Class 6 Exam  >  Class 6 Notes  >  RD Sharma Solutions for Class 6 Mathematics  >  RD Sharma Solutions -Page No.9.5 & 9.6, Ratio Proportion And Unitary Method, Class 6, Maths

Page No.9.5 & 9.6, Ratio Proportion And Unitary Method, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download

PAGE NO 9.5:

Question 1: Express each of the following in the language of ratios:
(i) In a class, the number of girls in the merit list of the board examination is two times that of boys.
(ii) The number of student passing mathematics test is 2/3 of the number that appeared.

ANSWER:

(i)  The ratio of the number of girls in the merit list of the board examination to the number of boys in that list is 2 : 1.

(ii) The ratio of the number of students passing mathematics test to the total number of students appeared is 2 : 3.

PAGE NO 9.6:

Question 2: Express the following ratios in language of daily life:
(i) The ratio of the number of bad pencils to that good pencils produced in a factory is 1:9.
(ii) In India, the ratio of the number of villages to that of cities is about 2000:1.

ANSWER: (i) The ratio of the number of bad pencils to that of good pencils produced in a factory is 1 : 9 means out of 10 or (9 + 1)  pencils, 9 pencils are good and 1 is bad.
(ii) In India, the number of villages is 2,000 times that of the cities.


Question 3: Express each of the of the following rations in its simplest from:

(i) 60:72
(ii) 324:144
(iii) 85:391
(iv) 186:403
 

ANSWER: (i) 60 : 72 = 5 : 6 (dividing by 12)
(ii) 324 : 144 = 9 : 4 (dividing by 36)
(iii) 85 : 391 = 5 : 23 (dividing by 17)
(iv) 186 : 403 = 6 : 13 (dividing by 31)


Question 4: Find the ratio of the following in the simplest form:

(i) 75 paisa to Rs 3
(ii) 35 minutes to 45 minutes
(iii) 8 kg to 400 gm
(iv) 48 minutes to 1 hour
(v) 2 metres to 35 cm
(vi) 35 minutes to 45 seconds
(vii) 2 dozen to 3 scores
(viii) 3 weeks to 3 days
(ix) 48 min to 2 hour 40 min
(x) 3 m 5 cm to 35 cm.

ANSWER:

(i) ∵ Rs. 1 = 100 paise    
∴ 75  : 300 = 1 : 4

(ii)  35 : 45 = 7 : 9
(iii) ∵ 1 kg = 1000 gm    
∴ 8000 : 400 = 20 : 1
(iv) ∵ 1 Hour = 60 minute    
∴48 : 60 = 4 : 5
(v) ∵ 1 meter = 100 cm    
∴ 200 : 35 = 40 : 7
(vi) ∵ 1 min = 60 sec.    
∴ 35×60 : 45 = 140 : 3
(vii) ∵ 1 dozen = 12      
∴ 1 score = 20  
or 3 score = 3 × 20 = 60  
∴ 24 : 60 = 2 : 5.
(viii) ∵ 1 week = 7 days      
∴ 21 : 3 = 7 : 1
(ix) ∵ 1 hour = 60 minute    
∴ 2 hour 40 min = 2 × 60 + 40 = 160    
∴ 48 : 160 = 3 : 10
(x) ∵ 1 meter = 100 cm    
∴ 3 m 5 cm = 3 ×100 + 5 = 305 cm    
∴ 305 : 35 = 61 : 7


Question 5: Find the ratio of

(i) 3.2 metres to 56 metres
(ii) 10 metres to 25 cm.
(iii) 25 paisa to Rs 60
(iv) 10 litres to 0.25 litre

ANSWER: (i) The ratio of 3.2 metres to 56 metres = 3.2 : 56 = 0.4 : 7 = 2 : 35
(ii) The ratio of 10 metres to 25 cm = 1000 : 25 = 40 : 1
(iii) The ratio of 25 paisa to Rs 60 = 25 : 6000 = 1 : 240
(iv) The ratio of 10 litres to 0.25 litre = 10 : 0.25 = 40 : 1


Question 6: The number of boys and girls in a school are 1168 and 1095 respectively. Express the ratio of the number of boys to that of the girls in the simplest form.

ANSWER: Ratio of the number of boys to that of the girls is 1168 : 1095 = 16 : 15 (dividing by 73)


Question 7: Avinash works as a lecturer and earns Rs 12000 per month. His wife who is a doctor earns Rs 15000 per month. Find the following ratios:

(i) Avinash's income to the income of his wife
(ii) Avinash's income to their total income.

ANSWER: Avinash's income = Rs. 12000
Avinash's wife income = Rs. 15000
Total income = 12000 + 15000 = Rs. 27000
(i) Ratio of Avinash's income to the income of his wife = 12000 : 15000 = 4 : 5
(ii) Ratio of Avinash's income to their total income = 12000 : 27000 = 4 : 9


Question 8: Of the 72 persons working in an office, 28 are men and the remaining are women. Find the ratio of the number of:

(i) men to that of women
(ii) men to the total number persons
(iii) persons to that of women.

ANSWER:

Total number of persons = 72
Number of men = 28
Number of women = 72 −- 28 = 44
(i) Ratio of men to that of women = 28 : 44 = 7 : 11
(ii) Ratio of men to the total number of persons = 28 : 72 = 7 : 18
(iii) Ratio of persons to that of women = 72 : 44 = 18 : 11


Question 9: The length of a steel tape for measurements of buildings is 10 m and its width is 2.4 cm. What is the ratio of its length to width?

ANSWER:

Length of the steel tape = 10 m
= 10×100 cm10×100 cm = 1000 cm
Breadth of the steel tape = 2.4 cm

Page No.9.5 & 9.6, Ratio Proportion And Unitary Method, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics


Question 10: An office opens at 9 a.m. and closed at 5 p.m. with a lunch interval of 30 minutes. What is the ratio of lunch interval to the total period in office?

ANSWER:

Total period in office = 9 a.m. to 12 p.m. and 12 p.m. to 5 p.m.
= 3 hours + 5 hours = 8 hours
∵ 1 hour = 60 minutes
∴ 8 hours = 8 × 60 = 480 minutes
Ratio of lunch interval to total period = 30 : 480 = 1 : 16 (dividing by 30)


Question 11: A bullock-cart travels 24 km in 3 hours and a train travels 120 km in 2 hours. Find the ratio fo their speeds.

ANSWER:

Page No.9.5 & 9.6, Ratio Proportion And Unitary Method, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics

Distance covered by bullock-cart = 24 km
Time taken = 3 hours
Speed of bullock-cart = 24/3=8 km/h

Distance covered by train = 120 km
Time taken = 2 hours
Speed of train = 120/2=60 km/h

Ratio for their speeds = Speed of bullock-cart : Speed of train = 8 : 60
= 2 : 15 

Question 12: Margarette works in a factory and earns Rs 955 per month. She saves Rs 185 per month from her earnings. Find the ratio of:

(i) her savings to her income
(ii) her income to her expenditure
(iii) her savings to her expenditure.

ANSWER:

Income of Margarette per month = Rs. 955
Saving of Margarette per month = Rs. 185
Expenditure of Margarette per month = 955−-185 = Rs. 770
(i) Ratio of her saving to her income = 185 : 955 = 37 : 191
(ii) Ratio of her income to her expenditure = 955 : 770 =  191 : 154
(iii) Ratio of her saving to her expenditure = 185 : 770 =  37 : 154

(i)  Rs. 1 = 100 paise      75  : 300 = 1 : 4(ii)  35 : 45 = 7 : 9(iii)  1 kg = 1000 gm     8000 : 400 = 20 : 1(iv)  1 Hour = 60 minute     48 : 60 = 4 : 5(v)  1 meter = 100 cm     200 : 35 = 40 : 7(vi)  1 min = 60 sec.      35×60 : 45 = 140 :3(vii)  1 dozen = 12       1 score = 20   or 3 score = 3 × 20 = 60    24 : 60 = 2 : 5.(viii)  1 week = 7 days       21 : 3 = 7 : 1(ix)  1 hour = 60 minute      2 hour 40 min = 2 × 60 + 40 = 160      48 : 160 = 3 : 10(x)  1 meter = 100 cm      3 m 5 cm = 3 ×100 + 5 = 305 cm     305 : 35 = 61 : 

The document Page No.9.5 & 9.6, Ratio Proportion And Unitary Method, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
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FAQs on Page No.9.5 & 9.6, Ratio Proportion And Unitary Method, Class 6, Maths RD Sharma Solutions - RD Sharma Solutions for Class 6 Mathematics

1. What are RD Sharma Solutions?
RD Sharma Solutions are the comprehensive step-by-step solutions to the questions and exercises given in the RD Sharma textbook. These solutions help students understand and solve mathematical problems effectively. They provide a detailed explanation of each concept, making it easier for students to grasp the subject matter.
2. What topics are covered in RD Sharma Solutions for Class 6?
RD Sharma Solutions for Class 6 cover a wide range of topics, including ratio, proportion, and unitary method. These solutions provide a solid foundation in mathematical concepts and help students develop problem-solving skills. The solutions are designed to meet the curriculum requirements and provide a comprehensive understanding of the subject.
3. How can RD Sharma Solutions help in preparing for exams?
RD Sharma Solutions are a valuable resource for exam preparation. They provide in-depth explanations and step-by-step solutions to the textbook questions, helping students understand the concepts thoroughly. By practicing these solutions, students can improve their problem-solving skills and gain confidence in tackling different types of questions that may appear in the exams.
4. Are RD Sharma Solutions available online?
Yes, RD Sharma Solutions are available online. Many educational websites and platforms offer these solutions for free. Students can access them anytime and anywhere, making it convenient for self-study and revision. Online RD Sharma Solutions also provide interactive features and additional practice exercises, enhancing the learning experience.
5. How can I use RD Sharma Solutions effectively?
To use RD Sharma Solutions effectively, it is recommended to follow a systematic approach. First, read the chapter from the textbook and understand the concepts. Then, refer to the corresponding RD Sharma Solution for step-by-step guidance on solving the exercises. Try to solve the problems independently before referring to the solution. Afterward, compare your approach with the provided solution to identify any mistakes or areas for improvement. Regular practice using RD Sharma Solutions will help strengthen your understanding and problem-solving skills in mathematics.
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