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Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics PDF Download

Q 1. Which of the following figures lie on the same base and between the same parallels. In such a case, write the common base and two parallels:

SOLUTION :

Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics
Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics

(i)  Δ PCD and trapezium ABCD are on the same base CD and between the same parallels AB and DC.

(ii) Parallelograms ABCD and APQD are on the same base AD and between the same parallels AD and BQ.

(iii) Parallelogram ABCD and ΔPQR are between the same parallels AD and BC but they are not on the same base.

(iv) ΔQQRT and parallelogram PQRS are on the same base QR and between the same parallels QR and PS.

(v) Parallelograms PQRS and trapezium SMNR are on the same base but not between the same parallels.

(vi) Parallelograms PQRS, AQRD, BCQR are between the same parallels. Also, parallelograms PQRS, BPSC, APSD are between the same parallels.

(vi) Parallelograms PQRS, AQRD, BCQR are between the same parallels. Also, parallelograms PQRS, BPSC, APSD are between the same parallels.

The document Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions | RD Sharma Solutions for Class 9 Mathematics is a part of the Class 9 Course RD Sharma Solutions for Class 9 Mathematics.
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FAQs on Ex-15.1, Areas Of Parallelograms And Triangles, Class 9, Maths RD Sharma Solutions - RD Sharma Solutions for Class 9 Mathematics

1. What is the formula to find the area of a parallelogram?
Ans. The formula to find the area of a parallelogram is given as base multiplied by the height, i.e., Area = base × height.
2. How do you find the height of a parallelogram if the base and area are given?
Ans. To find the height of a parallelogram, you can rearrange the formula for the area of a parallelogram as height = Area / base.
3. What is the difference between a parallelogram and a triangle?
Ans. A parallelogram is a four-sided polygon with opposite sides that are parallel and equal in length, while a triangle is a three-sided polygon. Another difference is that a parallelogram has two pairs of opposite equal angles, whereas a triangle may have different types of angles.
4. Can a parallelogram have a right angle?
Ans. Yes, a parallelogram can have a right angle. If one of the angles in a parallelogram is a right angle, then the parallelogram is called a rectangle.
5. How do you find the area of a triangle?
Ans. The formula to find the area of a triangle is given as half of the product of the base and the height, i.e., Area = (1/2) × base × height.

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