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Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10 PDF Download

Lakhmir Singh Physics Class 10 Solutions Page No:257

Question 18: A camera fitted with a lens of focal length 50 mm is being used to photograph a flower that is 5 cm in diameter. The flower is placed 20 cm in front of the camera lens.
 (a) At what distance from the film should the lens be adjusted to obtain a sharp image of the flower ?
 (b) What would be the diameter of the image of the flower on the film ?
 (c) What is the nature of camera lens ?

Solution :

Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10
The film should be at a distance of 6.66cm behind the camera lens,
Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10

Question 19: An object is 2 m from a lens which forms an erect image one-fourth (exactly) the size of the object. Determine the focal length of the lens. What type of lens is this ?

Solution :

Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10
Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10

Question 20: An image formed on a screen is three times the size of the object. The object and screen are 80 cm apart when the image is sharply focussed.
 (a) State which type of lens is used.
 (b) Calculate focal length of the lens.

Solution : (a) Since the image is formed on a screen, it must be a real image.

Hence, the lens should be a convex lens.

(b) m = -3 (Real and inverted image)

Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10
Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 | Extra Documents, Videos & Tests for Class 10

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FAQs on Solutions of Refraction of Light (Page No- 257) - Physics By Lakhmir Singh, Class 10 - Extra Documents, Videos & Tests for Class 10

1. What is refraction of light?
Ans. Refraction of light is the bending of light as it passes from one medium to another, due to a change in its speed. This change in speed causes the light ray to change its direction.
2. What are the laws of refraction?
Ans. The laws of refraction are: 1. The incident ray, the refracted ray, and the normal to the interface of two media at the point of incidence, all lie in the same plane. 2. The ratio of the sine of the angle of incidence to the sine of the angle of refraction is a constant, known as the refractive index. This is given by Snell's law: n₁ sin θ₁ = n₂ sin θ₂, where n₁ and n₂ are the refractive indices of the two media, and θ₁ and θ₂ are the angles of incidence and refraction, respectively.
3. How does refraction of light occur?
Ans. Refraction of light occurs when light passes from one medium to another with a different refractive index. This happens because the speed of light changes when it enters a medium with a different refractive index. As the speed of light changes, its direction also changes, causing the phenomenon of refraction.
4. What are some real-life examples of refraction of light?
Ans. Some real-life examples of refraction of light include: 1. The bending of a pencil in a glass of water. 2. The formation of a rainbow when sunlight passes through raindrops. 3. The apparent bending of a straw in a glass of water. 4. The magnifying effect of a lens.
5. How does refraction of light affect the appearance of objects underwater?
Ans. When light enters water from air, it undergoes refraction. This refraction causes objects to appear closer to the surface of the water than they actually are. It also makes objects appear distorted and can cause them to appear larger or smaller than they actually are. This is why objects underwater often look different from how they appear in air.
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