Table of contents | |
Solutions | |
Types of Solutions | |
Vapour Pressure of a Solution | |
Raoult’s Law | |
Composition of the Vapour | |
Ideal solutions | |
Non-ideal Solutions |
In chemistry, a solution is a special type of homogeneous mixture composed of two or more substances.
Homogeneous means that the components of the mixture form a single phase. Heterogeneous means that the components of the mixture are of different phase.
If the solvent is a liquid, then almost all gases, liquids, and solids can be dissolved. Here are some examples:
1) Gas in liquid:
2) Liquid in liquid:
3) Solid in liquid:
If the solvent is a solid, then gases, liquids, and solids can be dissolved.
1) Gas in solids:
2) Liquid in solid:
3) Solid in solid:
The pressure exerted by vapours over the liquid surface at this equilibrium is called vapour pressure of the liquid.
This law is applied for a solution of liquid in liquids and can be stated as follows. “The partial vapour pressure of any component in the solution is directly proportional to its mole fraction”.
PA ∝ XA where PA = Partial Vapour pressure of XA
PA = KXA XA = Mole fraction of A in solution
For pure liquids XA = 1
Then K = P°A where P°A is the vapour pressure of component A is a pure state
Hence, PA = XAP°A, similarly for component B, PB = XBP°B
Assuming that vapours of a liquid is behaving like an ideal gas, then according to Dalton’s law of partial pressure the total pressure PT is given by
PT = PA + PB
= XAP0A + XBP0B
= XAP0A + (1-XA) P0B = Vapour pressure in terms of Mole fraction of Solvent.
= P0B + (P0A - P0B)XA
Example: The vapour pressure of ethanol and methanol are 44.5 mm and 88.7 mm Hg respectively. An ideal solution is formed at the same temperature by mixing 60 g of ethanol with 40 g of methanol. Calculate total vapour pressure of the solution.
Solution: Number of moles of ethanol = 60/40 = 1.5
Number of moles of methanol = 40/32 = 1.25
XB 1-0.4545 = 0.545
Let A = CH3OH, B = C2H5OH
Total pressure of the solution
PT = XAP°A + XBP°A = 0.4545 × 88.7 + 0.545 × 44.5 = 40.31 + 24.27 = 64.58 mm Hg
The composition of the liquid mixture and vapour that are in mutual equilibrium are not necessarily the same, the common sense suggest that the vapour pressure should be richer in the more volatile component. This expectation can be confirmed as follows:
Let the mole fraction of A and B in vapour phase be YA and YB then from Dalton’s law,
Provided the mixture of vapours behaves as an ideal gas
Rewriting equation (1)
Example: What is the composition of the vapour which is in equilibrium at 30°C with a benzene toluene solution with a mole fraction of benzene of 0.400?
(P°B = 119 torr and P°T = 37.0 torr)
Solution: Total pressure of the solution is given by
PT = XBP°B + XTP°T
= 0.4 × 119 + 0.6 × 37 = 47.6 + 22.2
= 69.8 torr
Applying Dalton’s law for mole fraction is vapour phase.
YT = 1 – 0.763 = 0.237
When the vapours of solution (containing liquids A and B is) condensed, the composition of liquids A and B in the condensate remains same. Vapour over condensate can again recondense and the composition of A and B in condensate (2) remains same as it was in vapour phase over condensate (1).
Example: Liquid A and B form an ideal solution. The vapour pressure of A and B at 100°C are 300 and 100 mm Hg respectively. Suppose that vapour above solution is composed of 1 mole of A and 1 mole of B is collected and condensed. This condensate is then heated at 100°C and vapour are again condensed to form a liquid L. What is the mole fraction of A in the vapours of L?
Solution: Vapour pressure due to vapours above solution
It is given that in vapour phase each of A and B are one mole each hence each of them have mole fraction 0.5 in vapour phase.
After condensation of vapours.
In condensate (1)
X'A 0.5, X'B 0.5
P'T 0.5 × 300 0.5 × 100 150 + 50 = 200 mm
Mole fraction A and B in vapour phase of condensate
When the vapours of the condensate (1) will again be vaporized in condensate (2) liquid L.
X"A = 0.75, X"B = 0.25, where X"A and X"B are mole fraction of A and B in liquid L.
P"T = 300 × 0.75 + 100 × 0.25 = 225 + 25 = 250 mm and mole fraction of A in vapour phase of the condensate (2) is given by
The solutions which obey raoult’s law at all compositions of solute in solvent at all temperature are called ideal solution.
Ideal solution can be obtained by mixing two components with identical molecular size, structure and they should have almost same intermolecular attraction e.g., two liquids A and B form an ideal solution when A-A and B-B molecular attractions will be same, and hence A-B molecular attraction will be almost same as A-A and B-B molecular attractions.
An ideal solution should have following characteristics
1. It should obey Raoult’s law i.e., PA = XAP°A and PA = XBP°B
2. ΔHmixing = 0, i.e. no heat should be absorbed or evolved during mixing.
3. ΔHmixing = 0, i.e. no expansion of contraction on mixing.
Examples of Ideal solutions:
(i) Ethyl chloride and ethyl bromide
(ii) n-hexane and n-heptane
(iii) CCl4 and SiCl4
.
The solution which deviates from ideal behaviour are called nonideal solution or real solutions and they do not obey Raoult’s law over entire range of composition. It has been found that on increasing dilution, a nonideal solution tend to be ideal.
Many pairs of liquids are present in which there is no uniformity of attractive forces, i.e., the adhesive and cohesive forces of attraction are not uniform between the two liquids, so that they deviate from the Raoult's law applied only to ideal solutions.
For non ideal solutions,
(i) i.e. they do not obey Raoult's law
(ii) ΔHmixing ≠ 0
(iii) ΔVmixing ≠ 0
Here, we have two cases:
Positive Deviation
When (i) PA > XA P°A & PB > XBP°B
(ii) ΔHmix > 0,
(iii) ΔVmix > 0
When the cohesive forces between like molecules are greater than the adhesive forces between dissimilar molecules, the dissimilarities of polarity leads both components to escape solution more easily. Therefore, the vapor pressure is greater than expected from the Raoult's law, showing positive deviation. If the deviation is large, then the vapor pressure curve shows a maximum at a particular composition and form a positive azeotrope. Some mixtures in which this happens are
(1) benzene and methanol, (2) carbon disulfide and acetone, and (3) chloroform and ethanol. When these pairs of components are mixed, the process is endothermic reaction as weaker intermolecular forces are formed so that ΔmixH is positive.
If the vapor pressure of a mixture is lower than expected from Raoult's law, there is said to be a negative deviation.
(i) PA < XAP°A & PB < XBP°B
(ii) ΔHmix < 0
(iii) ΔVmix < 0
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1. What are the different types of solutions? |
2. What is the vapour pressure of a solution? |
3. What is Raoult's Law? |
4. How is the composition of the vapour determined in a solution? |
5. What are ideal and non-ideal solutions? |
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