JEE Main Previous Year Questions (2025): Ionic Equilibrium

 Page 1


JEE Main Previous Year Questions 
(2025): Ionic Equilibrium 
Q1: The molar solubility(s) of zirconium phosphate with molecular formula 
( ????
?? +
)
?? ( ????
?? ?? -
)
?? is given by relation : 
JEE Main 2025 (Online) 22nd January Evening Shift 
Options: 
A. (
K
sp
5348
)
1
6
 
B. (
K
sp
8435
)
1
7
 
C. (
?? ????
6912
)
1
7
 
D. (
K
sp
9612
)
1
3
 
Ans: C 
Solution: 
K
sp
= ( 3 s)
3
· ( 4 s)
4
 K
sp
= 6912 s
7
 s = (
KO
4
)
4
( s ) ? 3Zr
4+
( aq )+ 4PO
4
3-
( aq )
6912
)
1
7
 
Q2: Which of the following happens when ????
?? ???? is added gradually to the solution 
containing ???? ?? ?? +
 and ?? ????
?? +
 ions? 
Given : ?? sp 
[?? ( ???? )
?? ] = ?? × ????
-????
 and ?? sp 
[?? ( ???? )
?? ] = ???? × ????
-????
 at ?????? ?? . 
JEE Main 2025 (Online) 23rd January Morning Shift 
Options: 
A. A( OH )
2
 will precipitate before B( OH )
3
 
B. A( OH )
2
 and B( OH )
3
 will precipitate together 
C. Both A( OH )
2
 and B( OH )
3
 do not show precipitation with NH
4
OH 
D. B( OH )
3
 will precipitate before A( OH )
2
 
Ans: D 
Solution: 
Condition for precipitation Q
ip
> K
sp
 
For [A( OH )
2
] 
Page 2


JEE Main Previous Year Questions 
(2025): Ionic Equilibrium 
Q1: The molar solubility(s) of zirconium phosphate with molecular formula 
( ????
?? +
)
?? ( ????
?? ?? -
)
?? is given by relation : 
JEE Main 2025 (Online) 22nd January Evening Shift 
Options: 
A. (
K
sp
5348
)
1
6
 
B. (
K
sp
8435
)
1
7
 
C. (
?? ????
6912
)
1
7
 
D. (
K
sp
9612
)
1
3
 
Ans: C 
Solution: 
K
sp
= ( 3 s)
3
· ( 4 s)
4
 K
sp
= 6912 s
7
 s = (
KO
4
)
4
( s ) ? 3Zr
4+
( aq )+ 4PO
4
3-
( aq )
6912
)
1
7
 
Q2: Which of the following happens when ????
?? ???? is added gradually to the solution 
containing ???? ?? ?? +
 and ?? ????
?? +
 ions? 
Given : ?? sp 
[?? ( ???? )
?? ] = ?? × ????
-????
 and ?? sp 
[?? ( ???? )
?? ] = ???? × ????
-????
 at ?????? ?? . 
JEE Main 2025 (Online) 23rd January Morning Shift 
Options: 
A. A( OH )
2
 will precipitate before B( OH )
3
 
B. A( OH )
2
 and B( OH )
3
 will precipitate together 
C. Both A( OH )
2
 and B( OH )
3
 do not show precipitation with NH
4
OH 
D. B( OH )
3
 will precipitate before A( OH )
2
 
Ans: D 
Solution: 
Condition for precipitation Q
ip
> K
sp
 
For [A( OH )
2
] 
[A
2+
][OH
-
]
2
> 9 × 10
-10
[ A
+2
] = 1M
 ? [OH
-
] > 3 × 10
-5
M
 
For [B( OH )
3
] 
[B
3+
][OH
-
]
3
> 27 × 10
-18
[ B
3+
] = 1M
 ? [OH
-
] > 3 × 10
-6
M
 
So, B( OH )
3
 will precipitate before A( OH )
2
 
Q3: pH of water is 7 at ????
°
?? . If water is heated to ????
°
?? ., it's pH will : 
JEE Main 2025 (Online) 23rd January Evening Shift 
Options: 
A. Decrease 
B. Remains the same 
C. Increase 
D. H
+
concentration increases, OH
-
concentration decreases 
Ans: A 
Solution: 
When water is heated, its self-ionization increases. At 25
°
C, the water ionization constant is 
given by 
?? ?? = [H
+
][OH
-
] = 1.0 × 10
-14
 
so in pure water, 
[H
+
] = [OH
-
] = 1.0 × 10
-7
M, 
which corresponds to a pH of 7 . 
As water is heated to 80
°
C, the value of ?? ?? increases due to the endothermic nature of water's 
autoionization. This means that both [H
+
]and [OH
-
]increase. However, since their 
concentrations remain equal (which defines neutrality at that temperature), the pH isn't 7 
anymore. Instead, the increased concentration of H
+
ions leads to a pH value lower than 7 . 
Key points: 
? Heating water increases ?? ?? . 
? Higher ?? ?? means higher [H
+
](and equally higher [OH
-
]). 
? Thus, the pH decreases (e.g., it might be around 6.5 - 6.6 at 80
°
C ) even though the 
water is still neutral. 
So, the correct answer is: Option A - Decrease. 
Q4: ?? ????
 for ???? ( ???? )
?? is ?? . ?? × ????
-????
. What is the molar solubility of this salt in water? 
Page 3


JEE Main Previous Year Questions 
(2025): Ionic Equilibrium 
Q1: The molar solubility(s) of zirconium phosphate with molecular formula 
( ????
?? +
)
?? ( ????
?? ?? -
)
?? is given by relation : 
JEE Main 2025 (Online) 22nd January Evening Shift 
Options: 
A. (
K
sp
5348
)
1
6
 
B. (
K
sp
8435
)
1
7
 
C. (
?? ????
6912
)
1
7
 
D. (
K
sp
9612
)
1
3
 
Ans: C 
Solution: 
K
sp
= ( 3 s)
3
· ( 4 s)
4
 K
sp
= 6912 s
7
 s = (
KO
4
)
4
( s ) ? 3Zr
4+
( aq )+ 4PO
4
3-
( aq )
6912
)
1
7
 
Q2: Which of the following happens when ????
?? ???? is added gradually to the solution 
containing ???? ?? ?? +
 and ?? ????
?? +
 ions? 
Given : ?? sp 
[?? ( ???? )
?? ] = ?? × ????
-????
 and ?? sp 
[?? ( ???? )
?? ] = ???? × ????
-????
 at ?????? ?? . 
JEE Main 2025 (Online) 23rd January Morning Shift 
Options: 
A. A( OH )
2
 will precipitate before B( OH )
3
 
B. A( OH )
2
 and B( OH )
3
 will precipitate together 
C. Both A( OH )
2
 and B( OH )
3
 do not show precipitation with NH
4
OH 
D. B( OH )
3
 will precipitate before A( OH )
2
 
Ans: D 
Solution: 
Condition for precipitation Q
ip
> K
sp
 
For [A( OH )
2
] 
[A
2+
][OH
-
]
2
> 9 × 10
-10
[ A
+2
] = 1M
 ? [OH
-
] > 3 × 10
-5
M
 
For [B( OH )
3
] 
[B
3+
][OH
-
]
3
> 27 × 10
-18
[ B
3+
] = 1M
 ? [OH
-
] > 3 × 10
-6
M
 
So, B( OH )
3
 will precipitate before A( OH )
2
 
Q3: pH of water is 7 at ????
°
?? . If water is heated to ????
°
?? ., it's pH will : 
JEE Main 2025 (Online) 23rd January Evening Shift 
Options: 
A. Decrease 
B. Remains the same 
C. Increase 
D. H
+
concentration increases, OH
-
concentration decreases 
Ans: A 
Solution: 
When water is heated, its self-ionization increases. At 25
°
C, the water ionization constant is 
given by 
?? ?? = [H
+
][OH
-
] = 1.0 × 10
-14
 
so in pure water, 
[H
+
] = [OH
-
] = 1.0 × 10
-7
M, 
which corresponds to a pH of 7 . 
As water is heated to 80
°
C, the value of ?? ?? increases due to the endothermic nature of water's 
autoionization. This means that both [H
+
]and [OH
-
]increase. However, since their 
concentrations remain equal (which defines neutrality at that temperature), the pH isn't 7 
anymore. Instead, the increased concentration of H
+
ions leads to a pH value lower than 7 . 
Key points: 
? Heating water increases ?? ?? . 
? Higher ?? ?? means higher [H
+
](and equally higher [OH
-
]). 
? Thus, the pH decreases (e.g., it might be around 6.5 - 6.6 at 80
°
C ) even though the 
water is still neutral. 
So, the correct answer is: Option A - Decrease. 
Q4: ?? ????
 for ???? ( ???? )
?? is ?? . ?? × ????
-????
. What is the molar solubility of this salt in water? 
JEE Main 2025 (Online) 24th January Morning Shift 
Options: 
A. v1.8 × 10
-30
5
 
B. 
1.8×10
-30
27
 
C. v
1.6×10
-30
27
4
 
D. v1.6 × 10
-30
2
 
Ans: C 
Solution: 
To find the molar solubility of Cr( OH )
3
 in water, we start with the dissolution equilibrium: 
Cr( OH )
3( s)
? Cr
( aq)
3+
?? + 3OH
( aq)
-
3?? 
At equilibrium, the solubility product K
sp
 is given by: 
K
sp
= ( s)· ( 3 s)
3
= 27 s
4
 
Substituting the given K
sp
 value: 
27 s
4
= 1.6 × 10
-30
 
Solving for s , we divide both sides by 27 : 
s = (
1.6 × 10
-30
27
)
1/4
 
Thus, the molar solubility of Cr( OH )
3
 is: 
(
1.6
27
× 10
-30
)
1/4
 
Q5: A weak acid HA has degree of dissociation ?? . Which option gives the correct 
expression of ( ???? - ????
?? )? 
JEE Main 2025 (Online) 28th January Morning Shift 
Options: 
A. log (
1-?? ?? ) 
B. 0 
C. log ( 1 + 2x) 
D. log (
?? 1-?? ) 
Ans: D 
Solution: 
Page 4


JEE Main Previous Year Questions 
(2025): Ionic Equilibrium 
Q1: The molar solubility(s) of zirconium phosphate with molecular formula 
( ????
?? +
)
?? ( ????
?? ?? -
)
?? is given by relation : 
JEE Main 2025 (Online) 22nd January Evening Shift 
Options: 
A. (
K
sp
5348
)
1
6
 
B. (
K
sp
8435
)
1
7
 
C. (
?? ????
6912
)
1
7
 
D. (
K
sp
9612
)
1
3
 
Ans: C 
Solution: 
K
sp
= ( 3 s)
3
· ( 4 s)
4
 K
sp
= 6912 s
7
 s = (
KO
4
)
4
( s ) ? 3Zr
4+
( aq )+ 4PO
4
3-
( aq )
6912
)
1
7
 
Q2: Which of the following happens when ????
?? ???? is added gradually to the solution 
containing ???? ?? ?? +
 and ?? ????
?? +
 ions? 
Given : ?? sp 
[?? ( ???? )
?? ] = ?? × ????
-????
 and ?? sp 
[?? ( ???? )
?? ] = ???? × ????
-????
 at ?????? ?? . 
JEE Main 2025 (Online) 23rd January Morning Shift 
Options: 
A. A( OH )
2
 will precipitate before B( OH )
3
 
B. A( OH )
2
 and B( OH )
3
 will precipitate together 
C. Both A( OH )
2
 and B( OH )
3
 do not show precipitation with NH
4
OH 
D. B( OH )
3
 will precipitate before A( OH )
2
 
Ans: D 
Solution: 
Condition for precipitation Q
ip
> K
sp
 
For [A( OH )
2
] 
[A
2+
][OH
-
]
2
> 9 × 10
-10
[ A
+2
] = 1M
 ? [OH
-
] > 3 × 10
-5
M
 
For [B( OH )
3
] 
[B
3+
][OH
-
]
3
> 27 × 10
-18
[ B
3+
] = 1M
 ? [OH
-
] > 3 × 10
-6
M
 
So, B( OH )
3
 will precipitate before A( OH )
2
 
Q3: pH of water is 7 at ????
°
?? . If water is heated to ????
°
?? ., it's pH will : 
JEE Main 2025 (Online) 23rd January Evening Shift 
Options: 
A. Decrease 
B. Remains the same 
C. Increase 
D. H
+
concentration increases, OH
-
concentration decreases 
Ans: A 
Solution: 
When water is heated, its self-ionization increases. At 25
°
C, the water ionization constant is 
given by 
?? ?? = [H
+
][OH
-
] = 1.0 × 10
-14
 
so in pure water, 
[H
+
] = [OH
-
] = 1.0 × 10
-7
M, 
which corresponds to a pH of 7 . 
As water is heated to 80
°
C, the value of ?? ?? increases due to the endothermic nature of water's 
autoionization. This means that both [H
+
]and [OH
-
]increase. However, since their 
concentrations remain equal (which defines neutrality at that temperature), the pH isn't 7 
anymore. Instead, the increased concentration of H
+
ions leads to a pH value lower than 7 . 
Key points: 
? Heating water increases ?? ?? . 
? Higher ?? ?? means higher [H
+
](and equally higher [OH
-
]). 
? Thus, the pH decreases (e.g., it might be around 6.5 - 6.6 at 80
°
C ) even though the 
water is still neutral. 
So, the correct answer is: Option A - Decrease. 
Q4: ?? ????
 for ???? ( ???? )
?? is ?? . ?? × ????
-????
. What is the molar solubility of this salt in water? 
JEE Main 2025 (Online) 24th January Morning Shift 
Options: 
A. v1.8 × 10
-30
5
 
B. 
1.8×10
-30
27
 
C. v
1.6×10
-30
27
4
 
D. v1.6 × 10
-30
2
 
Ans: C 
Solution: 
To find the molar solubility of Cr( OH )
3
 in water, we start with the dissolution equilibrium: 
Cr( OH )
3( s)
? Cr
( aq)
3+
?? + 3OH
( aq)
-
3?? 
At equilibrium, the solubility product K
sp
 is given by: 
K
sp
= ( s)· ( 3 s)
3
= 27 s
4
 
Substituting the given K
sp
 value: 
27 s
4
= 1.6 × 10
-30
 
Solving for s , we divide both sides by 27 : 
s = (
1.6 × 10
-30
27
)
1/4
 
Thus, the molar solubility of Cr( OH )
3
 is: 
(
1.6
27
× 10
-30
)
1/4
 
Q5: A weak acid HA has degree of dissociation ?? . Which option gives the correct 
expression of ( ???? - ????
?? )? 
JEE Main 2025 (Online) 28th January Morning Shift 
Options: 
A. log (
1-?? ?? ) 
B. 0 
C. log ( 1 + 2x) 
D. log (
?? 1-?? ) 
Ans: D 
Solution: 
HA ? H
?
+ A
?
t = 0 a
t = t a( 1 - x)  ax ax 
K
a
= ( ax)
( x)
1 - x
; [H
+
] = ax
 -log ( K
a
)= -log ( ax)- log (
x
1 - x
)
pKa= pH- log (
x
1 - x
)
pH- pKa= log (
x
1 - x
)
 
Q6: Arrange the following in increasing order of solubility product : 
???? ( ???? )
?? , ???????? , ?????? , ?????? 
JEE Main 2025 (Online) 28th January Evening Shift 
Options: 
A. PbS< HgS< Ca ( OH )
2
< AgBr 
B. HgS< AgBr < PbS< Ca ( OH )
2
 
C. HgS< PbS< AgBr < Ca ( OH )
2
 
D. Ca ( OH )
2
< AgBr < HgS< PbS 
Ans: C 
Solution: 
Based on the Ksp values and salt analysis cation identification, we can say that order of Ksp 
value is: 
HgS< PbS< AgBr < Ca ( OH )
2
 
Ksp values 
HgS? 4 × 10
-53
 
PbS? 8 × 10
-28
 
AgBr ? 5 × 10
-13
 
Ca ( OH )
2
? 5.5 × 10
-6
 
Q7: If equal volumes of ?? ?? ?? and ???? (both are salts) aqueous solutions are mixed, 
which of the following combination will give a precipitate of ????
?? at 300 K ?(Given ?? sp 
 
( at 300 K ) for ????
?? = ?? . ?? × ????
-?? ) 
JEE Main 2025 (Online) 2nd April Morning Shift 
Options: 
A. 2.0 × 10
-4
MAB
2
, 0.8 × 10
-3
MXY 
B. 2.0 × 10
-2
MAB
2
, 2.0 × 10
-2
MXY 
C. 1.5 × 10
-4
MAB
2
, 1.5 × 10
-3
MXY 
D. 3.6 × 10
-3
MAB
2
, 5.0 × 10
-4
MXY 
Ans: B 
Solution: 
Page 5


JEE Main Previous Year Questions 
(2025): Ionic Equilibrium 
Q1: The molar solubility(s) of zirconium phosphate with molecular formula 
( ????
?? +
)
?? ( ????
?? ?? -
)
?? is given by relation : 
JEE Main 2025 (Online) 22nd January Evening Shift 
Options: 
A. (
K
sp
5348
)
1
6
 
B. (
K
sp
8435
)
1
7
 
C. (
?? ????
6912
)
1
7
 
D. (
K
sp
9612
)
1
3
 
Ans: C 
Solution: 
K
sp
= ( 3 s)
3
· ( 4 s)
4
 K
sp
= 6912 s
7
 s = (
KO
4
)
4
( s ) ? 3Zr
4+
( aq )+ 4PO
4
3-
( aq )
6912
)
1
7
 
Q2: Which of the following happens when ????
?? ???? is added gradually to the solution 
containing ???? ?? ?? +
 and ?? ????
?? +
 ions? 
Given : ?? sp 
[?? ( ???? )
?? ] = ?? × ????
-????
 and ?? sp 
[?? ( ???? )
?? ] = ???? × ????
-????
 at ?????? ?? . 
JEE Main 2025 (Online) 23rd January Morning Shift 
Options: 
A. A( OH )
2
 will precipitate before B( OH )
3
 
B. A( OH )
2
 and B( OH )
3
 will precipitate together 
C. Both A( OH )
2
 and B( OH )
3
 do not show precipitation with NH
4
OH 
D. B( OH )
3
 will precipitate before A( OH )
2
 
Ans: D 
Solution: 
Condition for precipitation Q
ip
> K
sp
 
For [A( OH )
2
] 
[A
2+
][OH
-
]
2
> 9 × 10
-10
[ A
+2
] = 1M
 ? [OH
-
] > 3 × 10
-5
M
 
For [B( OH )
3
] 
[B
3+
][OH
-
]
3
> 27 × 10
-18
[ B
3+
] = 1M
 ? [OH
-
] > 3 × 10
-6
M
 
So, B( OH )
3
 will precipitate before A( OH )
2
 
Q3: pH of water is 7 at ????
°
?? . If water is heated to ????
°
?? ., it's pH will : 
JEE Main 2025 (Online) 23rd January Evening Shift 
Options: 
A. Decrease 
B. Remains the same 
C. Increase 
D. H
+
concentration increases, OH
-
concentration decreases 
Ans: A 
Solution: 
When water is heated, its self-ionization increases. At 25
°
C, the water ionization constant is 
given by 
?? ?? = [H
+
][OH
-
] = 1.0 × 10
-14
 
so in pure water, 
[H
+
] = [OH
-
] = 1.0 × 10
-7
M, 
which corresponds to a pH of 7 . 
As water is heated to 80
°
C, the value of ?? ?? increases due to the endothermic nature of water's 
autoionization. This means that both [H
+
]and [OH
-
]increase. However, since their 
concentrations remain equal (which defines neutrality at that temperature), the pH isn't 7 
anymore. Instead, the increased concentration of H
+
ions leads to a pH value lower than 7 . 
Key points: 
? Heating water increases ?? ?? . 
? Higher ?? ?? means higher [H
+
](and equally higher [OH
-
]). 
? Thus, the pH decreases (e.g., it might be around 6.5 - 6.6 at 80
°
C ) even though the 
water is still neutral. 
So, the correct answer is: Option A - Decrease. 
Q4: ?? ????
 for ???? ( ???? )
?? is ?? . ?? × ????
-????
. What is the molar solubility of this salt in water? 
JEE Main 2025 (Online) 24th January Morning Shift 
Options: 
A. v1.8 × 10
-30
5
 
B. 
1.8×10
-30
27
 
C. v
1.6×10
-30
27
4
 
D. v1.6 × 10
-30
2
 
Ans: C 
Solution: 
To find the molar solubility of Cr( OH )
3
 in water, we start with the dissolution equilibrium: 
Cr( OH )
3( s)
? Cr
( aq)
3+
?? + 3OH
( aq)
-
3?? 
At equilibrium, the solubility product K
sp
 is given by: 
K
sp
= ( s)· ( 3 s)
3
= 27 s
4
 
Substituting the given K
sp
 value: 
27 s
4
= 1.6 × 10
-30
 
Solving for s , we divide both sides by 27 : 
s = (
1.6 × 10
-30
27
)
1/4
 
Thus, the molar solubility of Cr( OH )
3
 is: 
(
1.6
27
× 10
-30
)
1/4
 
Q5: A weak acid HA has degree of dissociation ?? . Which option gives the correct 
expression of ( ???? - ????
?? )? 
JEE Main 2025 (Online) 28th January Morning Shift 
Options: 
A. log (
1-?? ?? ) 
B. 0 
C. log ( 1 + 2x) 
D. log (
?? 1-?? ) 
Ans: D 
Solution: 
HA ? H
?
+ A
?
t = 0 a
t = t a( 1 - x)  ax ax 
K
a
= ( ax)
( x)
1 - x
; [H
+
] = ax
 -log ( K
a
)= -log ( ax)- log (
x
1 - x
)
pKa= pH- log (
x
1 - x
)
pH- pKa= log (
x
1 - x
)
 
Q6: Arrange the following in increasing order of solubility product : 
???? ( ???? )
?? , ???????? , ?????? , ?????? 
JEE Main 2025 (Online) 28th January Evening Shift 
Options: 
A. PbS< HgS< Ca ( OH )
2
< AgBr 
B. HgS< AgBr < PbS< Ca ( OH )
2
 
C. HgS< PbS< AgBr < Ca ( OH )
2
 
D. Ca ( OH )
2
< AgBr < HgS< PbS 
Ans: C 
Solution: 
Based on the Ksp values and salt analysis cation identification, we can say that order of Ksp 
value is: 
HgS< PbS< AgBr < Ca ( OH )
2
 
Ksp values 
HgS? 4 × 10
-53
 
PbS? 8 × 10
-28
 
AgBr ? 5 × 10
-13
 
Ca ( OH )
2
? 5.5 × 10
-6
 
Q7: If equal volumes of ?? ?? ?? and ???? (both are salts) aqueous solutions are mixed, 
which of the following combination will give a precipitate of ????
?? at 300 K ?(Given ?? sp 
 
( at 300 K ) for ????
?? = ?? . ?? × ????
-?? ) 
JEE Main 2025 (Online) 2nd April Morning Shift 
Options: 
A. 2.0 × 10
-4
MAB
2
, 0.8 × 10
-3
MXY 
B. 2.0 × 10
-2
MAB
2
, 2.0 × 10
-2
MXY 
C. 1.5 × 10
-4
MAB
2
, 1.5 × 10
-3
MXY 
D. 3.6 × 10
-3
MAB
2
, 5.0 × 10
-4
MXY 
Ans: B 
Solution: 
When equal volumes of solutions are mixed, the molarity of each solution halves. To determine 
if a precipitate will form, calculate the ionic product Q
SP
 using the formula: 
Q
SP
= [A
2+
][Y
-
]
2
 
A precipitate of ?? ?? 2
 will form if ?? ????
> ?? ?? ?? , where ?? ????
 is given as 5.2 × 10
-7
. 
Option 1 Calculation: 
Q
SP
= ( 1.8 × 10
-3
)(
5
2
× 10
-4
)
2
= Calculated value < K
SP
 
Option 2 Calculation: 
Q
SP
= ( 10
-4
) ( 0.4 × 10
-3
)
2
= Calculated value < K
SP
 
Option 3 Calculation: 
Q
SP
= ( 10
-2
) ( 10
-2
)
2
= Calculated value > K
SP
 
Option 4 Calculation: 
Q
SP
= (
1.5
2
× 10
-4
)(
1.5
2
× 10
-3
)
2
= Calculated value < K
SP
 
From the calculations, the solution in Option 3 will form a precipitate since the ionic product 
Q
SP
 is greater than the solubility product K
SP
. 
Q8: 40 mL of a mixture of ????
?? ???????? and ?????? (aqueous solution) is titrated against 0.1 
M NaOH solution conductometrically. Which of the following statement is correct? 
 
JEE Main 2025 (Online) 3rd April Evening Shift 
Options: 
A. The concentration of CH
3
COOH in the original mixture is 0.005 M 
B. The concentration of HCl in the original mixture is 0.005 M 
C. CH
3
COOH is neutralised first followed by neutralisation of HCl 
D. Point ' C ' indicates the complete neutralisation of HCl 
Ans: B 
Solution: