As performed in the real lab:
Materials Required:
Glazed paper, pencil, a pair of scissors, gum.
Procedure:
1. Make a parallelogram by paper folding. Call it ABCD.
2. Cut out the parallelogram with the help of a pair of scissors.
3. Obtain a perpendicular from D to AB meeting AB at E. [Fig A]
4. Cut and remove the triangle AED and align AD with BC. Call the displaced segment AE as BE'. [Fig B]
5. Verify using a scale that EBE' are collinear.
6. Verify that CE' is perpendicular to EBE and EE' = CD
7. Observe that the figure obtained is a rectangle.[Fig B]
As performed in the simulator:
Create a parallelogram ABCD with length L and breadth B.[Fig C]
Draw perpendicular from A to DC meeting at point E.
Click on "Set Square" in Tools to use it.
Drag and place Set Square such that point A and line DC is perpendicular.
Click on ▲ AED to separate it from parallelogram.
Drag ▲ AED and place it such a way that AD is overlapped with BC.
Please see the observation
Observation:
1. E is Colinear with base.
2. Line DE is perpendicular to base.
3. Therefore it will forms rectangle ABE'E.
4. Thus the area of parallelogram = area of rectangle ABE'E
= breadth X height
Note:
In some input cases, perpendicular of parallelogram may fall outside the base [E.g. Fig D]. In such cases click on parallelogram to rotate it and follow the same procedure as mentioned above.
Result:
Area of parallelogram is the product of its base and height.
1 videos228 docs21 tests

1. What is the formula to find the area of a parallelogram? 
2. How do you determine the base and height of a parallelogram? 
3. Can the base and height of a parallelogram be the same length? 
4. Is the formula for finding the area of a parallelogram the same as that for a rectangle? 
5. Can the area of a parallelogram be negative? 
1 videos228 docs21 tests


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