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The line x+y =4 divides the line joining the points (1,-1) and (5,7) in the ratio?
Ref: https://edurev.in/question/620103/The-line-xy-4-divides-the-line-joining-the-points-1-1-and-5-7-in-the-ratio-

MCQ: Straight Lines - Class 11

The given points are (-1, 1) and (5,7).
Hence equation of the line joining the above points is


MCQ: Straight Lines - Class 11


The point of intersection of the lines (1) and (2) is
xy=2x−y=−2
x+y=4
2x=2
⇒x=1 and y=3

Let the point (1,3) divide the line segment joining (-1,1) and (5,7) in the ratio 1 : k
By applying the section formula,

MCQ: Straight Lines - Class 11

Hence the line joining the points (-1, 1) and (5,7) is divided by line
x+y= in the ratio 1 : 2
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FAQs on MCQ: Straight Lines - Class 11

1. What are the basic concepts of straight lines in Class 11 Mathematics?
Ans. In Class 11 Mathematics, the basic concepts of straight lines include slope-intercept form, point-slope form, two-point form, intercept form, and general form of a straight line equation.
2. How do you find the slope of a straight line given two points?
Ans. To find the slope of a straight line given two points (x1, y1) and (x2, y2), we use the formula: slope = (y2 - y1) / (x2 - x1).
3. What is the significance of the y-intercept in a straight line equation?
Ans. The y-intercept in a straight line equation represents the value of y when the line intersects the y-axis. It helps determine the starting point of the line on the y-axis.
4. How do you find the equation of a straight line given its slope and a point on the line?
Ans. To find the equation of a straight line given its slope (m) and a point (x1, y1) on the line, we use the point-slope form: y - y1 = m(x - x1).
5. What is the general form of a straight line equation?
Ans. The general form of a straight line equation is Ax + By + C = 0, where A, B, and C are constants, and A and B are not both zero. This form allows us to represent any straight line equation in a standardized way.
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