Class 6 Exam  >  Class 6 Notes  >  Mathematics (Maths) Class 6  >  NCERT Solutions: Fractions

NCERT Solutions for Class 6 Maths - Fractions

Exercise 7.1

Q1. Write the fraction representing the shaded portion.
NCERT Solutions for Class 6 Maths - Fractions

Ans: 
(i) Number of parts = 4
Shaded portion = 2
∴ Fraction = 2 / 4
(ii) Number of parts = 9
Shaded portion = 8
∴ Fraction = 8 / 9
(iii) Number of parts = 8
Shaded portion = 4
∴ Fraction = 4 / 8
(iv) Number of parts = 4
Shaded portion = 1
∴ Fraction = 1 / 4
(v) Number of parts = 7
Shaded portion = 3
∴ Fraction = 3 / 7
(vi) Number of parts = 12
Shaded portion = 3
∴ Fraction = 3 / 12
(vii) Number of parts = 10
Shaded portion = 10
∴ Fraction = 10 / 10
(viii) Number of parts = 9
Shaded portion = 4
∴ Fraction = 4 / 9
(ix) Number of parts = 8
Shaded portion = 4
∴ Fraction = 4 / 8
(x) Number of parts = 2
Shaded portion = 1
∴ Fraction = 1 / 2


Q2. Colour the part according to the given fraction.

NCERT Solutions for Class 6 Maths - FractionsAns:
NCERT Solutions for Class 6 Maths - Fractions


Q3. Identify the error, if any.
NCERT Solutions for Class 6 Maths - FractionsAns: (i) The shaded portion is not half
Hence, this is not 1 / 2
(ii) Since the parts are not equal
∴ Shaded portion is not 1 / 4
(iii) Since the parts are not equal
∴ Shaded portion is not 3 / 4


Q4. What fraction of a day is 8 hours?
Ans: There are 24 hours in a day
We have 8 hours
Hence, required fraction is 8 / 24


Q5. What fraction of an hour is 40 minutes?
Ans: There are 60 minutes in 1 hour
∴ 1 hour = 60 minutes
Hence, required Fraction = 40 / 60


Q6. Arya, Abhimanyu, and Vivek shared lunch. Arya has brought two sandwiches, one made of vegetables and one of jam. The other two boys forgot to bring their lunch. Arya agreed to share his sandwiches so that each person will have an equal share of each sandwich.
(a) How can Arya divide his sandwiches so that each person has an equal share?
(b) What part of a sandwich will each boy receive?
Ans: (a) To ensure that each person has an equal share of both sandwiches, Arya can divide each of his sandwiches into three equal parts. Therefore, each boy will receive 1/3 of each sandwich.
(b) In summary, each boy will receive:

  • 1/3 of the vegetable sandwich
  • 1/3 of the jam sandwich


Q7. Kanchan dyes dresses. She had to dye 30 dresses. She has so far finished 20 dresses. What fraction of dresses has she finished?
Ans: Total number of dresses Kanchan has to dye = 30 dresses
Number of dresses she has finished = 20 dresses
∴ Required Fraction = 20 / 30 = 2 / 3


Q8. Write the natural numbers from 2 to 12. What fraction of them are prime numbers?
Ans: Natural numbers from 2 to 12 are
2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
Total number of natural numbers given= 11
Number of prime numbers = 5
∴ Required Fraction = 5 / 11


Q9. Write the natural numbers from 102 to 113. What fraction of them are prime numbers?

Ans: Natural numbers from 102 to 113 are
102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113
Total number of natural numbers given = 12
Number of prime numbers = 4 [103, 107, 109, 113]
∴ Required Fraction = 4 / 12 = 1 / 3


Q10. What fractions of these circles have X’s in them?
NCERT Solutions for Class 6 Maths - FractionsAns: Total number of circles in the figure = 8
Number of circles having Xs in them = 4
∴ Required Fraction = 4 / 8 = 1 / 2


Q11. Kristin received a CD player for her birthday. She bought 3 CDs and received 5 others as gifts. What fraction of her total CDs did she buy and what fraction did she receive as gifts?
Ans: Number of CDs Kristin bought from the market = 3
Number of CDs received as gifts = 5
Total number of CDs Kristin have = 3 + 5 = 8
∴ Fraction of CD she bought = 3 / 8
∴ Fraction of CDs received as gifts = 5 / 8


Exercise 7.2

Q1. Draw number lines and locate the points on them:

NCERT Solutions for Class 6 Maths - Fractions
Ans:
(a) 1 / 2, 1 / 4, 3 / 4, 4 / 4
NCERT Solutions for Class 6 Maths - FractionsHere divide the number line from 0 to 1 into four equal parts
C = 2 / 4 = 1 / 2
B = 1 / 4
D = 3 / 4 and
E = 4 / 4 = 1
(b) 1 / 8, 2 / 8, 3 / 8, 7 / 8
NCERT Solutions for Class 6 Maths - Fractions

Divide the number line from 0 to 1 into eight equal parts
B = 1/8
C =2/8
D = 3/8
H = 7/8
(c) 2 / 5, 3 / 5, 8 / 5, 4 / 5
NCERT Solutions for Class 6 Maths - Fractions

From the given number line, we have
C = 2/5
D = 3/5
E = 4/5
I = 8/5


Q2. Express the following as mixed fractions:
(a) 20/3
(b) 11/5
(c) 17/7
(d) 28/5
(e) 19/6
(f) 35/9
Ans: 
(a) 
NCERT Solutions for Class 6 Maths - Fractions

(b)
NCERT Solutions for Class 6 Maths - Fractions

(c) 
NCERT Solutions for Class 6 Maths - Fractions

(d) 
NCERT Solutions for Class 6 Maths - Fractions

(e) 
NCERT Solutions for Class 6 Maths - Fractions

(f) 
NCERT Solutions for Class 6 Maths - Fractions


Q3. Express the following as improper fractions:

NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
Ans:

  NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions


Exercise 7.3

Q1. Write the fractions. Are all these fractions equivalent?
NCERT Solutions for Class 6 Maths - Fractions

Ans:
(a)
(i) The shaded portion is 1 / 2
(ii) The shaded portion is 2 / 4 = (2 / 2) / (4 / 2) = 1 / 2
(iii) The shaded portion is 3 / 6 = (3 / 3) / (6 / 3) = 1 / 2
(iv) The shaded portion is 4 / 8 = (4 / 4) / (8 / 4) = 1 / 2
Hence, all fractions are equivalent.
(b)
(i) The shaded portion is 4 / 12 = (4 / 4) / (12 / 4) = 1 / 3
(ii) The shaded portion is 3 / 9 = (3 / 3) / (9 / 3) = 1 / 3
(iii) The shaded portion is 2 / 6 = (2 / 2) / (6 / 2) = 1 / 3
(iv) The shaded portion is 1 / 3
(v) The shaded portion is 6 / 15 = (6 / 3) / (15 / 3) = 2 / 5
All the fractions in their simplest form are not equal
Hence, they are not equivalent fractions.


Q2. Write the fractions and pair up the equivalent fractions from each row.
NCERT Solutions for Class 6 Maths - Fractions

Ans: 
(a) 1 / 2
(b) 4 / 6 = (4 / 2) / (6 / 2)
= 2 / 3
(c) 3 / 9 = (3 / 3) / (9 / 3)
= 1 / 3
(d) 2 / 8 = (2 / 2) / (8 / 2)
= 1 / 4
(e) 3 / 4
(i) 6 / 18 = (6 / 6) / (18 / 6)
= 1 / 3
(ii) 4 / 8 = (4 / 4) / (8 / 4)
= 1 / 2
(iii) 12 / 16 = (12 / 4) / (16 / 4)
= 3 / 4
(iv) 8 / 12 = (8 / 4) / (12 / 4)
= 2 / 3
(v) 4 / 16 = (4 / 4) / (16 / 4)
= 1 / 4
The following are the equivalent fractions
(a) and (ii) = 1 / 2
(b) and (iv) = 2 / 3
(c) and (i) = 1 / 3
(d) and (v) = 1 / 4
(e) and (iii) = 3 / 4


Q3. Replace NCERT Solutions for Class 6 Maths - Fractions in each of the following by the correct number:
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
Ans:

NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions


Q4. Find the equivalent fraction of 3/5 having
(a) denominator 20 
(b) numerator 9
(c) denominator 30 
(d) numerator 27
Ans: 
(a) We require denominator 20
Let M be the numerator of the fractions
∴ M / 20 = 3 / 5
5 × M = 20 × 3
M = (20 × 3) / 5
= 12
Therefore, the required fraction is 12 / 20
(b) We require numerator 9
Let N be the denominator of the fractions
∴ 9 / N = 3 / 5
3 × N = 9 × 5
N = (9 × 5) / 3
= 15
Therefore, the required fraction is 9 / 15
(c) We require denominator 30
Let D be the numerator of the fraction
∴ D / 30 = 3 / 5
5 × D = 3 × 30
D = (3 × 30) / 5
= 18
Therefore, the required fraction is 18 / 30
(d) We require numerator 27
Let N be the denominator of the fraction
∴ 27 / N = 3 / 5
3 × N = 5 × 27
N = (5 × 27) / 3
= 45
Therefore, the required fraction is 27 / 45


Q5. Find the equivalent fraction of 36/48 with
(a) numerator 9 
(b) denominator 4
Ans: 
(a) Given numerator = 9
∴ 9 / D = 36 / 48
D × 36 = 9 × 48
D = (9 × 48) / 36
D = 12
Hence, the equivalent fraction is 9 / 12
(b) Given, denominator = 4
∴ N / 4 = 36 / 48
N × 48 = 4 × 36
N = (4 × 36) / 48
= 3
Hence, the equivalent fraction is 3 / 4


Q6. Check whether the given fractions are equivalent:
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
Ans: 
(a) Given 5 / 9 and 30 / 54
We have 5 × 54 = 270
9 × 30 = 270
5 × 54 = 9 × 30
Hence, 5 / 9 and 30 / 54 are equivalent fractions
(b) Given 3 / 10 and 12 / 50
We have 3 × 50 = 150
10 × 12 = 120
3 × 50 ≠ 10 × 12
Hence, 3 / 10 and 12 / 50 are not equivalent fractions
(c) Given 7 / 13 and 5 / 11
We have 7 × 11 = 77
5 × 13 = 65
7 × 11 ≠ 5 × 13
Hence, 7 / 13 and 5 / 11 are not equivalent fractions


Q7. Reduce the following fractions to the simplest form:
(a) 48/60
(b) 150/60
(c) 84/98
(d) 12/52
(e) 7/28
Ans:
(a) 48 / 60 = (12 × 4) / (12 × 5)
= 4 / 5
(b) 150 / 60 = (30 × 5) / (30 × 2)
= 5 / 2
(c) 84 / 98 = (14 × 6) / (14 × 7)
= 6 / 7
(d) 12 / 52 = (3 × 4) / (13 × 4)
= 3 / 13
(e) 7 / 28 = 7 / (7 × 4)
= 1 / 4


Q8. Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check if each has used up an equal fraction of her/his pencils?
Ans: Total number of pencils Ramesh had = 20
Number of pencils used by Ramesh = 10
∴ Fraction = 10 / 20 = 1 / 2
Total number of pencils Sheelu had = 50
Number of pencils used by Sheelu = 25
∴ Fraction = 25 / 50 = 1 / 2
Total number of pencils Jamaal had = 80
Number of pencils used by Jamaal = 40
∴ Fraction = 40 / 80 = 1 / 2
Yes, each has used up an equal fraction of pencils i.e 1 / 2


Q9. Match the equivalent fractions and write two more for each.
NCERT Solutions for Class 6 Maths - FractionsAns:
(i) 250 / 400
= (5 × 50) / (8 × 50)
= 5 / 8
25 / 40 and 30 / 48 are two more fractions
(ii) 180 / 200
= (9 × 20) / (10 × 20)
= 9 / 10
18 / 20 and 27 / 30 are two more fractions
(iii) 660 / 990
= (2 × 330) / (3 × 330)
= 2 / 3
20 / 30 and 200 / 300 are two more fractions
(iv) 180 / 360
= (1 × 180) / (2 × 180)
= 1 / 2
20 / 40 and 30 / 60 are two more fractions
(v) 220 / 550
= (2 × 110) / (5 × 110)
= 2 / 5
20 / 50 and 40 / 100 are two more fractions
∴ The equivalent fractions are
NCERT Solutions for Class 6 Maths - Fractions


Exercise 7.4

Q1. Write the shaded portion as a fraction. Arrange them in ascending and descending order using correct sign ‘<’, ‘=’, ‘>’ between the fractions:
NCERT Solutions for Class 6 Maths - Fractions(c) Show NCERT Solutions for Class 6 Maths - Fractions on the number line. Put appropriate signs between the fractions given.
NCERT Solutions for Class 6 Maths - Fractions
Ans: (a) First circle shows 3 shaded parts out of 8 equal parts. Hence, the fraction is 3 / 8
Second circle shows 6 shaded parts out of 8 equal parts. Hence, the fraction is 6 / 8
Third circle shows 4 shaded parts out of 8 equal parts. Hence, the fraction is 4 / 8
Fourth circle shows 1 shaded parts out of 8 equal parts. Hence, the fraction is 1 / 8
The arranged fractions are:
1 / 8 < 3 / 8 < 4 / 8 < 6 / 8
(b) First square shows 8 shaded parts out of 9 equal parts. Hence, the fraction is 8 / 9
Second square shows 4 shaded parts out of 9 equal parts. Hence, the fraction is 4 / 9
Third square shows 3 shaded parts out of 9 equal parts. Hence, the fraction is 3 / 9
Fourth square shows 6 shaded parts out of 9 equal parts. Hence, the fraction is 6 / 9
The arranged fractions are:
3 / 9 < 4 / 9 < 6 / 9 < 8 / 9
(c) Each unit length should be divided into 6 equal parts to represent the fractions 2 / 6, 4 / 6, 8 / 6 and
6 / 6 on number line. These fractions can be represented as follows:
NCERT Solutions for Class 6 Maths - Fractions

Now appropriate signs between the fractions are given below:
5/6 (>) 2/6, 3/6 (>) 0, 1/6 (<) 6/6, 8/6 (>) 5/6.


Q2. Compare the fractions and put an appropriate sign.
NCERT Solutions for Class 6 Maths - Fractions
Ans: 
(a) Here both fractions have same denominators. So, the fraction with greater numerator is the highest factor
∴ 3 / 6 < 5 / 6
(b) Multiply by 4
1 / 7 = (1 × 4) / (7 × 4)
= 4 / 28
Multiply by 7
1 / 4 = (1 × 7) / (4 × 7)
= 7 / 28
Here 4 < 7
∴ 1 / 7 < 1 / 4
(c) Here both fractions have same denominators. So, the fraction with greater numerator is the highest factor
∴ 4 / 5 < 5 / 5
(d) Here both numerators are same. So, the fraction having less denominator will be the highest factor
∴ 3 / 7 < 3 / 5


Q3. Make five more each pairs and put appropriate signs. 
Ans:
(i) 5 / 8 < 6 / 8
Here, the denominators are same. So, the fraction having greater numerator is the highest factor
(ii) 5 / 8 > 2 / 8
Here, the denominators are same. So, the fraction having greater numerator is the highest factor
(iii) 6 / 13 > 6 / 18
Here, the numerators are same. So, the fraction having lesser denominator will be the highest factor
(iv) 5 / 25 > 3 / 25
Here, the denominators are same. So, the fraction having greater numerator is the highest factor
(v) 9 / 50 < 9 / 45
Here, the numerators are same. So, the fraction having lesser denominator will be the highest factor


Q4. Look at the figures and write ‘<’ or ‘>’, ‘=’ between the given pairs of fractions.
NCERT Solutions for Class 6 Maths - Fractions(a) 1 / 6 ☐ 1 / 3 
(b) 3 / 4 ☐ 2 / 6 
(c) 2 / 3 ☐ 2 / 4 
(d) 6 / 6 ☐ 3 / 3 
(e) 5 / 6 ☐ 5 / 5

Ans: 
(a) Here, the numerators are same. So, the fraction having lesser denominator is the greater
∴ 1 / 6 < 1 / 3
(b) 3 / 4 = (3 × 3) / (4 × 3)
= 9 / 12
2 / 6 = (2 × 2) / (6 × 2)
= 4 / 12
Between 4 / 12, 9 / 12
Both fractions have same denominators. So, the fraction having greater numerator will be the greater
∴ 9 / 12 > 4 / 12
3 / 4 > 2 / 6
(c) Here, the numerators are same. So, the fraction having lesser denominator is the greater
∴ 2 / 3 > 2 / 4
(d) We get 6 / 6 = 1 and 3 / 3 = 1
So, 6 / 6 = 3 / 3
(e) Here, the numerators are same. So, the fraction having lesser denominator is the greater
∴ 5 / 6 < 5 / 5


Q5. How quickly can you do this? Fill appropriate sign. ( ‘<’, ‘=’, ‘>’)
(a) 1 / 2 ☐ 1 / 5
(b) 2 / 4 ☐ 3 / 6
(c) 3 / 5 ☐ 2 / 3
(d) 3 / 4 ☐ 2 / 8
(e) 3 / 5 ☐ 6 / 5
(f) 7 / 9 ☐ 3 / 9
(g) 1 / 4 ☐ 2 / 8
(h) 6 / 10 ☐ 4 / 5
(i) 3 / 4 ☐ 7 / 8
(j) 6 / 10 ☐ 3 / 5
(k) 5 / 7 ☐ 15 / 21
Ans:
(a) Here, the numerators are same. So, the fraction having lesser denominator is greater
∴ 1 / 2 > 1 / 5
(b) 2 / 4 = 1 / 2 and 3 / 6 = 1 / 2
∴ 2 / 4 = 3 / 6
(c) 3 / 5 = (3 × 3) / (5 × 3)
= 9 / 15
2 / 3 = (2 × 5) / 3 × 5)
= 10 / 15
Here, between 9 / 15 and 10 / 15 both have same denominators. Hence, the fraction having greater numerator will be the greater.
∴ 3 / 5 < 2 / 3
(d) Here, 2 / 8 = 1 / 4
As, 3 / 4 and 1 / 4 have same denominators. Hence, the fraction having greater numerator will be the greater
∴ 3 / 4 > 2 / 8
(e) Here, the denominators are same. So, the fraction having greater numerator will be the greater
∴ 3 / 5 < 6 / 5
(f) Here, the denominators are same. So, the fraction having greater numerator will be the greater
∴ 7 / 9 > 3 / 9
(g) We know 2 / 8 = 1 / 4
Hence, 1 / 4 = 2 / 8
(h) 6 / 10 = (3 × 2) / (5 × 2)
= 3 / 5
Between 3 / 5 and 4 / 5
Both have same denominators. So, the fraction having greater numerator will be greater
∴ 6 / 10 < 4 / 5
(i) 3 / 4 = (3 × 2) / (4 × 2)
= 6 / 8
Between 6 / 8 and 7 / 8
Both have same denominators. So, the fraction having greater numerator will be greater
∴ 3 / 4 < 7 / 8
(j) 6 / 10 = (3 × 2) / (5 × 2)
= 3 / 5
∴ 6 / 10 = 3 / 5
(k) 5 / 7 = (5 × 3) / (7 × 3)
= 15 / 21
∴ 5 / 7 = 15 / 21


Q6. The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.
(a) 2/12
(b) 3/15
(c) 8/50
(d) 16/100
(e) 10/60
(f) 15/75
(g) 12/60
(h) 16/96
(i) 12/75
(j) 12/72
(k) 3/18
(l) 4/25
Ans: 
(a) 2 / 12 = (1 × 2) / (6 × 2)
= 1 / 6
(b) 3 / 15 = (1 × 3) / (5 × 3)
= 1 / 5
(c) 8 / 50 = (4 × 2) / (25 × 2)
= 4 / 25
(d) 16 / 100 = (4 × 4) / (25 × 4)
= 4 / 25
(e) 10 / 60 = (1 × 10) / (6 × 10)
= 1 / 6
(f) 15 / 75 = (1 × 15) / (5 × 15)
= 1 / 5
(g) 12 / 60 = (1 × 12) / (5 × 12)
= 1 / 5
(h) 16 / 96
= (1 × 16) / (6 × 16)
= 1 / 6
(i) 12 / 75 = (4 × 3) / (25 × 3)
= 4 / 25
(j) 12 / 72 = (1 × 12) / 6 × 12)
= 1 / 6
(k) 3 / 18 = (1 × 3) / (6 × 3)
= 1 / 6
(l) 4 / 25
Totally there are 3 groups of equivalent fractions.
1 / 6 = (a), (e), (h), (j), (k)
1 / 5 = (b), (f), (g)
4 / 25 = (c), (d), (i), (l)


Q7. Find answers to the following. Write and indicate how you solved them.
(a) Is 5 / 9 equal to 4 / 5?
(b) Is 9 / 16 equal to 5 / 9?
(c) Is 4 /5 equal to 16 / 20?
(d) Is 1 / 15 equal to 4 / 30?
Ans: 
(a) 5 / 9, 4 / 5
Convert these fractions into like fractions
5 / 9 = (5 / 9) × (5 / 5)
= 25 / 45
4 / 5 = (4 / 5) × (9 / 9)
= 36 / 45
∴ 25 / 45 ≠ 36 / 45
Hence, 5 / 9 is not equal to 4 / 5
(b) 9 / 16, 5 / 9
Convert into like fractions
9 / 16 = (9 / 16) × (9 / 9)
= 81 / 144
5 / 9 = (5 / 9) × (16 / 16)
= 80 / 144
∴ 81 / 144 ≠ 80 / 144
Hence, 9 / 16 is not equal to 5 / 9
(c) 4 / 5, 16 / 20
16 / 20 = (4 × 4) / (5 × 4)
= 4 / 5
∴ 4 / 5 = 16 / 20
Hence, 4 / 5 is equal to 16 / 20
(d) 1 / 15, 4 / 30
4 / 30 = (2 × 2) / (15 × 2)
= 2 / 15
∴ 1 / 15 ≠ 4 / 30
Hence, 1 / 15 is not equal to 4 / 30


Q8. Ila read 25 pages of a book containing 100 pages. Lalita read 2 / 5 of the same book. Who read less?
Ans: Total number of pages a book has = 100 pages
Lalita read = 2 / 5 × 100 = 40 pages
Ila read = 25 pages
∴ Ila read less than Lalita.


Q9. Rafiq exercised for 3 / 6 of an hour, while Rohit exercised for 3 / 4 of an hour. Who exercised for a longer time?
Ans: Rafiq exercised = 3 / 6 of an hour
Rohit exercised = 3 / 4 of a hour
3 / 6, 3 / 4
Convert these into like fractions
3 / 6 = (3 × 2) / (6 × 2)
= 6 / 12
3 / 4 = (3 × 3) / (4 × 3)
= 9 / 12
Clearly, 9 / 12 > 6 / 12
∴ 3 / 4 > 3 / 6
Therefore Rohit exercised for a longer time than Rafiq.


Q10. In a class A of 25 students, 20 passed with 60% or more marks; in another class B of 30 students, 24 passed with 60% or more marks. In which class was a greater fraction of students getting with 60% or more marks?
Ans: Total number of students in Class A = 25
Students passed in first class in Class A = 20
Hence, fraction = 20 / 25
= 4 / 5
Total number of students in Class B = 30
Students passed in first class in Class B = 24
Hence, fraction = 24 / 30
= 4 / 5
∴ An equal fraction of students passed in first class in both the classes


Exercise 7.5

Q1. Write these fractions appropriately as additions or subtractions:
NCERT Solutions for Class 6 Maths - FractionsAns:
(a) Total number of parts each rectangle has = 5
No. of shaded parts in the first rectangle = 1 i.e 1 / 5
No. of shaded parts in the second rectangle = 2 i.e 2 / 5
No. of shaded parts in the third rectangle = 3 i.e 3 / 5
Clearly, the fraction represented by the third rectangle = Sum of the fractions represented by first and second rectangle
Hence, 1 / 5 + 2 / 5 = 3 / 5
(b) Total number of parts each circle has = 5
We may observe that the first, second and third circles represent 5, 3 and 2 shaded parts out of 5 equal parts respectively. Clearly, fraction represented by the third circle is the difference between the fractions represented by the first and second circles.
Hence, 5 / 5 – 3 / 5 = 2 / 5
(c) Here we may observe that first, second and third rectangles represents 2, 3 and 5 shaded parts out of 6 equal parts, respectively. Clearly, fraction represented by the third rectangle is the sum of fractions represented by the first and second rectangles.
Hence, 2 / 6 + 3 / 6 = 5 / 6


Q2. Solve:
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
Ans:
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions


Q3. Shubham painted 2/3of the wall space in his room. His sister Madhavi helped and painted 1/3 of the wall space. How much did they paint together?
Ans: Fraction of wall painted by Shubham = 2/3
Fraction of wall painted by Madhavi = 1/3
Total painting by both of them = NCERT Solutions for Class 6 Maths - Fractions
Therefore, they painted the complete wall.


Q4. Fill in the missing fractions.
(a) 7 / 10 – ▯ = 3 / 10 
(b) ▯ – 3 / 21 = 5 / 21 
(c) ▯ – 3 / 6 = 3 / 6 
(d) ▯ + 5 / 27 = 12 / 27

Ans:
(a) Given 7 / 10 – ▯ = 3 / 10
▯ = 7 / 10 – 3 / 10
▯ = (7 – 3) / 10
▯ = 4 / 10
▯ = 2 / 5
(b) Given ▯ – 3 / 21 = 5 / 21
▯ = 5 / 21 + 3 / 21
▯ = (5 + 3) / 21
▯ = 8 / 21
(c) Given ▯ – 3 / 6 = 3 / 6
▯ = 3 / 6 + 3 / 6
▯ = (3 + 3) / 6
▯ = 6 / 6
▯ = 1
(d) Given ▯ + 5 / 27 = 12 / 27
▯ = 12 / 27 – 5 /27
▯ = (12 – 5) / 27
▯ = 7 /27


Q5. Javed was given a basket of oranges. What fraction of oranges was left in the basket?
Ans:
Total = 1
Fraction of Orange left  NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
Thus, 2/7 oranges were left in the basket.


Exercise 7.6

Q1. Solve
(a) 2 / 3 + 1 / 7
(b) 3 / 10 + 7 / 15
(c) 4 / 9 + 2 / 7
(d) 5 / 7 + 1 / 3
(e) 2 / 5 + 1 / 6
(f) 4 / 5 + 2 / 3
(g) 3 / 4 – 1 / 3
(h) 5 / 6 – 1 / 3
(i) 2 / 3 + 3 / 4 + 1 / 2
(j) 1/ 2 + 1 / 3 + 1 / 6

NCERT Solutions for Class 6 Maths - Fractions

NCERT Solutions for Class 6 Maths - Fractions
(m) 16 / 5 – 7 / 5 
(n) 4 / 3 – 1 / 2

Ans:
(a) 2 / 3 + 1/ 7
Taking LCM
[(2 × 7) + (1 × 3)] / 21
= (14 + 3) / 21
= 17 / 21
(b) 3 / 10 + 7 / 15
Taking LCM 30
= [(3 × 3) + (7 × 2)] / 30
= (9 + 14) / 30
= 23 / 30
(c) 4 / 9 + 2/ 7
Taking LCM 63
= [(4 × 7) + (2 × 9)] / 63
= (28 + 18) / 63
= 46 / 63
(d) 5 / 7 + 1 / 3
Taking LCM 21
= [(5 × 3) + (1 × 7)] / 21
= (15 + 7) / 21
= 22 / 21
(e) 2 / 5 + 1 / 6
Taking LCM 30
= [(2 × 6) + (1 × 5)] / 30
= (12 + 5) / 30
= 17 / 30
(f) 4 / 5 + 2 / 3
Taking LCM 15
= [(4 × 3) + (2 × 5)] / 15
= (12 + 10) / 15
= 22 / 15
(g) 3 / 4 – 1 / 3
Taking LCM 12
= [(3 × 3) – (1 × 4)] / 12
= (9 – 4) / 12
= 5 / 12
(h) 5 / 6 – 1 / 3
Taking LCM 6
= [(5 × 1) – (1 × 2)] / 6
= (5 – 2) / 6
= 3 / 6
= 1 / 2
(i) 2 / 3 + 3 / 4 + 1 / 2
Taking LCM 12
= [(2 × 4) + (3 × 3) + (1 × 6)] / 12
= (8 + 9 + 6) / 12
= 23 / 12
(j) 1 / 2 + 1 / 3 + 1 / 6
Taking LCM 6
= [(1 × 3) + (1 × 2) + (1 × 1)] / 6
= (3 + 2 + 1) / 6
= 6 / 6
= 1  
NCERT Solutions for Class 6 Maths - Fractions= [(3 × 1) + 1] / 3 + [(3 × 3) + 2] / 3
= (3 + 1) / 3 + (9 + 2) / 3
= 4/ 3 + 11 / 3
= (4 + 11) / 3
= 15 / 3
= 5
NCERT Solutions for Class 6 Maths - Fractions= [(3 × 4) + 2] / 3 + [(3 × 4) + 1] / 4
= 14 / 3 + 13 / 4
= [(14 × 4) + (13 × 3)] / 12
= (56 + 39) / 12
= 95 / 12
(m) 16 / 5 – 7 / 5
= (16 – 7) / 5
= 9 / 5
(n) 4 /3 – 1 / 2
Taking LCM 6
= [(4 × 2) – (1 × 3)] / 6
= (8 – 3) /6
= 5 / 6


Q2. Sarita bought 2/5 metre of ribbon and Lalita 3/4 metre of ribbon. What is the total length of the ribbon they bought?
Ans: Ribbon bought by Sarita = 2/5 m and Ribbon bought by Lalita = 3/4 m
The total length of ribbon = NCERT Solutions for Class 6 Maths - Fractions
NCERT Solutions for Class 6 Maths - Fractions
Therefore, they bought NCERT Solutions for Class 6 Maths - Fractions  of ribbon.


Q3. Naina was given NCERT Solutions for Class 6 Maths - Fractions piece of cake and Najma was given NCERT Solutions for Class 6 Maths - Fractions piece of cake. Find the total amount of cake was given to both of them.
Ans: Cake taken by Naina = NCERT Solutions for Class 6 Maths - Fractions piece and Cake taken by Najma NCERT Solutions for Class 6 Maths - Fractions piece
Total cake taken
NCERT Solutions for Class 6 Maths - Fractions
Therefore, the total consumption of cake is NCERT Solutions for Class 6 Maths - Fractions


Q4. Fill in the boxes: 
(a) ▯ – 5 / 8 = 1 / 4 
(b) ▯ – 1 / 5 = 1 / 2 
(c) 1 / 2 – ▯ = 1 / 6

Ans:
NCERT Solutions for Class 6 Maths - Fractions


Q5. Complete the addition and subtraction box.
NCERT Solutions for Class 6 Maths - FractionsAns:
(a) 2 / 3 + 4 / 3
= (2 + 4) / 3
= 6 / 3
= 2
1 / 3 + 2 / 3
= (1 + 2) / 3
= 3 / 3
= 1
2 / 3 – 1 / 3
= (2 – 1) / 3
= 1 / 3
4 / 3 – 2 / 3
= (4 – 2) / 3
= 2 / 3
1 / 3 + 2 / 3
= (1 + 2) / 3
= 3 / 3
= 1
Hence, the complete given box is
NCERT Solutions for Class 6 Maths - Fractions

(b) 1 / 2 + 1 / 3
= [(1 × 3) + (1 × 2)] / 6
= (3 + 2) / 6
= 5 / 6
1 / 3 + 1 / 4
= [(1 × 4) + (1 × 3)] / 12
= (4 + 3) / 12
= 7 / 12
1 / 2 – 1 / 3
= [(1 × 3) – (1 × 2)] / 6
= (3 – 2) / 6
= 1 / 6
1 / 3 – 1 / 4
= [(1 × 4) – (1 ×3)] / 12
= (4 – 3) / 12
= 1 / 12
1 / 6 + 1 / 12
= [(1 × 2) + 1] / 12
= (2 + 1) / 12
= 3 / 12
= 1 / 4
Hence, the complete given box is
NCERT Solutions for Class 6 Maths - Fractions


Q6. A piece of wire 7 / 8 metre long broke into two pieces. One piece was 1 / 4 metre long. How long is the other piece?
Ans: Total length of wire = 7 / 8 metre
Length of one piece of wire = 1 / 4 metre
Length of other piece of wire = Length of the original wire and this one piece of wire
= 7 / 8 – 1 / 4
= [(7 × 1) – (1 × 2)] / 8
= (7 – 2) / 8
= 5 / 8
∴ Length of the other piece of wire = 5 / 8 metre


Q7. Nandini’s house is 9/10 km from her school. She walked some distance and then took a bus for 1/2 km to reach the school. How far did she walk?
Ans: Distance of the school from house = 9 / 10 km
Distance she travelled by bus = 1 / 2 km
Distance walked by Nandini = Total distance of the school – Distance she travelled by bus
= 9 / 10 – 1 / 2
= [(9 × 1) – (1 × 5)] / 10
= (9 – 5) / 10
= 4 / 10
= 2 / 5 km
∴ Distance walked by Nandini is 2 / 5 km


Q8. Asha and Samuel have bookshelves of the same size partly filled with books. Asha’s shelf is 5 / 6 th full and Samuel’s shelf is 2/ 5 th full. Whose bookshelf is more full? By what fraction?
Ans: Fraction of Asha’s bookshelf = 5 / 6
Fraction of Samuel’s bookshelf = 2 / 5
Convert these fractions into like fractions
5 / 6 = 5 / 6 × 5 / 5
= (5 × 5) / (6 × 5)
= 25 / 30
2 / 5 = 2 / 5 × 6 / 6
= (2 × 6) / (5 × 6)
= 12 / 30
25 / 30 > 12 / 30
5 / 6 > 2 / 5
∴ Asha’s bookshelf is more full than Samuel’s bookshelf
Difference = 5 / 6 – 2 / 5
= 25 / 30 – 12 / 30
= 13 / 30


Q9. Jaidev takes NCERT Solutions for Class 6 Maths - Fractionsminutes to walk across the school ground. Rahul takes 7/4 minutes to do the same. Who takes less time and by what fraction?
Ans:
Time taken by Jaidev to walk across the school ground =  NCERT Solutions for Class 6 Maths - Fractions= 11/5 minutes
Time taken by Rahul to walk across the school ground = 7 / 4 minutes
Convert these fractions into like fractions
11 / 5 = 11 / 5 × 4 / 4
= (11 × 4) / (5 × 4)
= 44 / 20
7 / 4 = 7 / 4 × 5 / 5
= (7 × 5) / (4 × 5)
= 35 / 20
Clearly, 44 / 20 > 35 / 20
11 / 5 > 7 / 4
∴ Rahul takes less time than Jaidev to walk across the school ground
Difference = 11 / 5 – 7 / 4
= 44 / 20 – 35 / 20
= 9 / 20
Hence, Rahul walks across the school ground by 9 / 20 minutes

The document NCERT Solutions for Class 6 Maths - Fractions is a part of the Class 6 Course Mathematics (Maths) Class 6.
All you need of Class 6 at this link: Class 6
94 videos|347 docs|54 tests

Top Courses for Class 6

FAQs on NCERT Solutions for Class 6 Maths - Fractions

1. What are fractions and how are they represented?
Ans.Fractions are a way to represent parts of a whole. They are written in the form of a numerator and a denominator, such as \(\frac{a}{b}\), where 'a' is the numerator (the number of parts we have) and 'b' is the denominator (the total number of equal parts the whole is divided into).
2. How do you add and subtract fractions with the same denominator?
Ans.To add or subtract fractions with the same denominator, you simply keep the denominator the same and add or subtract the numerators. For example, \(\frac{2}{5} + \frac{3}{5} = \frac{5}{5}\) and \(\frac{4}{7} - \frac{2}{7} = \frac{2}{7}\).
3. What is the process for adding fractions with different denominators?
Ans.To add fractions with different denominators, first find a common denominator, which is usually the least common multiple (LCM) of the denominators. Convert each fraction to an equivalent fraction with the common denominator, then add the numerators and keep the common denominator. For example, to add \(\frac{1}{4} + \frac{1}{6}\), the common denominator is 12, so it becomes \(\frac{3}{12} + \frac{2}{12} = \frac{5}{12}\).
4. How do you convert a mixed number into an improper fraction?
Ans.To convert a mixed number (like \(2\frac{1}{3}\)) into an improper fraction, multiply the whole number by the denominator and add the numerator. The result becomes the new numerator, and the denominator remains the same. For \(2\frac{1}{3}\), it becomes \(\frac{2 \times 3 + 1}{3} = \frac{7}{3}\).
5. What are equivalent fractions and how can you find them?
Ans.Equivalent fractions are fractions that represent the same value or proportion, even though they have different numerators and denominators. To find equivalent fractions, you can multiply or divide both the numerator and denominator by the same non-zero number. For example, \(\frac{1}{2}\) is equivalent to \(\frac{2}{4}\) because both are the same proportion of a whole.
94 videos|347 docs|54 tests
Download as PDF
Explore Courses for Class 6 exam

Top Courses for Class 6

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

study material

,

Semester Notes

,

past year papers

,

Free

,

Sample Paper

,

ppt

,

Viva Questions

,

Summary

,

Previous Year Questions with Solutions

,

NCERT Solutions for Class 6 Maths - Fractions

,

NCERT Solutions for Class 6 Maths - Fractions

,

practice quizzes

,

NCERT Solutions for Class 6 Maths - Fractions

,

MCQs

,

shortcuts and tricks

,

mock tests for examination

,

pdf

,

video lectures

,

Objective type Questions

,

Exam

,

Important questions

,

Extra Questions

;