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Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1
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Page 1
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
Page 2
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
Page 3
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
CBSE VII | Mathematics
Sample Paper 1 – Solution
Section B
13.
2x-1 x+2
=
32
Multiply both sides by 6 (L.C.M of 3 and 2)
2 (2x -1) = 3 (x + 2)
4x - 2 = 3x + 6
Transpose 3x to L.H.S and -2 to R.H.S
4x -3x = 6 + 2
x = 8
14. Decrease in consumption = 10 - 8 = 2 kg
Therefore,
= ??
2
100 20
10
%
15. The rational form of the given decimals are:
The rational numbers obtained above can be represented as follows:
16. Area of the triangle ABC = 48 m
2
Height, CD = 12 m
Area =
1
2
x base x height
48 =
1
2
x AB x 12
6 x AB = 48
AB = 8 m
Thus, base AB = 8 m
Page 4
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
CBSE VII | Mathematics
Sample Paper 1 – Solution
Section B
13.
2x-1 x+2
=
32
Multiply both sides by 6 (L.C.M of 3 and 2)
2 (2x -1) = 3 (x + 2)
4x - 2 = 3x + 6
Transpose 3x to L.H.S and -2 to R.H.S
4x -3x = 6 + 2
x = 8
14. Decrease in consumption = 10 - 8 = 2 kg
Therefore,
= ??
2
100 20
10
%
15. The rational form of the given decimals are:
The rational numbers obtained above can be represented as follows:
16. Area of the triangle ABC = 48 m
2
Height, CD = 12 m
Area =
1
2
x base x height
48 =
1
2
x AB x 12
6 x AB = 48
AB = 8 m
Thus, base AB = 8 m
CBSE VII | Mathematics
Sample Paper 1 – Solution
17. Consider:
3(a + b) - 2(2a - b) + 4a - 7
= 3a + 3b - 4a + 2b + 4a - 7
= (3a - 4a + 4a) + (2b + 3b) - 7
= 3a + 5b - 7
18. We have,
Since bases are equal, powers are also equal.
19. The alphabet is H
It has 2 lines of symmetry as shown below:
After rotating the letter H through 180
o
, we find that the image remains same. So the
order of rotational symmetry is 2.
20. Number of cubes in the first layer = 5 x 5 = 25
Number of cubes in the second layer = 13 + 4 = 17
Number of cubes in third layer = 4
Hence, total number of cubes = 25 + 17 + 4 = 46
Page 5
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
CBSE VII | Mathematics
Sample Paper 1 – Solution
Section B
13.
2x-1 x+2
=
32
Multiply both sides by 6 (L.C.M of 3 and 2)
2 (2x -1) = 3 (x + 2)
4x - 2 = 3x + 6
Transpose 3x to L.H.S and -2 to R.H.S
4x -3x = 6 + 2
x = 8
14. Decrease in consumption = 10 - 8 = 2 kg
Therefore,
= ??
2
100 20
10
%
15. The rational form of the given decimals are:
The rational numbers obtained above can be represented as follows:
16. Area of the triangle ABC = 48 m
2
Height, CD = 12 m
Area =
1
2
x base x height
48 =
1
2
x AB x 12
6 x AB = 48
AB = 8 m
Thus, base AB = 8 m
CBSE VII | Mathematics
Sample Paper 1 – Solution
17. Consider:
3(a + b) - 2(2a - b) + 4a - 7
= 3a + 3b - 4a + 2b + 4a - 7
= (3a - 4a + 4a) + (2b + 3b) - 7
= 3a + 5b - 7
18. We have,
Since bases are equal, powers are also equal.
19. The alphabet is H
It has 2 lines of symmetry as shown below:
After rotating the letter H through 180
o
, we find that the image remains same. So the
order of rotational symmetry is 2.
20. Number of cubes in the first layer = 5 x 5 = 25
Number of cubes in the second layer = 13 + 4 = 17
Number of cubes in third layer = 4
Hence, total number of cubes = 25 + 17 + 4 = 46
CBSE VII | Mathematics
Sample Paper 1 – Solution
21. Drawing the relational part, the images become as follows:
22.
i. 343000 = 343 × 1000
= 7 × 7 × 7 × 10 × 10 × 10
= 7
3
×10
3
ii. 2048 = 2 × 1024
= 2 × 2 × 512
= 2 × 2 × 2 × 256
= 2 × 2 × 2 × 2 × 128
= 2 × 2 × 2 × 2 × 2 × 64
= 2 × 2 × 2 × 2 × 2 × 2 × 32
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 16
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 8
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
= 2
11
23. Total tons of hay owned by the farmer =
1
56
2
tons
Amount of hay sold by him =
3
5
of
1
56
2
tons
i.e.
3
5
×
1
56
2
['of' means multiplication]
3 113
=×
52
3×113
=
5×2
339
=
10
9
=33
10
Thus, the farmer sold
9
33
10
tons of hay.
Read MoreFAQs on Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1
| 1. What are the main topics covered in CBSE Class 7 Maths Term II sample question paper? |  |
Ans. CBSE Class 7 Maths Term II typically includes integers, fractions, decimals, algebra basics, geometry fundamentals, data handling, and mensuration concepts. The sample question paper reflects the actual exam structure with questions testing both conceptual understanding and problem-solving skills. Students should focus on practising these core areas to strengthen their mathematical foundation before the assessment.
| 2. How do I solve geometry problems involving lines and angles in Class 7 Maths? | |
Ans. Geometry problems in Class 7 require understanding angle relationships, parallel lines, and transversals. Start by identifying given information, draw accurate diagrams, and apply relevant angle properties systematically. Practise using flashcards and mind maps to memorise angle theorems, then work through sample question paper solutions to build confidence with different problem types and exam-style questions.
| 3. What's the difference between profit and loss calculations for Class 7 Maths exams? | |
Ans. Profit occurs when selling price exceeds cost price; loss occurs when cost price exceeds selling price. The formulas are: Profit = Selling Price - Cost Price and Loss = Cost Price - Selling Price. Class 7 students should practise applying these formulas through sample question paper solutions and work through percentage-based profit-loss problems commonly featured in CBSE assessments.
| 4. Why am I getting algebra equations wrong in Term II sample papers? | |
Ans. Common mistakes include mishandling negative signs, forgetting to apply operations to both equation sides, and computational errors. Careful equation-solving requires isolating variables step-by-step while maintaining balance. Review detailed solutions from sample question papers, use mind maps to visualise algebraic processes, and practise linear equation problems repeatedly to identify personal error patterns and improve accuracy.
| 5. How should I prepare data handling and probability concepts for the CBSE Class 7 Maths sample question paper? | |
Ans. Data handling and probability involve organising information through tables, graphs, and calculating simple event probabilities. Master frequency distribution, bar graphs, and basic probability principles by reviewing sample question paper solutions systematically. Refer to structured notes and MCQ tests focusing on data interpretation to strengthen both conceptual clarity and speed during actual CBSE exams.
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Document Description: Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1 for Class 7 2026 is part of Mathematics (Maths) Class 7 (Old NCERT) preparation. The notes and questions for Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1 have been prepared according to the Class 7 exam syllabus. Information about Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1 covers topics like and Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1 Example, for Class 7 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1.
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