 26 = 40.

40 - 17 = 23,

which means letter which is on 17

**(2) Which letter is 5 ^{th} to the left of 12^{th} letter from the left hand side on the series?**

12 – 5 = 7

Which falls in first half of the series which starts from position 1

1 + 13 = 14, 14 – 7 = 7th

Which is letter “g” in the real series.

(Position is same even in reversed series, because letter 7 is in the middle of the series, and its position will not Changed even after letter get reversed)

**(3) Which letter is 5 ^{th} to left of 12^{th} letter from the right hand side on the series?**

In this case first of all we will convert 12

Means, we have to find 5

Which falls in first half of the series.

Therefore,

1 + 10 = 14, 14 – 10 = 4th

Which is letter “d”.

**(4) Which letter is 5 ^{th} to the right of 12^{th} letter from right hand side of the series?**

12

Means, 15 + 5 = 20,

Which falls in second half of the series. Therefore,

14 + 26 = 40, 40 – 20 = 20th

Which is letter “t”.

(because position 20 is in middle of second half of the series).

Option C

**Q.2. P, ?, J, G, D, A****(a) Q****(b) N****(c) K****(d) M****(e) None of The Above****Solution :-**

Option D

**Q.3. ?, E, G, J, N****(a) A ****(b) B****(c) D****(d) Z****(e) None of The Above****Solution :-**

Option C

**Q.4. X, F, Y, G, ?, H****(a) Z****(b) A****(c) B****(d) Y****(e) None of The Above****Solution :-**

Option A

**Q.5. B, B, A, D, ?, F ****(a) B****(b) A****(c) Z****(d) C****(e) None of The Above ****Solution :-**

Option C

**TYPE-3** **Fill in the blank series:**

These types of series consist of small letters which follow a specific pattern or series. Some spaces are left blank in between the series given. We have to fill in the blanks from given options to make a pattern. This can be clearly explained by following examples:

**Example 1: ** a _ c a a _ b c c _ a a b bb _ c c

(a) bbca

(b) abac

(c) bbac

(d) bacb

We can solve questions of these types by following steps:**1.** Check out total number of positions in the statement which is 18 here.**2.** Now,18 can be divided by 2, 3, 6, 9 if the pattern here is of groups of equal size.**3.** We can’t divide them in group of 2 or 3 letters here because of repeated letters in the last of series.**4.** If we divide them in group of 6 or 9 letters each then also we are not getting a particular pattern here.**5.**** **Hence, groups here are in of different size.**6.** Considering this part _ a a b bb _ c c, we can see that letter “b” comes thrice here, which means letter”a” and “c” also could be thrice and if we fill this with a and c respectively , we will get that – a aa b bb c cc .**7.** That means , in the previous groups letters are repeated twice- a a _ b c c. if we fill it with “b”, we will get that.**8.**** **So, groups here are formed by all the three letters first one time then twice and at last thrice.**9.**** **By looking at the options we will get option (c) – bbac is our ans.

**Example 2:** a _ b b a a _ b a a _ b a a b _ a a b

(a) abab

(b) baba

(c) abbb

(d) babb

We can solve this by following steps:**1.**** **If we look at the total no. of positions that are 19**2.** Because, 19 is a prime number that means we can’t divide this, so we can use either 18 or 16 letters to divide in groups**3.** If we are taking 18 letters , we can divide it in groups of 3, 6, and 9 letters from which we will get optimum numbers and size of group if we divide by 6. But , it will also not lead to particular pattern.**4.** If we are taking 16, we can divide it in groups of 2, 4, and 8 letters of which we will get optimum number and size of group if we divide it by 4. therefore,-a _ b b a a _ b a a _ b a a b _ a a b,**5.** Now, we will get same group of same size, therefore pattern is - a a b b a a b b a a b b a a b b a a b

Which we will get with the help of option (c) – abbb..

**Example 3:** a _ b c a a _ _ aa b _ a a _ c a a _ c

(a) accbbb

(b) acbcbb

(c) cbcbba

(d) abccbb

We can solve this by following steps:**1.** Total no. of postions here are 20 which can be divided by 2, 4, 5 and 10**2.** To make optimum group of optimum size either we can divide it by 4 or by 5.**3.** So,if we make groups of 4 letters each :

a _ b c a a _ _ aa b _ a a _ c a a _ c,

We will get identical groups.**4.**** **Therefore, the pattern is –

a a b c a a b c a a b c a a b c a a b c ,

which we will get with the help of option(d) – abccbb.**TYPE-4** **Miscellaneous Questions **** **

In the exam one can also ask questions to make meaningful word, or by arranging letters in ascending or descending order, or by getting the same gap in between two letters as in the alphabet series.

Let us discussed one example of each type.

**Example 1:** If the letters of the word “ BEAUTIFUL” are arranged in Ascending/increasing order. How many letters are

There whose position will not change?

(a) 4

(b) 3

(c) 1

(d) 2**Solutions:**

2 5 1 21 20 9 6 21 12

B E A U T I F U L

In ascending order :

1 2 5 6 9 12 20 21 21

A B E F I L T U U

As we can see only letter “U” is on same position after rearrangement. Therefore, answer is option – (c).

**Example 2: **How many pairs are there in the word “BEAUTIFUL”

Which have same number of letters between them as

In the alphabet series?

(a) 1

(b) 4

(c) 3

(d) none**Solutions:**

Therefore, ans is option - (b)

**Example 3:** – With the help of letters “ E , S, R , O” each letter used

Ones, how many meaningful words can be formed?

(a) 1

(b) 2

(c) 3

(d) none**Solutions:** With the help of these letters only one word is formed-

ROSE. Hence, answer is option – (a)

(NOTE : These types of questions are just to check your General intelligence).

**Example 4:** With the help of the letters “A, D, E, R” each letter used

Ones, how many meaningful words can be formed?

(a) 2

(b) 3

(c) more than 3

(d) none**Solutions: **with the help of these letters words formed are :

1-READ, 2-DEAR, 3-DARE, 4-RADE.

Hence, answer is option- (c).

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