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Long Answer Type Questions: Circles

Question 1. Look at the adjoining figure. If O is the center of the circle. PQ=12cm and ST = 3 cm, then find the radius of the circle when RS ⊥ PQ.Long Answer Type Questions: Circles Solution: Let us join O and P such that OP = r.
∵ RS ⊥ PQ

Long Answer Type Questions: Circles∴ T is the mid-point of PQ
.⇒ PT = (1/2) PQ⇒ PT = (1/2) x 12 cm = 6 cm             [∵ PQ = 12 cm      (Given)]
And ∠ OTP = 90°
Also OS = r and TS = 3 cm
∴ OT = OS - TS = (r - 3) cm
Now, in right ΔOTP, we have OP2 = PT2 + OT2
⇒ r= 62 + (r - 3)2
⇒ r2 = 36 + r+ 9 - 6r
⇒ 6r = 45

⇒ r =(45/6) = (15/2) = 7.5 cm
Thus, the radius of the circle is 7.5 cm.


Question 2. An equilateral triangle ABCABC is inscribed in a circle. Each side of the triangle is 9cm9cm. Find the radius of the circle.
 Solution:
Let ABC be an equilateral triangle such that AB = BC = AC = 9 cm                  (each)
Let us draw a median AD corresponding to BC.
∴ BD =(1/2) BC
⇒ BD = (1/2) x 9 cm = (9/2)cm
Also, AD ⊥ BC                  [∵ O is the centre of the circle]
Now, in right ΔADB,

Long Answer Type Questions: Circles

AD2 = AB2 - BD2

Long Answer Type Questions: Circles

Since, in an equilateral triangle, the centroid and circumcentre coincide.

∴ AO: OD = 2:1

⇒   Long Answer Type Questions: Circles

⇒ Radius = 3√3 cm

Thus, the required radius =  3√3 cm

The document Long Answer Type Questions: Circles is a part of the Class 9 Course Mathematics (Maths) Class 9.
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FAQs on Long Answer Type Questions: Circles

1. How do I find the angle subtended by an arc at the centre versus at the circumference?
Ans. The angle subtended by an arc at the centre is always twice the angle subtended at any point on the circumference. This relationship, called the inscribed angle theorem, is fundamental to solving circle problems. If the central angle is 80°, the circumference angle will be 40°. This property helps in calculating unknown angles in cyclic configurations.
2. What's the difference between a chord and a tangent, and how do they relate to circles?
Ans. A chord is a line segment joining two points on a circle's circumference, while a tangent touches the circle at exactly one point and is perpendicular to the radius at that point. Chords can pass through the circle's interior; tangents never do. Understanding this distinction is crucial for solving long answer questions involving secant-tangent relationships and circle theorems.
3. How do I solve problems about angles in the same segment of a circle?
Ans. Angles subtended by the same chord in the same segment of a circle are always equal. This means if two angles are drawn from different points on the same arc to the same chord, both angles have identical measures. This property, known as angles in the same segment theorem, simplifies calculations in cyclic quadrilaterals and helps identify equal angles without measurement.
4. Why do opposite angles in a cyclic quadrilateral always add up to 180°?
Ans. In a cyclic quadrilateral-where all four vertices lie on a circle-opposite angles are supplementary because they subtend complementary arcs. The angle subtended at the centre equals twice the inscribed angle, creating this relationship. Opposite angles sum to 180°, making this property essential for proving angle measures and validating whether quadrilaterals can be inscribed in circles.
5. How can I use the alternate segment theorem to find unknown angles in circle problems?
Ans. The alternate segment theorem states that the angle between a tangent and a chord equals the inscribed angle in the alternate segment subtended by that chord. This powerful tool links tangent properties with circumference angles, enabling solutions without calculating central angles. It's particularly useful in CBSE Class 9 long answer questions where tangent-chord configurations require angle determination and geometric reasoning.
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