Table of contents | |
Gradient of a Velocity-Time Graph | |
Acceleration on a Velocity-Time Graph | |
Calculating the Gradient of a Velocity-Time Graph | |
Exam Tip | |
Solved Example |
Part (a)
Step 1: Recall that the slope of a velocity-time graph represents the magnitude of acceleration
(i) The slope of a velocity-time graph indicates the magnitude of acceleration
(ii) Therefore, the only sections of the graph where Tora is accelerating is section B and section D
(iii) Sections A, C, and E are flat – in other words, Tora is moving at a constant velocity (i.e. not accelerating)Step 2: Identify the section with the steepest slope
(i) Section D of the graph has the steepest slope
Hence, the largest acceleration is shown in section DPart (b)
Step 1: Recall that the gradient of a velocity-time graph gives the acceleration
(i) Calculating the gradient of a slope on a velocity-time graph gives the acceleration for that time periodStep 2: Draw a large gradient triangle at the appropriate section of the graph
A gradient triangle is drawn for the time period between 5 and 10 seconds below:Step 3: Calculate the size of the gradient and state this as the acceleration
(i) The acceleration is given by the gradient, which can be calculated using:
acceleration = gradient = 5 ÷ 5 = 1 m/s2
(ii) Therefore, Tora accelerated at 1 m/s2 between 5 and 10 seconds
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