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Page 1
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
Page 2
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
Page 3
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
CBSE VII | Mathematics
Sample Paper 3 - Solution
Section B
13. Given that, m||p and t is the transversal
We know that, if two parallel lines are cut by a transversal, each pair of alternate
interior angles are equal.
So, ? a = ? z (pair of alternate interior angles)
Thus, ? z = 57
o
.
14. The numbers in ascending order are:
11, 12, 12, 12, 19, 23, 33, 34, 34, 45, 46, 49, 50, 55, 56, 65, 67, 78, 81, 87, 98
As the number of observations (21) are odd,
Median = middle observation = 11
th
observation = 46
Mode is the observation that appears most often.
Here, 12 appears maximum number of times (thrice). So, 12 is the mode.
15. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
16. Sum of 38 and -87 = 38 + (-87) = 38 - 87 = -49
Subtracting (-134) from -49, we get
-49 - (-134) = -49 + 134 = 85
17. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
18. Pie filling made in 1 minute = 9.2 kg
Pie filling made in 6 minutes = 6 × 9.2 kg = 55.2 kg
Page 4
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
CBSE VII | Mathematics
Sample Paper 3 - Solution
Section B
13. Given that, m||p and t is the transversal
We know that, if two parallel lines are cut by a transversal, each pair of alternate
interior angles are equal.
So, ? a = ? z (pair of alternate interior angles)
Thus, ? z = 57
o
.
14. The numbers in ascending order are:
11, 12, 12, 12, 19, 23, 33, 34, 34, 45, 46, 49, 50, 55, 56, 65, 67, 78, 81, 87, 98
As the number of observations (21) are odd,
Median = middle observation = 11
th
observation = 46
Mode is the observation that appears most often.
Here, 12 appears maximum number of times (thrice). So, 12 is the mode.
15. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
16. Sum of 38 and -87 = 38 + (-87) = 38 - 87 = -49
Subtracting (-134) from -49, we get
-49 - (-134) = -49 + 134 = 85
17. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
18. Pie filling made in 1 minute = 9.2 kg
Pie filling made in 6 minutes = 6 × 9.2 kg = 55.2 kg
CBSE VII | Mathematics
Sample Paper 3 - Solution
19. Distance travelled with 1 gallon =
2 32
10 =
33
miles
Distance travelled with
1 11
5=
22
gallons.
11 32
= × miles
23
16
=11× miles
3
176
= miles
3
mile
Thus, Sam can go
176
3
miles with
11
2
gallons.
20. ASA congruence criterion:
The Angle Side Angle (ASA) postulate states that if under correspondence, two
angles and the included side of a triangle is equal to two corresponding angles and
included side of another triangle, then the two triangles are congruent.
Consider the triangles ABC and XYZ as shown below.
Two angles and the included side are congruent.
? ABC = ? XYZ (equal angle)
BC = YZ (equal side)
? ACB = ? XZY (equal angle)
So, ABC XYZ
Therefore, by the ASA congruence criterion, the triangles are congruent.
Page 5
CBSE VII | Mathematics
Sample Paper 3 - Solution
CBSE Board
Class VII Mathematics
Term I
Sample Paper 3 - Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: A
(128 ÷32)÷ (-4)
= 4 ÷ (-4)
= -1
2. Correct answer: A
Total cost = 2.40 × 10
= Rs. 24
3. Correct answer: B
The given observations can be arranged in ascending order as
4, 6, 9, 10, 11, 12 and 18
Here, number of observations = 7 (odd)
Median = Middle observation = 10
4. Correct answer: A
2x + 3 = 7
If we will transpose 3 to RHS, then the term with variable will remain on one side
and the constants will be on other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
5. Correct answer: C
?BCA = 180° - 150° = 30° (linear pair angles)
Also, ?B = ?BCA = 30° (Angles opp. to equal sides are equal)
? ?A = 180° - 30° - 30° = 120° (Using angle sum property of triangle)
6. Correct answer: B
Increased amount =
12
Rs. ×54=Rs. 6.48
100
CBSE VII | Mathematics
Sample Paper 3 - Solution
7. Correct answer: C
?
28
2
33
So the multiplicative inverse is
3
8
.
8. Correct answer: D
The triangle ABC is a right angled triangle,
By Pythagoras theorem, we have: c
2
= a
2
+ b
2
9. Correct answer: B
21b - 32 + 7b - 20b
= 21b + 7b - 20b – 32
= 8b – 32
10. Correct answer: D
11. Correct answer: A
The two triangles can be proved to be congruent by using SAS congruency criterion.
The corresponding equal parts in triangles ABC and ADE are
12. Correct answer: C
Let the whole number be x.
Twice of the whole number = 2x
9 added to twice of the whole number = 9 + 2x
From the given information, we have:
9 + 2x = 31
2x = 31 - 9
2x = 22
x = 11
Thus, the required whole number is 11.
CBSE VII | Mathematics
Sample Paper 3 - Solution
Section B
13. Given that, m||p and t is the transversal
We know that, if two parallel lines are cut by a transversal, each pair of alternate
interior angles are equal.
So, ? a = ? z (pair of alternate interior angles)
Thus, ? z = 57
o
.
14. The numbers in ascending order are:
11, 12, 12, 12, 19, 23, 33, 34, 34, 45, 46, 49, 50, 55, 56, 65, 67, 78, 81, 87, 98
As the number of observations (21) are odd,
Median = middle observation = 11
th
observation = 46
Mode is the observation that appears most often.
Here, 12 appears maximum number of times (thrice). So, 12 is the mode.
15. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
16. Sum of 38 and -87 = 38 + (-87) = 38 - 87 = -49
Subtracting (-134) from -49, we get
-49 - (-134) = -49 + 134 = 85
17. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
18. Pie filling made in 1 minute = 9.2 kg
Pie filling made in 6 minutes = 6 × 9.2 kg = 55.2 kg
CBSE VII | Mathematics
Sample Paper 3 - Solution
19. Distance travelled with 1 gallon =
2 32
10 =
33
miles
Distance travelled with
1 11
5=
22
gallons.
11 32
= × miles
23
16
=11× miles
3
176
= miles
3
mile
Thus, Sam can go
176
3
miles with
11
2
gallons.
20. ASA congruence criterion:
The Angle Side Angle (ASA) postulate states that if under correspondence, two
angles and the included side of a triangle is equal to two corresponding angles and
included side of another triangle, then the two triangles are congruent.
Consider the triangles ABC and XYZ as shown below.
Two angles and the included side are congruent.
? ABC = ? XYZ (equal angle)
BC = YZ (equal side)
? ACB = ? XZY (equal angle)
So, ABC XYZ
Therefore, by the ASA congruence criterion, the triangles are congruent.
CBSE VII | Mathematics
Sample Paper 3 - Solution
21. Let A and B be the two numbers such that,
40% of A =
2
B
3
Then,
?
??
??
? ? ? ?
??
??
??
40 2
100 3
22
53
2 5 10
3 2 3
: 5:3
AB
AB
A
B
AB
22. Here, AB = PR (= 3.5 cm),
BC = PQ (= 7.1 cm)
And AC = QR (= 5 cm)
This shows that the three sides of one triangle are equal to the three sides
Of the other triangle. So, by SSS congruence rule, the two triangles are
congruent. From the above three equality relations, it can be easily seen
that A ? R, B ? P and C ? Q.
So, we have ?ABC ? ?RPQ
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FAQs on Class 7 Math: CBSE Sample Question Paper Solutions Term I – 3 - Mathematics (Maths) Class 7
| 1. What is the CBSE sample question paper for Class 7 Math Term I? |  |
Ans. The CBSE sample question paper for Class 7 Math Term I is a set of practice questions designed by the Central Board of Secondary Education (CBSE) to help students prepare for their exams. It includes questions based on the syllabus and format of the actual exam.
| 2. How can I access the CBSE sample question paper for Class 7 Math Term I? | |
Ans. The CBSE sample question paper for Class 7 Math Term I can be accessed online through the official website of CBSE or other educational platforms that provide study materials for CBSE students. These sample papers are usually available in PDF format and can be downloaded for free.
| 3. Why is it important to solve the CBSE sample question paper for Class 7 Math Term I? | |
Ans. Solving the CBSE sample question paper for Class 7 Math Term I is important for several reasons. It helps students understand the exam pattern, practice time management, and identify their strengths and weaknesses in different topics. It also familiarizes them with the types of questions that can be asked in the actual exam, allowing them to prepare effectively.
| 4. Can the CBSE sample question paper for Class 7 Math Term I be used as a study resource? | |
Ans. Yes, the CBSE sample question paper for Class 7 Math Term I can be used as a study resource. By solving these sample papers, students can enhance their problem-solving skills, improve their understanding of concepts, and gain confidence in their preparation. It is recommended to solve these papers after covering the entire syllabus to assess one's knowledge.
| 5. Are the questions in the CBSE sample question paper for Class 7 Math Term I similar to the actual exam? | |
Ans. The questions in the CBSE sample question paper for Class 7 Math Term I are designed to be similar to the ones that can be asked in the actual exam. However, the actual exam may have variations in terms of difficulty level, marks distribution, and specific topics covered. It is important to refer to the official exam syllabus and previous years' question papers for a comprehensive preparation.
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