Class 7 Exam  >  Class 7 Notes  >  RD Sharma Solutions for Class 7 Mathematics  >  RD Sharma Solutions - Ex - 9.3, Ratio And Proportion, Class 7, Math

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics PDF Download

Question 1:

Find which of the following are in proportion?
 (i) 33, 44, 66, 88
 (ii) 46, 69, 69, 46
 (iii) 72, 84, 186, 217

Answer 1:

(i) We have
                 Product of extremes = 33 ×× 88 = 2904
                 Product of means  = 44 ×× 66 = 2904
   Therefore, the product of the extremes is equal to the product of the means.
    Hence, 33, 44, 66, 88 are in proportion.
(ii) We have
                 Product of extremes = 46 ×× 46 = 2116
                 Product of means  = 69 ×× 69 = 4761
   Therefore, the product of the extremes is not equal to the product of the means.
    Hence, 46, 69, 69, 46 are not in proportion.
(iii) We have
                 Product of extremes = 72 ×× 217 = 15624
                 Product of means  = 84 ×× 186 = 15624
   Therefore, the product of the extremes is equal to the product of the means.
    Hence, 72, 84, 186, 217 are in proportion.

Question 2:

Find x in the following proportions:
 (i) 16 : 18 = x : 96
 (ii) x : 92 = 87 : 116

Answer 2:

(i) 16 : 18 = x : 96
    ⇒ 16, 18, x, and 96 are in proportion.
    ⇒ Product of extremes = Product of means

⇒  16 × 96 = 18  × x

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

 

(ii) x : 92 = 87 : 116
      ⇒ x, 92, 87, and 116 are in proportion.
      ⇒ Product of extremes = Product of means
      ⇒  x ×  116 = 87 ×  92

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

Question 3:

The ratio of the income to the expenditure of a family is 7 : 6. Find the savings if the income is Rs 1400.

Answer 3:

The ratio of the income of a family to its expenditure = 7 : 6.
Let us assume that the income and expenditure of the family are '7x' and '6x', respectively.
But the income = Rs. 1400.
Therefore, 7x = 1400
                  x = 1400/7 = 200
The expenditure = 6x = 6 × 200 = Rs. 1200.
Now, savings = Income - expenditure = Rs. (1400 - 1200) = Rs. 200.

 

Question 4:

The scale of a map is 1 : 4000000. What is the actual distance between the two towns if they are 5 cm apart on the map?

Answer 4:

The scale of the map = 1 : 4000000.
This means that 1 unit of distance on the map is equal to 4000000 units of the actual distance.
So, let us assume that the actual distance between the towns = 'x' cm.
Now, it is given that
   1 : 4000000 = 5 : x
Hence, 1, 4000000, 5 and x are in proportion.
Therefore, product of extremes = product of means

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

Since 1 km = 1000 m =1000××1 m =1000××100 cm = 100000 cm (1 m =100 cm),

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

 

Question 5:

The ratio of income of a person to his savings is 10 : 1. If his savings of one year are Rs 6000, what is his income per month?

Answer 5:

Savings in one year = Rs. 6000
So, savings per month = 6000/12 = Rs. 500.
Let the income per month be Rs 'x'.
Then, x : 500 = 10 : 1.
So, x, 500, 10 and 1 are in proportion.
Product of extremes = Product of means

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

Question 6:

An electric pole casts a shadow of length 20 metres at a time when a tree 6 metres high casts a shadow of length 8 metres. Find the height of the pole.

Answer 6:

Length of the shadow of the electric pole = 20 m
Length of the shadow of the tree = 8 m
Height of the tree = 6 m
Now, let us assume that the height of the pole is 'x' m.
Height of the electric pole : length of the shadow of the electric pole = Height of the tree : length of the shadow of the tree
 x : 20 = 6 : 8
Thus, x, 20, 6 and 8 are in proportion.
Product of extremes = Product of means

Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

The document Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics is a part of the Class 7 Course RD Sharma Solutions for Class 7 Mathematics.
All you need of Class 7 at this link: Class 7
97 docs

Top Courses for Class 7

FAQs on Ex - 9.3, Ratio And Proportion, Class 7, Math RD Sharma Solutions - RD Sharma Solutions for Class 7 Mathematics

1. What is the importance of studying ratio and proportion in mathematics?
Ans. Studying ratio and proportion in mathematics is important because it helps us understand the relationship between two or more quantities. It enables us to compare and analyze quantities in a meaningful way. Ratio and proportion are used in various real-life situations such as scaling, cooking, financial planning, and architecture.
2. How do you find the ratio between two quantities?
Ans. To find the ratio between two quantities, divide one quantity by the other. For example, if we have 3 apples and 5 oranges, the ratio of apples to oranges would be 3:5. This means that for every 3 apples, there are 5 oranges.
3. What are the properties of ratios and proportions?
Ans. The properties of ratios and proportions include: - The order of the terms in a ratio is important. For example, the ratio of 3:5 is not the same as the ratio of 5:3. - Ratios can be simplified by dividing both terms by their greatest common divisor. - Proportions are equations that state two ratios are equal. - Proportions can be solved using cross-multiplication.
4. How are ratios and proportions used in real-life situations?
Ans. Ratios and proportions are used in various real-life situations, such as: - Scaling: Ratios are used to scale up or down measurements, such as maps or models. - Cooking: Ratios are used to determine the quantities of ingredients needed for a recipe. - Financial planning: Ratios are used to analyze and compare financial data, such as profit margins or debt ratios. - Architecture: Ratios are used to design and create structures with the correct proportions.
5. Can you provide an example of solving a proportion?
Ans. Sure! Let's solve the proportion: 2/5 = x/10. To solve this proportion, we can cross-multiply: 2 * 10 = 5 * x 20 = 5x Dividing both sides by 5, we get: x = 4 So, the solution to the proportion is x = 4.
Explore Courses for Class 7 exam

Top Courses for Class 7

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

Ratio And Proportion

,

Ratio And Proportion

,

Ratio And Proportion

,

Summary

,

Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

,

Free

,

Exam

,

mock tests for examination

,

practice quizzes

,

Semester Notes

,

Objective type Questions

,

Important questions

,

study material

,

shortcuts and tricks

,

Sample Paper

,

Extra Questions

,

pdf

,

ppt

,

Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

,

MCQs

,

video lectures

,

Previous Year Questions with Solutions

,

Math RD Sharma Solutions | RD Sharma Solutions for Class 7 Mathematics

,

Viva Questions

,

Ex - 9.3

,

Class 7

,

Class 7

,

past year papers

,

Class 7

,

Ex - 9.3

,

Ex - 9.3

;