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Structure of Atom, Class 11, Chemistry Detailed Chapter Notes PDF Download

Different models of atom - Structure of Atom, Class 11, Chemistry

Different models of atom

(1) Dalton's atomic model.

Dalton's atomic model is one of the fundamentals of physics and chemistry. This theory of atomic composition was hypothesized and partially confirmed by the English chemist and Physicist John Dalton. Dalton came with his Atomic theory as a result of his research into gases. He discovered that certain gases only could be combined in certain proportions even if two different compounds shared the same common element or group of elements. Through deductive reasoning and experimentation, he made an interesting discovery. His findings led him to hypothesize that elements combine at the atomic level in fixed ratios. This ratio would naturally differ in compounds due to the unique atomic weights of the elements being combined.

This was a revolutionary idea but further experimentation by himself and others confirmed his theory. The findings became the basis of Dalton's Atomic Laws or Model. These laws focus on five basic theorems.

(1) Pure Elements consist of particles called atoms.

(2) Atoms of an element are all the same for that element. That means gold is gold and oxygen is oxygen down to the last atom.

(3) Atoms of different elements can be told apart by their atomic weights.

(4) Atoms of elements unite to form chemical compounds.

(5) Atoms can neither be created or destroyed in chemical reaction. The grouping only changes.

(2) Thomson's model or Plum Pudding model or Raisin Pudding model or water melon model.

Thomson stated that atom is uniform sphere of positive charge with negatively charged electron embedded in it in such a way that atom becomes electrically neutral.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important features :

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation It shows electrical neutrality of atom.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation The mass of the atom is assumed to be uniformly distributed over the atom.

The model was rejected as it was not consistent with the results of alpha scattering experiment.

(3) Rutherford's Nuclear Model of Atom :

α-particle scattering experiment :-

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

A beam of α-particle was projected towards this gold foil. The foil was surrounded by circular fluorescent ZnS screen which produces flash when α-particle collide with it.

Observations of experiment :

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Most of α-particles passed through the foil un deflected or deflected by very small angles

[less than 1º].

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Few particles were deflected through angles as large as 90º.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Very few particles [ 1 in 20 thousand] bounce back or rejected through an angle almost equal to 180º.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Angle of deflection increases with increase in atomic number.

Conclusions

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Since, most of the α-particles passed through the foil un deflected, therefore there must be large empty space present in the atom. 

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation α-particles are positively charged and having considerable mass could be deflected by only some heavy positively charged centre by repulsion.[Rutherford named this positively charged heavy centre as nucleus]

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Since, very few α-particles were thrown back therefore the size of nucleus should be very small and is should be rigid because α-particle can recoil back only if it undergo direct collision with the heavy positively charged centre.

Rutherford's model

On the basis of scattering experiment, Rutherford proposed an atomic model or nuclear atomic model or nuclear model of atoms.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation The electrons are revolving around the nucleus in circular path and electrostatics force of attraction between the electrons and nucleus is balanced by the centrifugal force acting on revolving electron.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation The -ve charge on electrons are equal to the total positive charge on the nucleus and therefore as a whole atom is electrically neutral.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Size of the nucleus is extremely small as compared to size of the atom.

Radius of nucleus

Radius of nucleus is of the order of 10-15 m and radius of atom is order of 10-10 m.

r = r0A1/3

A = Mass number = no. of protons no. of neutrons.

r0 = constant = 1.2 × 10-13 cm.

Distance of closest approach :

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

If the α-particle is projected with some velocity -v from very large distance then at point (1), energy of the α-particle Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

 

As the particle is moving closer to the nucleus of other particle, repulsive coulombic force increase (P.E. increases) and velocity of the particle decrease kinetic energy is converted into P.E.

At point (2) E = K.E. P.E. = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

[As no ext. force is acting, Total energy of system remains constant]

velocity becomes zero at rmin distance where columbic potential energy of repulsion becomes equal to the initial kinetic energy.

At point (3),

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

q1 = z1e ; q2 = z2e

e = electronic charge = 1.6 × 10-19 C

z1 = z2 = Atomic number

Failures of Rutherford's Model :

(1) According to maxwell's wave theory, an accelerated charged particles (like electron) revolving in the field of another charged particle like nucleus looses energy in the form of electromagnetic radiation and if this happen then orbit of the revolving electron should keep on decreasing and ultimately electron should fall into the nucleus and atom should collapse but this dosen't happen actually.

(2) Rutherford's model didn't give any idea about electronic arrangement of an atom and since he didn't mention specific energy levels he couldn't explain the discontinuous atomic hydrogen spectrum.

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Wave Nature of Electromagnetic RadiationAbsorption and Emission Spectra - Structure of Atom, Class 11, Chemistry

Waves and its Characteristics

It is a periodical disturbance causing transfer of energy without transfer of matter.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Characteristics of waves :

Amplitude : Maximum displacement from mean position it remains constant with distance except stationary or standing waves.

Wavelength : It is the distance between two adjacent crest or troughs.

Frequency (m or n) : The no of waves passing through a point in 1second, unit-sec-1 or Hz

Wave number Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation : No. of waves present in unit distance.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation etc.

Velocity : linear distance travelled by wave in one second.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation 

Nature of light

Maxwell electromagnetic wave theory (wave nature of light) :

An accelerated electrically charged particle produces and transmits electrical and magnetic field. These are transmitted in the form of waves known as electromagnetic waves or electromagnetic radiations.

He stated that light also possess electrical and magnetic field and it is also known as electromagnetic radiations or e.m.w.

Characteristics of Electromagnetic Radiations :

1. In these electromagnetic radiation electrical and magnetic field oscillates ⊥ to each other and it also propagates ⊥ to both field.

2. All these electromagnetic radiation do not require any medium and can travel in vacuum.

3. Velocity of all electromagnetic radiation is 3 × 108 m/s in vacuum.

4. Energy of an electromagnetic wave is directly proportional to intensity and it is independent of frequency.

5. There are also showing diffraction and interference

And therefore. Maxwell concluded light to be wave nature.

But Maxwell theory couldn't explain the results of photoelectric effect and black body radiations.

Photon Energies for EM Spectrum

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

A Blackbody

A blackbody is an object that emits a well defined spectrum of radiation solely based on its temperature. We see from figure at right that the hotter the blackbody, the more intense it is, and the shorter the peak wavelength.

The picture does not say anything about what the object is made of, or how heavy it is, etc. It doesn't matter! The only property that determines the spectrum of a blackbody is its temperature. Brick, iron or a dense gas will emit the same spectrum as long as they are at the same temperature. That spectrum will have a peak that lies at a particular wavelength.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Planck's Quantum Theory : [Particle nature of light]

He stated that a body radiates energy in the form of discontinuous energy packets or bundles. Each bundle of energy is known as quantum and quantum of light is known as photons.

Energy of each quantum is directly proportions to frequency of radiation.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

E = hn h = 6.62 × 10-34 Js.

¯

Plank's constant

Total energy absorbed or emitted by a body will be whole no. integral multiple of energy of quantum

Eabs or Eemitted = nhν

Ex. Calculate the no. of photons emitted by 60 watt bulb in 10 hrs. When light of wavelength 6000 Å is emitted by it.

Sol. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = 6.5 × 1024

Energies in Electron Volts

Room temperature thermal energy of a molecule..................................0.04 eV

Visible light photons................................................................ ......1.5-3.5 eV

Energy for the dissociation of an NaCl molecule into Na and Cl- ions:.......4.2 eV

Ionization energy of atomic hydrogen ..............................................13.6 eV

Approximate energy of an electron striking a color television screen (CRT display) ....................20,000 eV

High energy diagnostic medical x-ray photons..................200,000 eV (=0.2 MeV)

Typical energies from nuclear decay:

(1) gamma..................................................................................0-3 MeV

(2) beta.....................................................................................0-3 MeV

(3) alpha....................................................................................2-10 MeV

Cosmic ray energies ...........................................................1 MeV - 1000 TeV

1 MeV = 106 eV, 1 GeV = 109 eV, 1 TeV = 1012 eV

Explanation of black body radiations using Planck's quantum theory :

When a solid substance like iron piece is heated it emits radiations. As heating is continued, more and more energy is being absorbed by the atom and hence, more energy will be emitted and therefore energy of e.m.w. increases and frequency of e.m.w. increases and therefore body first becomes red then yellow and finally white.

Therefore, it can be concluded that light posses particle nature and energy of electromagnetic radiation depends upon frequency.

Explanation of Photo electric Effect using Planck's Quantum Theory :

When a metal sheet is subjected to electromagnetic radiation of suitable frequency then some electrons are ejected from metal surface and these electrons are known as photoelectron and the effect is known as photoelectric effect.

If electromagnetic radiation of low frequency are used then there is no ejection of electron inspite of continuous increasing intensity. This observation was contradicting to maxwell theory according to which energy electromagnetic radiation ∝ I but can be explained using Planck's quantum theory i.e.

E ∝ ν.

Dual nature of light

Since, wave nature of light explains diffraction interference phenomenon while particle nature explains black body radiation and photo electric effect light was considered to have dual nature particle nature as well as wave nature.

Electromagnetic spectrum :

The arrangement of all the electromagnetic radiation in a definite order (decreasing or increasing of wavelength or frequency is known as electron magnetic spectrum

Spectrum

When light coming from a source is passed through a prism, the radiation of different wavelength deviated through different angles and get separated.

Angle of deviation ∝ n ∝ Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation 

this process is called dispersion.

And such a collection or dispersed light giving its wavelength composition is known as spectrum.

Spectrum are of two types.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(1)

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(2) Absorption :

Emission spectrum

This is the spectrum of radiations emitted by any source or atom or molecule of any substance (Which is excited by heating or electric discharge).

(i) Continuous Spectrum :

When white light from a source is dispersed, a bright spectrum continuously distributed on the dark background is obtained. The colours are continuously changing from violet to red and there is no Sharp boundaries between various colour. These colours appear to be merge into each other and therefore spectrum is known as continuous spectrum.

(ii) Discontinuous Spectrum :

When a atom is subjected to electromagnetic radiation, it cause excitation of electron to higher energy level. When electrons return back to lower energy level, it emits certain radiations corresponding to difference in energy level and therefore spectrum obtained in case of atom is discontinuous spectrum having specific wavelength is known as Atomic spectrum or line spectrum.

Absorption Spectrum :

When an atom is subjected to white light it absorbs some specific radiation corresponding to the difference in energy level the remaining radiations (transmitted radiations) are devoid of certain specific frequencies which is observed in the form of missing line and this spectrum is known as absorption spectrum.

It is photographic negative of emission spectrum i.e. those bright lines which are present in emission spectrum of an atom are missing.

In the absorption spectrum and observed in the form of dark lines.

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Bohrs Model of Hydrogen Atom nad Photoelectric Effect - Structure of Atom, CBSE, Class 11, Chemistry

(4) Bohr's Model

It was the first model based on Planck's quantum theory and the model explained stability of atom and line spectrum of hydrogen.

Postulates of Bohr's model

1. An atom consist of centrally located small, dense, positively charged nucleus and electrons are revolving around the nucleus in circular paths known as circular orbits and coulombic force of attraction between nucleus and electron is balanced by centrifugal force of the revolving electron.

2. Out of the infinite circular orbits only those circular orbits are possible in which angular momentum of electron is integral multiple of h/2p i.e. angular momentum of an electron can have fixed values like Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation etc. i.e., angular momentum of electron is quantised.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

m and v are mass and velocities of electron respectively and r is radius of orbit and n is integer which is later related with orbit number and shell number and h is Plank's constant.

3. The energy of these circular orbits have fixed values and hence electron in an atom can have only certain values of energy. It is characteristic of an orbit and it cannot have any orbit value of its own. And therefore energy of an electron is also quantised.

4. As long as electrons remains in these fixed orbits, it dosen't lose energy i.e. energy of an electron is stationary (not changing with time) and therefore these orbits are known as allowed energy levels or stationary states and this explains the stability of atom.

5. The energy levels are designated as K, L, M, N and numbered as 1, 2, 3, 4 etc from nucleus outwards and as the distance of the shell's or energy level from the nucleus increases the energy of the energy level also increases i.e., EN > EM > EL > Ek

6. The emission or absorption of energy in the form of radiations can only occur when an electron jump from one stationary states to other.

DE = Ehigher - Elower

DE = hn where hn is the energy of absorbed photon or emitted photon which corresponds to the difference in energy levels. Energy is absorbed when electron jumps from lower energy level (normal state) to higher energy level (exited, unstable state) and energy is emitted when electrons jumps from higher energy level to lower energy level.

Bohr's model is applicable for a one electron species only, like H, He , Li 2, Be 3 etc.

Derivation of Radius of different orbits in one electron species (using Bohr's model) :

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation ....(1)

q1 = e, q2 = Ze

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation ....(2)

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

r = 0.529 × Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

r ∝ Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

for a particular atom r ∝ n2

Radius of 1st orbit of H atom

r = 0.529 Å

Ex. Calculate ratio of radius of 1st orbit of H atom to Li 2 ion :

Sol. = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Derivation of Velocity of electron in Bohr's orbit :

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation, putting value of r.

v = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

v = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

v = 2.18 × 106 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation m/s

v ∝ Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Derivation of total energy of electron / system :

T.E. of system = K.E. of e- P.E. of system (nucleus and e-)

kinetic energy of electron = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

PE = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation


Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

T.E. = - 13.6 × Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation eV/atom

T.E. = - 2.18 × 10-18 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation J/atom

As shell no. or distance increases, the value of T.E. and P.E. increases (however magnitude decreases) and becomes maximum at infinity i.e., zero.

negative sign indicates that electron is under the influence of attractive forces of nucleus.

K.E. = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

T.E = - K.E.

Calculation of energy of energy level in H atom

(i) When n = 1 (ground level)

K.E. = 13.6 eV (atom)

P.E. = -27.2 eV / atom

T.E. = -13.6 eV/atom

(ii) When n = 2/2nd energy level / 1st excited state

K.E. = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation eV/atom = 3.4 eV/ atom

P.E. = - 6.8 eV/atom

T.E. = - 3.4 eV/atom

E2 - E1 = -3.4 13.6 eV/atom = 10.2 eV/atom

(iii) When n = 3 / 3rd energy level/2nd excited state.

K.E. = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation eV/atom = 1.51 eV/atom

P.E. = -3.02 eV/atom

T.E. = -1.51 eV/atom

-E3 - E2 = -1.51 eV/atom 3.4 eV/atom

= 1.89 eV atom.

(iv) when n = 4 / 3rd excited state

K.E. = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = 0.85 eV/atom

P.E. = -1.70 eV/atom T.E. = -0.85 eV/atom

E4 - E3 = 0.66

As distance increases (n increases) energy of the energy level increases but energy difference between consecutive energy level keeps on increasing i.e., maximum energy difference between 2 to 1 (consecutive)

If reference value (P.E at ∞) is assigned value other than zero. -

(i) All K.E. data remains same.

(ii) P.E./T.E. of each shell will be

changed however difference in P.E./T.E. between 2 shell will remain unchanged.

Hydrogen spectrum (Before Bohr's Model)

The spectrum of H atom is observed as discontinue line spectra. The line spectra of different in 3 region UV, visible and IR. The different lines observed H spectrum were classified in to different series and named after their discoverers.

Rydberg gave an empirical formula to calculate wavelength, which is applicable to all series.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation RH = 109677 cm-1 Rydberg's constant.

n1 and n2 are integers.

Explanation of Hydrogen spectrum using Bohr's model

When electron in an excited atom comes back from higher energy level (n2) to lower ever level (n1) then it emits a photon, having energy equal to difference in energy levels.

hn = DE =

hn = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

hn = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

The theoretical value is very closed to observed value

Bohr's model provides theoretical explanation of H spectrum.

Wavelength or wave no. of any line of any one electron species can be calculated as

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = RHZ2 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation, Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation → nm

Different series in Hydrogen spectrum.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Lyman series : nf = 1, ni = 2, 3, 4, 5, - - - - - - - -

Ultraviolet

Balmer series : nf = 2, ni = 3, 4, 5, 6, - - - - - - - -

visible

paschen series : nf = 3, ni = 4, 5, 6, 7, - - - - - - - -

infrared

brackett series : nf = 4, ni = 5, 6, 7, - - - - - - - -

infrared

pfund series : nf = 5, ni = 6, 7, - - - - - - - -

farinfrared

humphrey series : nf = 6, ni = 7, 8, - - - - - - - -

farinfrared

Ex. Calculation of different types of maximum possible radiations which can be observed in (from higher energy level to lower energy level)

Sol. n2 = n, n1 = 1

Total no. of radiation obtained having difference wave lengths = Transition ending at 1st level Transite

ending at 2nd level .................................................. Transition

ending at (n - 1) energy levels.

= Total no. of radiation in lyman series total no. of radiation in Balmer series ................... Total no. of radiation in (n - 1) series.

= (n - 1) (n - 2) (n - 3) ........................ 2 1

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation............................ 2 1

Total no. of different radiation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

N = difference in higher energy level and lower energy level

Ex. The energy level of an atom for 1st, 2nd and third levels are E, 4E, 2E respectively. If photon of wavelength l is emitted for a transition 3 to 1. Calculate the wavelength for transition 2 to 1 in terms of l.

Sol. 2E - E = E = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation ⇒ 3l = l2

Ex. Let n1 be the frequency of series limit of lyman series, n2 be the frequency of 1st line of lyman series, n3 be the frequency of series limit of Balmer series. Then find relation between n1, n2 and n3

Sol. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

E1 = E2 E3

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation ⇒ n1 = n2 n3

Ex. Hydrogen like species is observed to emit 6 wavelengths originating from all possible transitions between a group of levels these energy levels have energy between - 0.85 eV and -0.544 eV (including both these energy levels) calculate

(i) The quantum number of levels between which transition is taking place.

(ii) Find the atomic number of species.

Sol. (n2 - n1) (n2 - n1 1) = 12

n2 - n1 = x x(x 1) = 12

n2 = n1 3

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation n1 = 12 ; n2 = 15

Failures of Bohr's Model :

(i) It is applicable only for one electron species.

(ii) He couldn't explain the fine spectrum of hydrogen when a powerful spectroscope is used then several lines which are very closely placed are observed in addition to the expected lines later this problem was solved by Sommerfeld who introduced the concept of sub shell.

(iii) He couldn't explain splitting of spectral lines into a group of finer lines under the influence of external magnetic field (Zeeman effect) or under the influence of external electric field (stark effect).

(iv) He couldn't give theoretical reason for most of his assumption, for example he couldn't justify why angular momentum of electron should be quantised.

(v) Spectrum of isotopes of hydrogen were expected to be same according to the Bohr's model but found different experimentally.

(5) Sommerfeld model of Atom

Three refinements of the Bohr model were worked out by Arnold. Sommerfeld and are jointly responsible for giving rise to small deviations in the allowed energies from the values En These refinements brought the calculated frequencies into even better agreement with observation (from four to five significant digits). The refinements were:

(a) the introduction of elliptical orbits;

(b) allowance for an orbiting motion of the nucleus; and

(c) the consideration of relativistic mass effects.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Photo electric effect

Emission of electron from the metal surface when the light of suitable frequency is subjected to the metal surface. The effect is known as photoelectric effect and the ejected electrons are known as photoelectrons.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Terms used in photo electric effect

(1) Work function (w) : It is the minimum amount of energy required to cause a photo emission from the metal surface. It is also known as threshold energy or Binding energy. [Work function depends upon ionisation energy and therefore w is minimum for alkali metals).

(2) Threshold frequency (n0) : The minimum value of frequency that can cause photo emissions. If
n < n0, then there is no photo emission.

w = h n0 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(3) Threshold wavelength : (l0) The maximum value of wavelength that can cause photo emission.

If l > l0, then photo emission is not possible.

(4) Intensity (I) : Energy falling on metal surface of unit area of unit time

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(5) Photo intensity (IP) : It is number of photons falling per unit area per unit time.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Relation between I and Ip :

I = Ip hn

Photo intensity is independent of frequency while intensity depends on frequency.

Power : Total energy radiated per unit time.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Effect of variation of frequency

(a) Effect of Photo Emission :

I = Iphn

If frequency of subjected photon increases (intensity increases keeping photo intensity constant) then there is no change in no of ejected photo electrons as well as no change in photo current.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(b) Effect on kinetic Energy :

Average k. E. as well as k. E. max increases with increases in frequency.

h n - W = K Emax.

K Emax = hn - h n0 y = mx c

K Emax = h n -Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Kmax = hn - w

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Effect of Variation of Photo Intensity

On increasing intensity, keeping frequency constant (i.e. increasing photo intensity) no of ejected photo electrons increases as well as photo current increases.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Effect on Kinetic Energy

Average K.E. and K.Emax remains constant with change in photo intensity

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Stopping Potential or Retarding Potential (V0)

It is the minimum potential require to stop the fastest moving electrons completely or it is the minimum potential at which photo current becomes zero.

eV0 = hn - w

eV0 = hn - hn0

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

It can be commented that stopping potential increase with increase in frequency how ever if photo intensity is changed there is no effect on stopping potential.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Ex. In ultraviolet light of wavelength 200 nm is used in an experiment of photoelectric effect with lithium cathode (w = 2.5 eV). Then calculate

(i) K.Emax (ii) Stopping potential

Sol. K.Emax = hn - w

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

⇒ 6.2 - 2.5

⇒ 3.7 eV

Stopping Potential = 3.7 V

===================================================================

Dual nature Of Matter and Uncertainity Principle - Structure of Atom, Class 11, Chemistry

DeBroglie's hypothesis (dual nature of matter) :

deBroglie proposed that like light, electron possess dual nature i.e. behave like both as material particle and as wave. The concept of dual character of metal evolved a wave mechanical theory of atom according to which electrons. protons and even atoms possess wave properties when moving.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Derivation of deBroglie Relation ship :

For a photon,

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation ...(i)

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation ...(ii)

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

He concluded that as electromagnetic radiation have some associated mass or associated momentum, in the same way every moving particle of mass `m' and velocity `v' is associated with waves and these associated waves are known as matter waves or deBroglie's waves.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Experimentation verification of deBroglie's hypothesis : Given by Davission and Germer.

They observed that a beam of electrons are diffracted by nickel crystal just like the x-rays. More over it wavelength of the electrons determined by the diffraction experiments are equal to the values calculated from deBroglie's relations ship.

Derivation of Bohr's postulate of quantisation of angular momentum from deBroglie's Equations-

According to deBroglie moving electron is associated with waves must be completely in phase and there fore only those orbits are possible where circumference of the orbit is integral multiple of l i.e.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation, where n is the no. of waves

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

From the above expression it can be commented that

no of waves in a shell waves = shell no.

Calculation of deBroglie wavelength if K.E. of the particle is E :

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation 2E = mv2 2mE = m2 v2 = p2

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

If a charge particle at rest (having charge `q') is accelerated by potential difference `V' volt then

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation,

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation (Only for electron)

Ex. Calculate ldB of electron have K.E. 3eV

Sol. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation



Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation
 

The Uncertainty Principle

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

The position and momentum of a particle cannot be simultaneously measured with arbitrarily high precision. There is a minimum for the product of the uncertainties of these two measurements. There is likewise a minimum for the product of the uncertainties of the energy and time.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

The uncertainty principle contains implications about the energy that would be required to contain a particle within a given volume. The energy required to contain particles comes from the fundamental forces, and in particular the electromagnetic force provides the attraction necessary to contain electrons within the atom, and the strong nuclear force provides the attraction necessary to contain particles within the nucleus. But Planck's constant, appearing in the uncertainty principle, determines the size of the confinement that can be produced by these forces. Another way of saying it is that the strengths of the nuclear and electromagnetic forces along with the constraint embodied in the value of Planck's constant determine the scales of the atom and the nucleus.

Q. Does uncertainty principle violates energy conservation principle?

(6) Wave mechanical model of Atom

Schordinger equation :

The Schrodinger equation plays the role of Newton's laws and conservation of energy in classical mechanics - i.e., it predicts the future behavior of a dynamic system. It is a wave equation in terms of the wave function which predicts analytically and precisely the probability of events or outcome. The detailed outcome is not strictly determined, but given a large number of events, the Schrodinger equation will predict the distribution of results.

Hy = EY

The kinetic and potential energies are transformed into the Hamiltonian which acts upon the wave function to generate the evolution of the wave function in time and space. The Schrodinger equation gives the quantized energies of the system and gives the form of the wave function so that other properties may be calculated.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Where , E = total energy of electron

U = potential energy of electron

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation = Laplacian operator = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

and y = wave function of electron = amplitude of matter wave.

Schordinger equation can be solved completely for hydrogen atom and hydrogen-like species like He , Li2 .

The Schordinger equation can also be written in terms of spherical polar coordinates (r, q, f) in addition to Cartesian coordinate x, y, z.

Since, H-atom posses spherical symmetry, it is easier to solve schordinger equation if it is represented in polar coordinate.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

When schordinger equation in polar coordinate is solved for H-atom then the solution obtained can be expressed as

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation represents radial wave function which depends on n, l.

→ Angular wave function which depends on m, l.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation(Psi) : [Wave function or Amplitude of Electron Wave]

It is also known as atomic orbitals. It is a mathematical function whose value depends on coordinates of electron in an atom. It may be ve or -ve depending upon value of coordinates and it has no physical significance.

ψ2 [Probability Density] :

According to electromagnetic wave theory, intensity of light is proportional to square of amplitude. In the same way Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation gives an idea of intensity of electron wave i.e. probability of finding electron at that point.

Q. What is the significance of y2 (x).dx ?

Q. What is the significance of y2 .dV ?

==============================================================

Orbitals , Wave Functions and Quantum Numbers - Structure of Atom, Class 11, Chemistry

ORBITALS

Orbitals are defined as that region or zone in the space where probability of finding electrons is possible (more than 90%). In an atom large no. of permissible orbitals are present.

These orbitals are designated by a set of 3 quantum number (n, l, m) which arise as a natural consequence in the solution of Schordinger equation i.e. the values of 3 quantum numbers are restricted by the solution of Schordinger equation.

The Postulates of Quantum Mechanics

1. Associated with any particle moving in a conservative field of force is a wave function which determines everything that can be known about the system.

2. With every physical observable q there is associated an operator Q, which when operating upon the wave function associated with a definite value of that observable will yield that value times the wave function.

3. Any operator Q associated with a physically measurable property q will be Hermitian.

4. The set of eigen functions of operator Q will form a complete set of linearly independent functions.

5. For a system described by a given wave function, the expectation value of any property q can be found by performing the expectation value integral with respect to that wave function.

6. The time evolution of the wave function is given by the time dependent Schrodinger equation.

The Wave function Postulate

It is one of the postulates of quantum mechanics that for a physical system consisting of a particle there

is an associated wave function. This wave function determines everything that can be known about the system. The wave function is assumed here to be a single-valued function of position and time, since that is sufficient to guarantee an unambiguous value of probability of finding the particle at a particular position and time. The wave function may be a complex function, since it is its product with its complex conjugate which specifies the real physical probability of finding the particle in a particular state.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation single-valued probability amplitude at (x, t)

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparationprobability of finding particle at x at time t provided the wave function is normalized.

Q. How can a continuous description such as wave lead to discrete energy levels ?

Constraints on Wave function

In order to represent a physically observable system, the wave function must satisfy certain constraints:

1. Must be a solution of the Schrodinger equation.

2. Must be normalizable. This implies that the wave function approaches zero as x approaches infinity.

3. Must be a continuous function of x.

4. The slope of the function in x must be continuous.

Specifically Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation must be continuous.

These constraints are applied to the boundary conditions on the solutions, and in the process help determine the energy eigenvalues.

Few Radial Functions Rn,l

n = 1, l = 0 R10(r) = 2 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

n = 2, l = 0 R20(r) = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

n = 2, l = 1 R21(r) = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

n = 3, l = 0 R30(r) = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

n = 3, l = 1 R31(r) = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

n = 3, l = 2 R32(r) = Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Hydrogenic orbitals

(a) Radial wave functions

Rn l (r) = f (r) (Z/a0)3/2 e-r/2

Where a0 is the bohr radius (0.53Å) and r = 2Zr/na0.

n l f (r)

1 0 2

2 0 (1/Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation) (2 - r)

2 1 (1/Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation) r

3 0 (1/Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation) (6 - 6r r2)

3 1 (1/Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation) (4 - r)r

3 2 (1/Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation)r2

(b) Angular wave functions

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation(q, f) = (1/4p)1/2 y(q, f)

l ml y(q, f)

0 0 1

1 0 31/2 cos q

1 ± 1 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation(3/2)1/2 sin q e± i f

2 0 (5/4)1/2 (3 cos2 q - 1)

2 ± 1 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation(15/4)1/2 cos q sin q e± i f

2 ± 2 (15/8)1/2 sin2 q e± 2 i f

Q. If a particle of mass m located in one -Dimensional box as shown.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

wave function Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation for Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation then correct value of |K|2 is :

(A) Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(B) Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(C) Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(D) Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Ans. A

Q. The angular wave function for l = 0 & m = 0 is Y(q, f) = . Select the incorrect statement

(A) Wave fuction is independent of q & f

(B) Two demensional plot will be circle in x-z plane

(C) Three demensional plot will be spherical

(D) Y(q, f).Y(q, f) plot in two dimensional will be elliptical

Ans. D

Quantum Numbers

In the solution to the Schrodinger equation for the hydrogen atom, three quantum numbers arise from the space geometry of the solution and a fourth arises from electron spin. No two electrons can have an identical set of quantum numbers according to the Pauli exclusion principle , so the quantum numbers set limits on the number of electrons which can occupy a given state and therefore give insight into the building up of the periodic table of the elements.

(1) Principal Quantum No. (n) :

The principal quantum number or total quantum number n arises from the solution of the radial part of the Schrodinger equation for the hydrogen atom. The bound state energies of the electron in the hydrogen atom are given by

En Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(i) Permissible values of n : all integers from 1 to ∞ (infinity)

(ii) This no. identifies shell in an atom.

(iii) It gives an idea of average distance `R' [size of any orbital from the nucleus higher the value of, n, higher will be the average distance and hence greater will be the size].

(iv) It gives idea of energy of electron upto some extent. Higher the value of n, higher will be the energy (if `l' is constant).

for example order of energy 4s > 3s > 2s > 1s

(v) It gives value of total no. of orbitals present in any shell and that is equal to n2.

(vi) It gives value of total no. of electrons which may he present in the given shell = 2n2.

(vii) It gives value of angular momentum of electron i.e. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(viii) It give variation of radial probability distribution.

(2) Azimuthal Quantum No. or Angular momentum Quantum no. (l) :

Permissible values of l is 0 to (n -1). i.e. value of l is restricted by n.

n = 1, l = 0

n = 2, l = 0, 1. ; i.e. 2 values of l.

n = 3, l = 0, 1, 2. i.e. 3 values of l.

No. of values of `l' is equal to `n' principal quantum number

It identify sub shell in an atom

The value of `l' gives name of sub-shell and shape of orbital.

l Notation Name Shape

o s Sharp Spherical

1 p Principal dumbell shaped

2 d diffuse double dumbell

3 f fundamental complex

(3) magnetic quantum number (m)

The direct implication of this quantum number is that the z-component of angular momentum is quantized according to Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

It is called the magnetic quantum number because the application of an external magnetic field causes a splitting of spectral lines called the Zeeman effect. The different orientations of orbital angular momentum represented by the magnetic quantum number can be visualized in terms of a vector model.

(4) Spin quantum number (s)

An electron, besides charge and mass, has also spin angular momentum commonly called spin. The spin angular momentum of the electron is constant and cannot be changed.

An electron spin s = 1/2 is an intrinsic property of electrons. Electrons have intrinsic angular momentum characterized by quantum number 1/2. In the pattern of other quantized angular momenta, this gives total angular momentum

The resulting fine structure which is observed corresponds to two possibilities for the z-component of the angular momentum.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

This causes an energy splitting because of the magnetic moment of the electron

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Orbitals diagram

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Filling of Orbitals in atoms :

The filling of electrons into the orbitals of different atoms take place on the basic of 3 principles :

===========================================================

Afbaus Principle, Paulis Principle and Hunds Principle - Structure of Atom, CBSE, Class 11, Chemistry

Aufbau's Principle

The electrons are added progressively to Various orbitals in the order of increasing energy, starting with the orbital of lowest energy, generally.

Energy of Orbitals

(i) Hydrogen atom : In case of hydrogen atom, energy of orbital is mainly determined by principle quantum number.

n­, E ­

For H atom

1s < 2s = 2p < 3s = 3p = 3d < 4s = 4p

(ii) Multielectronic atoms : In case of multielectronic atoms, energy of orbitals depends upon both n and l and hence energy of orbitals is compared on the basis of (n l) rules generally

⇒ n l rule

(iii) As the value (n l) increases the total energy of orbitals also increases.

(iv) If value of (n l) is same or different orbital then orbital with lower value of n, have lower energy.

 

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s

Pauli's Exclusions Principle

The principle states that no two electrons in an atom can have same set of all 4 quantum no.

Therefore spin quantum No. have only two values therefore it can also be commented that orbital can have maximum two electrons with opposite spin.

Hund's Rule of Maximum Multiplicity

While filing the orbitals of same energy (i.e. orbitals of same subshell) pairing of electron start only when each orbital have got 1 electron that too with same spin or parallel spin.

Multiplicity is expressed as 2|s| 1 where s represent total spin.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation 2|s| 1 = 2

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation, 2|s| 1 = 2

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation, 2Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation 1 = 4 (It has maximum multiplicity)

Q. Total spin resulting from d7 configuration ?

=================================================

Electronic Configuration - Structure of Atom, Class 11, Chemistry

Electronic configuration of atom

The distribution of electrons of an atom in its various shell, sub shells and orbitals is known as electron configuration.

Valence shell or outer most shell → nth shell

Penultimate shell-Inner to outermost shell → (n -1) shell

Anti Penultimate shell → (n - 2) shell

Electronic configuration can be expressed in the following ways :

(i) Orbital notation method : nlx

Li → 3 → 1s2 2s1

(ii) Orbital diagram method :

Li → 3 → Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(iii) Condensed form :

[He] 2s1

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE PreparationImportant Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Electronic Configuration of ions :

Al [Ne]3s2 3p1,

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation,

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Similarly in case of transition elements electrons are removed from nth shell for e.g. 4th shell in case of 3d series.

,

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Cl : [Ne]3s2.3p5

Cl- : [Ne]3s2.3p6

Exceptional configuration

Expected confi.

Observed confi. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Expected confi. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Observed confi. Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Above exceptional configuration can be explained on the basis of following factor.

(i) Symmetrical Electronic Configuration :

It is well known fact that symmetry leads to stability, orbitals of a sub shell having half-filled or full-filled configuration (i.e. symmetrical distribution of electrons) are relatively more stable. This effect is dominating in d and f subshell.

d5, d10, f7, f14 configurations are relatively more stable.

(ii) Exchange Energy :

It is assumed that electrons in de-generate orbitals, do not remain confined to a particular orbital rather it keep on exchanging its position with electron having same spin and same energy (electrons present in orbitals having same energy). Energy is released in this process known as exchange energy which imparts stability to the atom. More the number of exchanges, more will be the energy released, more the energy released stability will be more.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation → 3 2 1 = 6 Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation when n represents no. of

electron having same spin.

The relative value of exchange energy and Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

decides the final configuration. For example, if magnitude of

Dep. energy Ex. energy > transfer. energy as in cases of Cu and Cr then configuration is

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation respectively

In case of carbon magnitude of transfer energy > dep. energy exch. energy and

configuration of carbon is

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Magnetic moment (m) : It is the measure of the magnetic nature of substance

where n is no. of unpaired electrons.

When m = 0, then there is no unpaired electron in the species and it is known as diamagnetic specie.

These species are repelled by magnetic field.

When Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation, for paramagnetic species. These species have unpaired electrons and are weakly attracted by the magnetic field.

Calculate magnetic moment of these species

(i) Cr (ii) N (iii) Cl (iv) Ar

(i) Cr : No. of unpaired electrons = 6.

= Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation BM

Generally species having unpaired electrons are coloured or impart colour to the flame. Species having unpaired electrons can be easily excited by the wavelengths corresponding to visible lights and hence they emit radiations having characteristic colour.

(A) Radial wave function (R)

In all cases R approaches zero as r approaches infinity. One finds that there is a node in the 2s radial function. In general, it has been found that ns-orbitals have (n-1) nodes, np-orbitals have (n-2) nodes etc.

The importance of these plots lies in the fact that they give information about how the radial wave function changes with distance r and about the presence of nodes where the change of sign of R occurs.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(B) Radial Probability density (R2)

The square of the radial wave function R2 for an orbital gives the radial density. The radial density gives the probability density of finding the electron at a point along a particular radius line. To get such a variation, the simplest procedure is to plot R2 against r. These plots give useful information about probability density or relative electron density at a point as a function of radius. It may be noted that while for s-orbitals the maximum electron density is at the nucleus. all other orbitals have zero electron density at the nucleus.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation 

(C) Radial probability functions 4pr2R2

The radial density R2 for an orbital, as discussed above, gives the probability density of finding the electron at a point at a distance r from the nucleus. Since the atoms have spherical symmetry, it is more useful to discuss the probability of finding the electron in a spherical shell between the spheres of radius (r dr) and r. The volume of the shell is equal to 4/3p(r dr)3-4/3pr3 = 4pr2dr.

This probability which is independent of direction is called radial probability and is equal to 4pr2drR2.

Radial probability function (4pr2drR2) gives the probability of finding the electron at a distance r from the nucleus regardless of direction.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

The radial probability distribution curves obtained by plotting radial probability functions versus distance r from the nucleus for 1s, 2s and 2p orbitals are shown in fig.

Hydrogen 1s Radial Probability

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Hydrogen 3s Radial Probability

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

 

Hydrogen 2p Radial Probability

 

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Hydrogen 3p Radial Probability

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Hydrogen 3d Radial Probability

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

 

Angular wave Function QF.

The angular wave function ' Q F ' depends only on the quantum number l and ml and is independent of the principal quantum number n for a given type of orbital. It therefore means that all s orbitals will have same angular wave function.

(A) Angular Wave Function, ' Q F '

For an s-orbital, the angular part is independent or angle and is, therefore, of constant value. Hence this graph is circular or, more properly, in three dimensions i.e., spherical. For the pz orbital, we get two tangent spheres. The px and py orbitals are identical in shape but are oriented along the x and y axes respectively. The angular, wave function plots for d and f-orbitals are four lobed and six-lobed respectively.

It is necessary to keep in mind that in the angular wave function plots, the distance from the center is proportional to the numerical values of ' Q F ' in that direction and is not the distance from the center of the nucleus.

(B) Angular Wave Function, | Q F |2

The angular probability density plots can be obtained by squaring the angular function plots shown in fig. On squaring, different orbitals change in different ways. For an s orbital, the squaring causes no change in shape since the function everywhere is the same: thus another sphere is obtained.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Plots of Total probability density: Shapes of Atomic Orbitals.

The problems associated with the representations of the variations of |Y|2 in space have been circumvented by the following two approaches.

(a) Charge cloud diagrams (b) Boundary surface diagrams

(A) Charge cloud diagrams

In this approach, the probability density |Y|2 is shown as a collection of dots such that the density of dots in any region represents the electron probability density in that region. Fig. shows such plots for some orbitals. These give some ideal about the shapes of the orbitals.

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

(B) Boundary surface digrams

In these diagrams, the shape of an orbital is defined as a surface of constant probability density that encloses some large fraction (say 90 %) of the probability of finding the electron. The probability density is |Y|2 . When |Y|2 is constant, so is |Y|. Hence |Y| is constant on the surface for an s orbital (l = 0) has the shape of a spherical shell centered on the nucleus, fig. For each value of n, there is one s orbital. As n increases, there are (n-1) concentric spherical shells like the successive layers in an onion.

 Fig. Boundary surface digrams for the 1 s orbital.

Shapes of Atomic Orbitals

 

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

The spherical Polar Coordinates S

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

pX py pz

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation dxy

 

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

dxz dyz Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

fxyz Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation Important Notes, Class 11, Structure of Atom, CBSE, NCERT, IIT JEE Preparation

 

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FAQs on Structure of Atom, Class 11, Chemistry Detailed Chapter Notes

1. What is the structure of an atom?
Ans. An atom consists of a nucleus containing positively charged protons and neutral neutrons, surrounded by negatively charged electrons in shells or energy levels.
2. What is the Bohr model of an atom?
Ans. The Bohr model of an atom is a simplified representation of an atom where electrons are arranged in concentric circular orbits around the nucleus, with each orbit corresponding to a specific energy level.
3. What is an atomic number?
Ans. The atomic number of an element is the number of protons present in the nucleus of an atom of that element. It determines the element's identity and properties.
4. What is an isotopes of an element?
Ans. Isotopes of an element are atoms that have the same number of protons but different numbers of neutrons in their nucleus. They have the same atomic number but different mass numbers.
5. How are the properties of an element related to its atomic structure?
Ans. The properties of an element are determined by its atomic structure, including the number of protons, neutrons, and electrons present in its atoms. The arrangement of electrons in energy levels also affects the chemical behavior of an element.
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