CBSE Class 7 > Class 7 Notes > Mathematics (Maths) (Old NCERT) > Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3
Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
Page 2
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
Page 3
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
CBSE VII | Mathematics
Sample Paper 3 - Solution
Section B
13. Given that, m||p and t is the transversal
We know that, if two parallel lines are cut by a transversal, each pair of alternate
interior angles are equal.
So, ? a = ? z (pair of alternate interior angles)
Thus, ? z = 57
o
.
14. The numbers in ascending order are:
11, 12, 12, 12, 19, 23, 33, 34, 34, 45, 46, 49, 50, 55, 56, 65, 67, 78, 81, 87, 98
As the number of observations (21) are odd,
Median = middle observation = 11
th
observation = 46
Mode is the observation that appears most often.
Here, 12 appears maximum number of times (thrice). So, 12 is the mode.
15. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
16. Sum of 38 and -87 = 38 + (-87) = 38 - 87 = -49
Subtracting (-134) from -49, we get
-49 - (-134) = -49 + 134 = 85
17. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
18. Pie filling made in 1 minute = 9.2 kg
Pie filling made in 6 minutes = 6 × 9.2 kg = 55.2 kg
Page 4
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
CBSE VII | Mathematics
Sample Paper 3 - Solution
Section B
13. Given that, m||p and t is the transversal
We know that, if two parallel lines are cut by a transversal, each pair of alternate
interior angles are equal.
So, ? a = ? z (pair of alternate interior angles)
Thus, ? z = 57
o
.
14. The numbers in ascending order are:
11, 12, 12, 12, 19, 23, 33, 34, 34, 45, 46, 49, 50, 55, 56, 65, 67, 78, 81, 87, 98
As the number of observations (21) are odd,
Median = middle observation = 11
th
observation = 46
Mode is the observation that appears most often.
Here, 12 appears maximum number of times (thrice). So, 12 is the mode.
15. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
16. Sum of 38 and -87 = 38 + (-87) = 38 - 87 = -49
Subtracting (-134) from -49, we get
-49 - (-134) = -49 + 134 = 85
17. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
18. Pie filling made in 1 minute = 9.2 kg
Pie filling made in 6 minutes = 6 × 9.2 kg = 55.2 kg
CBSE VII | Mathematics
Sample Paper 3 - Solution
19. Distance travelled with 1 gallon =
2 32
10 =
33
miles
Distance travelled with
1 11
5=
22
gallons.
11 32
= × miles
23
16
=11× miles
3
176
= miles
3
mile
Thus, Sam can go
176
3
miles with
11
2
gallons.
20. ASA congruence criterion:
The Angle Side Angle (ASA) postulate states that if under correspondence, two
angles and the included side of a triangle is equal to two corresponding angles and
included side of another triangle, then the two triangles are congruent.
Consider the triangles ABC and XYZ as shown below.
Two angles and the included side are congruent.
? ABC = ? XYZ (equal angle)
BC = YZ (equal side)
? ACB = ? XZY (equal angle)
So, ABC XYZ
Therefore, by the ASA congruence criterion, the triangles are congruent.
Page 5
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
CBSE VII | Mathematics
Sample Paper 3 - Solution
Section B
13. Given that, m||p and t is the transversal
We know that, if two parallel lines are cut by a transversal, each pair of alternate
interior angles are equal.
So, ? a = ? z (pair of alternate interior angles)
Thus, ? z = 57
o
.
14. The numbers in ascending order are:
11, 12, 12, 12, 19, 23, 33, 34, 34, 45, 46, 49, 50, 55, 56, 65, 67, 78, 81, 87, 98
As the number of observations (21) are odd,
Median = middle observation = 11
th
observation = 46
Mode is the observation that appears most often.
Here, 12 appears maximum number of times (thrice). So, 12 is the mode.
15. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
16. Sum of 38 and -87 = 38 + (-87) = 38 - 87 = -49
Subtracting (-134) from -49, we get
-49 - (-134) = -49 + 134 = 85
17. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
18. Pie filling made in 1 minute = 9.2 kg
Pie filling made in 6 minutes = 6 × 9.2 kg = 55.2 kg
CBSE VII | Mathematics
Sample Paper 3 - Solution
19. Distance travelled with 1 gallon =
2 32
10 =
33
miles
Distance travelled with
1 11
5=
22
gallons.
11 32
= × miles
23
16
=11× miles
3
176
= miles
3
mile
Thus, Sam can go
176
3
miles with
11
2
gallons.
20. ASA congruence criterion:
The Angle Side Angle (ASA) postulate states that if under correspondence, two
angles and the included side of a triangle is equal to two corresponding angles and
included side of another triangle, then the two triangles are congruent.
Consider the triangles ABC and XYZ as shown below.
Two angles and the included side are congruent.
? ABC = ? XYZ (equal angle)
BC = YZ (equal side)
? ACB = ? XZY (equal angle)
So, ABC XYZ
Therefore, by the ASA congruence criterion, the triangles are congruent.
CBSE VII | Mathematics
Sample Paper 3 - Solution
21. Let A and B be the two numbers such that,
40% of A =
2
B
3
Then,
?
??
??
? ? ? ?
??
??
??
40 2
100 3
22
53
2 5 10
3 2 3
: 5:3
AB
AB
A
B
AB
22. Here, AB = PR (= 3.5 cm),
BC = PQ (= 7.1 cm)
And AC = QR (= 5 cm)
This shows that the three sides of one triangle are equal to the three sides
Of the other triangle. So, by SSS congruence rule, the two triangles are
congruent. From the above three equality relations, it can be easily seen
that A ? R, B ? P and C ? Q.
So, we have ?ABC ? ?RPQ
Read MoreFAQs on Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3
| 1. What topics are covered in CBSE Class 7 Maths Term I sample papers? |  |
Ans. CBSE Class 7 Maths Term I sample question papers typically cover integers, fractions, decimals, data handling, simple equations, and basic geometry concepts. These foundational topics test computational skills and problem-solving abilities. Sample papers help students understand the exam pattern, marking scheme, and question distribution. Practising these papers improves confidence before assessments.
| 2. How do I solve word problems on integers and rational numbers for Class 7 exams? | |
Ans. Solving word problems on integers and rational numbers requires identifying the operation needed, converting statements into equations, and performing calculations carefully. Read the problem twice, underline key information, and check if answers make sense contextually. Common mistakes include ignoring negative signs and calculation errors. Refer to detailed notes and MCQ tests on EduRev to practise varied problem types systematically.
| 3. Why do my answers not match the CBSE sample paper solutions even though my method seems right? | |
Ans. Mismatched answers often occur due to calculation errors, incorrect order of operations, or misinterpretation of questions rather than faulty methods. Review each step carefully, especially with fractions and decimals where small errors multiply. Compare your working with provided solutions line-by-line. Using flashcards and mind maps helps identify conceptual gaps quickly before retrying problems.
| 4. What are the most important formulas and concepts I need to memorise for Class 7 Maths Term I? | |
Ans. Key formulas include area of rectangles and triangles, perimeter calculations, simple interest basics, and properties of angles and lines. Understanding concepts matters more than pure memorisation-know why formulas work. Focus on linear equations, data interpretation techniques, and fraction operations. Visual worksheets and PPTs break down abstract concepts into manageable chunks for better retention.
| 5. How much time should I spend practising CBSE sample papers to improve my Class 7 Maths marks? | |
Ans. Consistent practice beats quantity; solving 2-3 complete sample papers weekly with detailed solution review yields significant improvement. Time yourself to build speed and accuracy under exam conditions. After completing papers, analyse errors and revisit related concepts immediately. Gradual practice prevents burnout while building examination confidence and conceptual clarity simultaneously.
About this Document
4.87/5 Rating
Apr 26, 2026 Last updated
Document Description: Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 for Class 7 2026 is part of Mathematics (Maths) Class 7 (Old NCERT) preparation. The notes and questions for Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 have been prepared according to the Class 7 exam syllabus. Information about Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 covers topics like and Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 Example, for Class 7 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3.
Introduction of Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 in English is available as part of our Mathematics (Maths) Class 7 (Old NCERT) for Class 7 & Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 in Hindi for Mathematics (Maths) Class 7 (Old NCERT) course. Download more important topics related with notes, lectures and mock test series for Class 7 Exam by signing up for free. Class 7: Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3
Description
Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 of Maths Class 7 - variety of important questions with solutions, helping you prepare for exam. Download free PDF from EduRev.
Information about Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3
In this doc you can find the meaning of Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 defined & explained in the simplest way possible. Besides explaining types of Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 theory, EduRev gives you an ample number of questions to practice Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 tests, examples and also practice Class 7 tests
Related Searches
Free, MCQs, Extra Questions, Summary, mock tests for examination, pdf , Viva Questions, Objective type Questions, study material, Exam, Semester Notes, Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3, Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3, Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3, Important questions, Sample Paper, practice quizzes, ppt, past year papers, shortcuts and tricks, video lectures, Previous Year Questions with Solutions;