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JEE Advanced Previous Year Questions (2021 - 2025): Biomolecules

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 Page 1


 
Q1:  For a double strand DNA, one strand is given below:
The amount of energy required to split the double strand DNA into two single strands is ______ kcal mol ?¹.
[Given: Average energy per H-bond for A-T base pair = 1.0 kcal mol ?¹, G-C base pair = 1.5 kcal mol ?¹, and A-U
base pair = 1.25 kcal mol ?¹. Ignore electrostatic repulsion between the phosphate groups.]       [JEE Advanced
2024 Paper 2]
Ans: 41
A = T ? 2 H-bond
G = C ? 3 H-bond
Number of A = T pair = 7
Number of G = C pair = 6
Number of H-bond involved in A = T = 7 × 2 = 14
Number of H-bond involved in G = C = 6 × 3 = 18
Energy required for A = T = 14 × 1 = 14
Energy required for G = C = 18 × 1.5 = 27
T otal energy required = 14 + 27 = 41
Page 2


 
Q1:  For a double strand DNA, one strand is given below:
The amount of energy required to split the double strand DNA into two single strands is ______ kcal mol ?¹.
[Given: Average energy per H-bond for A-T base pair = 1.0 kcal mol ?¹, G-C base pair = 1.5 kcal mol ?¹, and A-U
base pair = 1.25 kcal mol ?¹. Ignore electrostatic repulsion between the phosphate groups.]       [JEE Advanced
2024 Paper 2]
Ans: 41
A = T ? 2 H-bond
G = C ? 3 H-bond
Number of A = T pair = 7
Number of G = C pair = 6
Number of H-bond involved in A = T = 7 × 2 = 14
Number of H-bond involved in G = C = 6 × 3 = 18
Energy required for A = T = 14 × 1 = 14
Energy required for G = C = 18 × 1.5 = 27
T otal energy required = 14 + 27 = 41
 
 
 JEE Advanced 2023 Paper 2 Online 
Q1. A disaccharide ?? cannot be oxidised by bromine water. The acid hydrolysis of ?? 
leads to a laevorotatory solution. The disaccharide ?? is : 
A. 
 
B. 
 
C. 
 
D. 
 
Ans: (a) 
A and D cannot be oxidised by bromine water as they do not have hemiacetal linkage. 
Page 3


 
Q1:  For a double strand DNA, one strand is given below:
The amount of energy required to split the double strand DNA into two single strands is ______ kcal mol ?¹.
[Given: Average energy per H-bond for A-T base pair = 1.0 kcal mol ?¹, G-C base pair = 1.5 kcal mol ?¹, and A-U
base pair = 1.25 kcal mol ?¹. Ignore electrostatic repulsion between the phosphate groups.]       [JEE Advanced
2024 Paper 2]
Ans: 41
A = T ? 2 H-bond
G = C ? 3 H-bond
Number of A = T pair = 7
Number of G = C pair = 6
Number of H-bond involved in A = T = 7 × 2 = 14
Number of H-bond involved in G = C = 6 × 3 = 18
Energy required for A = T = 14 × 1 = 14
Energy required for G = C = 18 × 1.5 = 27
T otal energy required = 14 + 27 = 41
 
 
 JEE Advanced 2023 Paper 2 Online 
Q1. A disaccharide ?? cannot be oxidised by bromine water. The acid hydrolysis of ?? 
leads to a laevorotatory solution. The disaccharide ?? is : 
A. 
 
B. 
 
C. 
 
D. 
 
Ans: (a) 
A and D cannot be oxidised by bromine water as they do not have hemiacetal linkage. 
The acid hydrolysis of A leads to a laevorotatory solution. 
A is sucrose which is dextrorotatory, on acid hydrolysis gives mixture of alpha-D-glucose and 
beta-D-fructose, the mixture is laevorotatory 
 
2022 
 
JEE Advanced 2022 Paper 2 Online 
Q1: Treatment of D-glucose with aqueous ?? ?? ?? ?? results in a mixture of 
monosaccharides, which are 
A. 
 
B. 
 
C. 
 
D. 
 
Page 4


 
Q1:  For a double strand DNA, one strand is given below:
The amount of energy required to split the double strand DNA into two single strands is ______ kcal mol ?¹.
[Given: Average energy per H-bond for A-T base pair = 1.0 kcal mol ?¹, G-C base pair = 1.5 kcal mol ?¹, and A-U
base pair = 1.25 kcal mol ?¹. Ignore electrostatic repulsion between the phosphate groups.]       [JEE Advanced
2024 Paper 2]
Ans: 41
A = T ? 2 H-bond
G = C ? 3 H-bond
Number of A = T pair = 7
Number of G = C pair = 6
Number of H-bond involved in A = T = 7 × 2 = 14
Number of H-bond involved in G = C = 6 × 3 = 18
Energy required for A = T = 14 × 1 = 14
Energy required for G = C = 18 × 1.5 = 27
T otal energy required = 14 + 27 = 41
 
 
 JEE Advanced 2023 Paper 2 Online 
Q1. A disaccharide ?? cannot be oxidised by bromine water. The acid hydrolysis of ?? 
leads to a laevorotatory solution. The disaccharide ?? is : 
A. 
 
B. 
 
C. 
 
D. 
 
Ans: (a) 
A and D cannot be oxidised by bromine water as they do not have hemiacetal linkage. 
The acid hydrolysis of A leads to a laevorotatory solution. 
A is sucrose which is dextrorotatory, on acid hydrolysis gives mixture of alpha-D-glucose and 
beta-D-fructose, the mixture is laevorotatory 
 
2022 
 
JEE Advanced 2022 Paper 2 Online 
Q1: Treatment of D-glucose with aqueous ?? ?? ?? ?? results in a mixture of 
monosaccharides, which are 
A. 
 
B. 
 
C. 
 
D. 
 
Ans: (C) 
 
 
 
 
 
 
 
Page 5


 
Q1:  For a double strand DNA, one strand is given below:
The amount of energy required to split the double strand DNA into two single strands is ______ kcal mol ?¹.
[Given: Average energy per H-bond for A-T base pair = 1.0 kcal mol ?¹, G-C base pair = 1.5 kcal mol ?¹, and A-U
base pair = 1.25 kcal mol ?¹. Ignore electrostatic repulsion between the phosphate groups.]       [JEE Advanced
2024 Paper 2]
Ans: 41
A = T ? 2 H-bond
G = C ? 3 H-bond
Number of A = T pair = 7
Number of G = C pair = 6
Number of H-bond involved in A = T = 7 × 2 = 14
Number of H-bond involved in G = C = 6 × 3 = 18
Energy required for A = T = 14 × 1 = 14
Energy required for G = C = 18 × 1.5 = 27
T otal energy required = 14 + 27 = 41
 
 
 JEE Advanced 2023 Paper 2 Online 
Q1. A disaccharide ?? cannot be oxidised by bromine water. The acid hydrolysis of ?? 
leads to a laevorotatory solution. The disaccharide ?? is : 
A. 
 
B. 
 
C. 
 
D. 
 
Ans: (a) 
A and D cannot be oxidised by bromine water as they do not have hemiacetal linkage. 
The acid hydrolysis of A leads to a laevorotatory solution. 
A is sucrose which is dextrorotatory, on acid hydrolysis gives mixture of alpha-D-glucose and 
beta-D-fructose, the mixture is laevorotatory 
 
2022 
 
JEE Advanced 2022 Paper 2 Online 
Q1: Treatment of D-glucose with aqueous ?? ?? ?? ?? results in a mixture of 
monosaccharides, which are 
A. 
 
B. 
 
C. 
 
D. 
 
Ans: (C) 
 
 
 
 
 
 
 
2021 
JEE Advanced 2021 Paper 1 Online 
MCQ (More than One Correct Answer) 
Q1: Given : 
 
The compound(s), which on reaction with ?? ?? ?? ?? will give the product having degree of 
rotation, [ ?? ]
?? = - ???? . ?? °
 is (are) 
A. 
 
B. 
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FAQs on JEE Advanced Previous Year Questions (2021 - 2025): Biomolecules

1. What are the four main classes of biomolecules?
Ans. The four main classes of biomolecules are carbohydrates, lipids, proteins, and nucleic acids.
2. What is the primary function of carbohydrates in living organisms?
Ans. Carbohydrates serve as a primary source of energy and provide structural support in cells.
3. How are lipids different from other biomolecules?
Ans. Lipids are hydrophobic molecules that are insoluble in water, unlike carbohydrates, proteins, and nucleic acids.
4. What is the building block of proteins?
Ans. The building blocks of proteins are amino acids.
5. How do nucleic acids contribute to genetic information?
Ans. Nucleic acids, such as DNA and RNA, store and transmit genetic information in living organisms.
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