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Word Problem: Multiplication | Mathematics for Class 2 PDF Download

Q1: 24 folders each has 56 sheets of paper inside them. How many sheets of paper are there altogether?
Ans: 
We can add 56 sheets 24 times
OR
Since multiplication is repeated addition we can multiply 56 and 24 to get the answer.
Word Problem: Multiplication | Mathematics for Class 2
Therefore, altogether there are 1344 sheets.

Q2: A carton holds 24 packets of biscuits. Each packet has 12 biscuits. How many biscuits can be packed in 45 cartons?
Ans:
In one carton we can pack 24 × 12 biscuits.
In 45 cartons, we can pack 24 × 12 × 45 biscuits.
24 × 12 = 288
Word Problem: Multiplication | Mathematics for Class 2
Therefore, altogether there are 12,960 biscuits.

Q3: There are 226 pencils in a packet. How many pencils are there in 212 such packets?
Ans:
Number of pencils in 1 packet = 226
Number of packets = 212
Total number of pencils = 226 × 212
= 47912
Word Problem: Multiplication | Mathematics for Class 2

Q4: A book costs $ 67. How much will be paid for 102 such books?
Ans: 
The cost of one book = $ 6 7
Number of books = 1 0 2    
The cost of 102 books = $ 67 × 102
= $ 6834

Word Problem: Multiplication | Mathematics for Class 2
Therefore, cost of 102 books = $ 6834

Q5: A bicycle costs $ 215. How much will be paid for 87 such bicycles?
Ans: The cost of one bicycle  = $ 215
Number of bicycle = 87
The cost of 87 bicycles = $215 × 87
= $ 6834
Word Problem: Multiplication | Mathematics for Class 2
Therefore, cost of 87 bicycles = $ 18705

Q6: The monthly salary of a man is $ 2,625. What is his annual income by salary?
Ans: Monthly income = $2,625
Annual income = $2,625 × 12
= $31,500
Word Problem: Multiplication | Mathematics for Class 2
Therefore, annual income = $ 31,500

Q7: A chair costs $ 452 and a table costs $ 1750. What will be cost of 15 chairs and 30 tables?
Ans:  

(i) Cost of one chair = $ 452
Cost of 15 chairs = $ 452 × 15
= $ 6,780
(ii) Cost of one table= $ 1,750
Cost of 30 tables  = $ 1,750 × 30
= $ 52,500
Therefore, cost of 15 chairs and 30 tables = $ 6,780 + $ 52,500

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