General Solution to Second-Order Homogeneous LTI System
We now focus on the zero input response of the second-order LTI system of Eq. (1–17), i.e., we focus on the system
Suppose that we guess the solution to Eq. (1–26) as
xh(t) = eλt (1–27)
where λ is constant that has yet to be determined. Differentiating the assumed solution of Eq. (1–27) twice, we have
Substituting the results of Eqs. (1–28) and (1–29) into (1–26), we obtain
Then, because eλt is not zero as a function of time, it can be dropped from Eq. (1–30) to give
Equation (1–31) is called the characteristic equation whose roots give the behavior of the zero input response of Eq. (1–17). Using the quadratic formula, the roots of Eq. (1–31) are given as
It can be seen that the types of roots admitted by Eq. (1–31) depend upon the value of ζ. In particular, the types of roots are governed by the quantity ζ2 − 1. We have three cases to consider: (1) 0 ≤ ζ < 1, (2) ζ = 1, and (3) ζ > 1. We now consider each of these cases in turn.
Case 1: 0 ≤ ζ < 1 (Underdamping)
When 0 ≤ ζ < 1 the zero input response is said to be underdamped. For an underdamped system the quantity ζ2 − 1 < 0 which implies that The roots of the characteristic equation for an underdamped system are then given as
It is seen from Eq. (1–33) that the roots of the characteristic equation for an underdamped system are complex. Furthermore, the general zero input response for an underdamped system is given as
Eq. (1–34) can be written as
xh(t) = e −ζωnt (c1 cos ωdt + c2 sinωdt) (1–35)
where the quantity ωd = ωn is called the damped natural frequency of the system. The constants c1 and c2 can be solved for by using the initial conditions as follows. First, substituting the initial condition x(0) = x0 into Eq. (1–35), we obtain c1 as
xh(0) = x0 = c1 (1–36)
Next, differentiating xh(t) in Eq. (1–35), we obtain
Applying the initial condition we obtain
(1–38)
Substituting the result for c1 from Eq. (1–36) into Eq. (1–38), we obtain
(1–39)
Solving for c2 we have
The zero input response for an underdamped system is then given as
A schematic of the underdamped zero input response for various values of 0 ≤ ζ < is shown in Fig. 1–2.
Figure 1–2 Schematic of the zero input response of an underdamped second-order linear time-invariant system.
Case 2: ζ = 1 (Critical Damping)
When ζ = 1 the zero input response is said to be critically damped. For critically damped system the quantity ζ2 − 1 = 0 which implies that = 0. The roots of the characteristic equation for an underdamped system are then given as
λ1,2 = −ζωn = −ωn (1–42)
It is seen from Eq. (1–42) that the roots of the characteristic equation for a critically damped system are real and repeated (i.e., the two roots are the same). Furthermore, the general zero input response for a critically damped system is given as
xh(t) = e −ωnt (c1 + c2t) (1–43)
The constants c1 and c2 can be solved for by using the initial conditions as follows. First, applying the initial condition x(0) = x0 into Eq. (1–43), we have
xh(0) = x0 = c1 (1–44)
Next, differentiating Eq. (1–43), we obtain
(1–45)
Applying the initial condition we obtain
(1–46)
Substituting the result for c1 from Eq. (1–44), we have
(1–47)
Solving Eq. (1–47) for c2 gives
(1–48)
The zero input response for an critically damped system is then given as
(1–49)
A schematic of a critically damped zero input response is shown in Fig. 1–3.
Figure 1–3 Schematic of the zero input response of a critically damped second-order linear time-invariant system.
Case 3: ζ > 1 (Overdamping)
When ζ > 1 the zero input response is said to be overdamped. For an overdamped system the quantity ζ2 −1 > 0 which implies that The roots of the characteristic equation for an underdamped system are then given as
It is seen from Eq. (1–50) that the roots of an overdamped system are real and distinct. Furthermore, the general zero input response for an overdamped system is given as
xh(t) = c1eλ1t + c2eλ2t (1–51)
The constants c1 and c2 can be solved for by using the initial conditions as follows. First, applying the initial condition x(0) = x0, we obtain
xh(0) = x0 = c1 + c2 (1–52)
Next, differentiating Eq. (1–51) gives
(1–53)
Then, applying the initial condition x( ˙ 0) = x˙0, we obtain
(1–54)
Equations (1–52) and (1–54) can then be solved simultaneously for c1 and c2 to give
The general zero input response for an overdamped system is then given as
A schematic of an overdamped zero input response for various values of ζ > 1 is shown in Fig. 1–4.
Figure 1–4 Schematic of the zero input response of an overdamped second-order linear time-invariant system.
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1. What is a second order homogeneous LTI system? |
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