L4 : Chemical Equation - Chemical Reaction, Science, Class 10 Video Lecture - Class 12

hello friends this video on chemical
reaction equations part 4 is brought to
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exam before watching this video please
make sure that you have watched part 1 -
Part 3 let's take for example you have
kclo3 + KCl they're going to case here
with + put the balances you don't see
any polyatomic thing CL 3 the polyatomic
thing but it is not here so will not
consider this correct please note here
Sierra 3 was a polyatomic thing but it
is not doing the product thing so will
not compare this you'll not consider
this correct so CL AR 3 is not handsome
any metal no nonmetal bashyam flowing
oxygen all so oxygen will put in last
because oxygen hydrogen has least pride
so let's see the balance thing he's
yellow this is my reactant is in the
product but a shame is 1 2 and product
there's only one finishing it is not
balanced let's multiply this guy with
two so what you get is kclo3 + case here
is going to do KCl + OD now let's again
see is balanced or not KCl Oh potassium
is - here here also T chlorine is 1+1 2
here also oxygen is here 3 here it is -
this is non violence so we will of
multiply this every 3 by 2 so let's
multiply this every 3 by 2 so what you
get here is kclo3
+ KCl is equal to K CL plus 3x2 put
let's see if it is balanced on KC alone
potassium is - hair product also -
chlorine is 1 plus 1
- hair red also - to KC and right to
chlorine oxygen is 3 here here also 3 by
2 into 2 g so it is balanced but there
is a fraction part
right so it removes Russian part it was
it is by two you multiply everything
into two so what you get is to KC and
three here comes two plus two KCl is
equal to 2 into 2 becomes 4 case here
plus 3 oh and this is my balanced
condition we will take 1 month on I am
taking more equations because for
example because the most critical part
of the chemical equation you should know
how to balance a chemical equation as a
foundation of the chemistry can say so
we have h n3 plus cos 2 it gives CNO 3/2
plus s2 is one chemical equation even if
you don't know about this compound right
it's ok you should just know how to
balance the chemical reactions so yes
balance this so here we have some
compound is there any compound yes
no.3 no.3 this guy's the reaction
product so we'll take into three is the
first priority then we'll take metals no
nonmetals we have calcium and then we
have hydrogen oxygen civility hydrogen
oxygen right so now we'll check this is
the my priority order right fried the
order will check in a three part
reactant and product team a reactant has
one no.3 product has to does not balance
still to multiply this guy with two so
what you get is 2h
in three class-c Oh H 2 is equal to C in
3 2 lastly please note here Oh H is but
also 1 polyatomic thing but which is not
here it is only in the reactant so we
didn't take action right but energy also
polyatomic thing it is there in reactant
and product both so we took energy hope
you understand this that polyatomic
thing has to be there in both site to
take that so we got this equation non
its compared so we have this in the 3 CH
no.3 is how many to here reactant and
what also we have to it is balanced
calcium we have 1 here also calcium we
have 1 right 1 1 hydrogen we have 2 + 2
4 right 2 + 2 4 here here we have 2
hydrogen's so hydrogen is non balanced
right see this part you can take this
part is going gone so 2 hydrogen here
Plus this again we can take we got this
here we have not assumed as a polyatomic
thing because this was not during the
product side right so we'll take two
hydrogen from here 2 plus 2 4 hydrogen's
here we have towards in please pay
attention here since
OS for the polyatomic thing is but still
we could not take this as one unit
because this guy is only in reactant
oven for a night so then we talk about
hydrogen will take hydrogen from this
also right so hydrogen 2+2 4 here and we
have really two hydrogen here not
balanced we multiply this they have it -
so what do you get is 2 H and O 3 plus c
a.o H to give CA n ot 2 + 2 H 3 now
let's check out of balance or not give
an OCC H o we have reactant and we
hunter
reacting no.3 is here is to molecule in
product we have in the street - can see
we have one here and we have one here
one one hydrogen we have 2 + 2 4 here
and here we have two oxygen so please
note will not take this oxygen because
this is already counted as part of no.3
will not take oxygen in this also
because this is already counted as part
of anything but will you take this
oxygen why because this o H we have not
considered self because they party to
make thing in the Triad till ends
because the product didn't harm is H so
we'll take H who from here but will not
take go from here please note once again
they'll not take oxygen from energy norm
will not consider that because it is
already counted for but we'll take from
this because H is not counted for right
which we didn't consider because of a
which was not the in the product side so
so for oxygen we have two oxygen here
and here we have again two oxygen
because this oxygen we won't come with
condolence oxygen so you can see them in
balanced right so this is my balanced
situation hope you understand this the
trick was here to us this in this the
oxygen we won't count because we have
already counted as oxygen but when we
take oxygen from this guy OAH because we
didn't count the edge let us take few
more examples we have nos surely - I +
h2so4 sulphuric acid give any two ways
imposed in sulphate in water so we have
to balance this equation so we already
know the mains of these things you
learned all these things in the past
classes you have to balance this
chemical equation so here also if you
see so4 is one unit here it also be ever
so for that guys were first tried right
and there are any metals no here sodium
will Dick's would you let me take
hydrogen you know so this now order the
pride
first you try to balance as a whole if
it is not balanced so let's check so we
have a simple and a children so this is
my reactant is my flora in this case we
see that su who D is 1 and here also we
have 1 1 and 1 is perfectly balanced
then comes surely M sodium we have 1
here and 2 here oops
it is unbalanced so let's multiply this
guy back to the new equation we get is
to any OAH plus h2 so4 is equal to n h2
so4 plus h2 let's again compare the
values i so for any H you know you have
reacted in product so sulfate we have
one here one here one one each sodium we
have two here two here tthe hydrogen so
we have two hydrogen's here plus two
four hydrogens here here we have only
two hydrogen's not balanced so let's
multiply b2 to do become smoke right so
what you get is two NaOH plus h2 so4
gives na2so4 plus two is true now if I
can compare so4 na h and oh yes reactant
we have product s o4 has one one sodium
is two hair sodium is two here
hydrogen is 2 u 2 1 2 + 2 4 here we have
2 into 2 4 oxygen bond if you have two
oxygen here this we won't consider
because this purely considered as part
of a so for this also mean won't
consider so we have already two oxygen
atoms here and here also we have two
oxygen atoms right this is my balanced
chemical equation everything is balanced
correct went a couple more examples NaCl
sodium chlorite + AG in a 3 so night
infant becomes a UCL plus nano3 so here
seller is ma any compound no metal yes
silver is the metal any compound yes
there's a compound man there's a
compound NF is a component so we'll take
no.3 first then we have metal building
metallurgy then we have gone metal
sodium chlorine first we'll try to
balance this is no.3 then we have AG in
the ends here the reactant is my product
right so no.3 how many and three here
one how many here 1 1 1 the rest AG how
many AG in reactant 1 in product one
sodium harmony slowly Haven reacted one
in product 1 CL how many CL in reactant
one product one you see the balance it
is already balanced it is no need to
balance the equation is already balanced
equation you don't do anything it's all
developed
let's take home example barium fluoride
be a CL to possess to a cell for cell
precursor give barium sulfate PSO 4 + SC
out let's see so we have a so forth in
here both side so I support is my first
ready then we'll take video the second
priority then we'll take glory
the third pride and here you we see that
some hydrogen is also there right so
we'll take five billion is the food
Friday they will compare now you see
sulfate part reactant we have one in
product we have one sulphate is vast
barium but the next barium barium we
have one here one here balanced next is
chlorine part we have two chlorine here
reactant product here only one chlorine
which is not balanced it's multiplied
with to correct so
what you get is no variant or i+ h2so4
gives barium sulfate plus 2ax see no a
let's see the balance part s o4 b CL NH
right the reactant is the product
sulfate has harmony one here one here
one gun balance barium is one here one
here balance
chlorine is two here two here balanced
how did you buy we have two hydrogen
here and two hydrogen here correct
balanced everything is balanced that
means it is my balanced chemical
equation this mass balance in dilution
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