Units And Dimensional Analysis JEE Notes | EduRev

Chemistry Class 11

JEE : Units And Dimensional Analysis JEE Notes | EduRev

The document Units And Dimensional Analysis JEE Notes | EduRev is a part of the JEE Course Chemistry Class 11.
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UNITS AND DIMENSIONAL ANALYSIS: CONVERSION OF UNITS 
The simplest way to carry out calculations that involve different units is to use dimensional analysis.
The simplest way to carry out calculations that involve different units is to use dimensional analysis.
As there is a need to convert units from one system to the other. The method used to accomplish this is called factor label method or unit factor method or dimensional analysis.

In this method a quantity expressed in one unit is converted into an equivalent quantity with a different unit by using conversion factor which express the relationship between units:

Units And Dimensional Analysis JEE Notes | EduRev

This is based on the fact that ratio of each fundamental quantity in one unit with their equivalent quantity in other unit is equal to one For example, in case of mass
1 kg = 2.205 pound = 1000 gm
In this way any derived unit first expressed in dimension and each fundamental quantity like mass length time are converted in other system of desired unit to work out the conversion factor.
For example: How unit of work / energy i.e. joule, in S.I. system is related with unit erg in C.G.S system
Dimension of work = force x displacement = MLT-2 × L = ML2T-2 
1 joule = 1 kg (1 metre)2 × (1sec)-2
⇒ 1 × Kg × 1000 gm/1Kg × [1 metre × 100 cm/1 metre] × [1 sec]-2
⇒ 100 gm × (100)2 × 1 em2 × (1 sec)-2
⇒ 1000 × 10000 × 1 gm × 1 cm2 × 1 sec-1
⇒ 1 joule = 107 erg

Similarly, we can deduce other conversion factor for other quantity in different unit by the dimensional analysis method.
Another interesting example is the conversion of liter – atmosphere to joule (the SI unit of energy) by multiplying with two successive unit factors.
Thus,
1 L atm × (10-3 m3/1L) × 101.325 Pa/1 atm 
= 101. 325 Pa M3 
Knowing that Pa = N/m2,
we can write
101.325 Pa m3 = 101.325 (N/m2) m3 
= 101.325 N m = 101.325 J
Hence, 1 L atm = 101.325 J  

MASS AND WEIGHT
Mass of a substance is the amount of matter present in it while weight is the force exerted by gravity on an object. The mass of a substance is constant whereas its weight may vary from one place to another due to change in gravity. The mass of a substance can be determined very accurately by using an analytical balance.

Volume
Volume has the units of (length)3. So, volume has units of m3 or cm3 or dm3. A common unit, litre (L) is not an SI unit, is used for measurement of volume of liquids.
1 L = 1000 mL,
1000 cm3 = 1 dm3

Units And Dimensional Analysis JEE Notes | EduRev

Fig: Some volume measuring devices


DENSITY
Density of a substance is its amount of mass per unit volume.SI unit of density = SI unit of mass/SI unit of volume = kg/m3 or kg m–3. This unit is quite large and a chemist often expresses density in g cm–3.Units And Dimensional Analysis JEE Notes | EduRevFig: Relationship between density, mass and volumeTEMPERATURE
There are three common scales to measure temperature:-
1) °C (degree Celsius)
2) °F (degree Fahrenheit) and
3) K (kelvin)
Here, K is the SI unit.

Conversion Formulas: 
1. K = °C + 273.15

2. °F = (9/5) °C +32

Note — Temperature below 0 °C (i.e. negative values) are possible in the Celsius scale but in the Kelvin scale, the negative temperature is not possible.
Units And Dimensional Analysis JEE Notes | EduRev

Fig: Temperature Kelvin scale

Example 1. What is the mass of 1 L of mercury in grams and in kilograms if the density of liquid mercury is 13.6 g cm−3?
Solution. We know the relationship, 1 L = 1000 cm3 and
Also, density = mass/volume
We can write, mass = (volume) (density)
Therefore, the mass of 1 L of mercury is equal to

Units And Dimensional Analysis JEE Notes | EduRev 
The mass in kilograms can be calculated as
Units And Dimensional Analysis JEE Notes | EduRev
(Remember,
Units And Dimensional Analysis JEE Notes | EduRev
are conversion factors with which we have to multiply for getting our answer in appropriate units).

Example 2. How unit of velocity i.e. kilometer/hour is related to unit meter/second.
Solution. We know the relationship, velocity = total displacement/total time 

Units And Dimensional Analysis JEE Notes | EduRev

Prefixes in SI system

Name

Symbol

Quantity

 yotta

 Y

 1024

 zetta

 Z

 1021

 exa

 E

 1018

 peta

 P

 1015

 tera

 T

 1012

 giga

 G

 109

 mega

 M

 106

 kilo

 k

 103

 hecto

 h

 102

 deca

 da

 10

 deci

 d

 10-1

 centi

 c

 10-2

 miIIi

 m

 10-3

 micro

 M

 10-6

 nano

 n

 10-9

 pico

 P

 10-12

 fempto

 f

 10-15

 atto

 a

 10-18

 zepto

 z

 10-21

 yocto

 y

 10-24

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