Using section formula, we get
Coordinates of P =
Now
,
So, P divides the line segment AB in the ratio 2 : 7.
Putting k = 2/7 in Y =
Hence, the value of y is 6.
Let the co-ordinates of point A be.
Centre lies on the mid-point of the diameter. So applying the mid-point formula we get,
x = 3
Similarly,
y = -10
So the co-ordinates of A are (3,−10)
Let ABCD be a parallelogram in which the co-ordinates of the vertices are A (−2,−1); B (1, 0); C (x, 3) and D (1, y).
Since ABCD is a parallelogram, the diagonals bisect each other. Therefore the mid-point of the diagonals of the parallelogram will coincide.
In general to find the mid-point of two pointsand we use section formula as,
The mid-point of the diagonals of the parallelogram will coincide.
So,
Therefore,
Now equate the individual terms to get the unknown value. So,
Similarly,
Therefore,
Let A (2, 0); B (9, 1); C (11, 6) and D (4, 4) be the vertices of a quadrilateral. We have to check if the quadrilateral ABCD is a rhombus or not.
So we should find the lengths of sides of quadrilateral ABCD.
All the sides of quadrilateral are unequal. Hence ABCD is not a rhombus.
The co-ordinates of a point which divided two points and internally in the ratio is given by the formula,
Here it is said that the point (−4,6) divides the points A(−6,10) and B(3,−8). Substituting these values in the above formula we have,
Equating the individual components we have,
Therefore the ratio in which the line is divided is
The ratio in which the y-axis divides two points and is λ:1
The co-ordinates of the point dividing two points and in the ratio is given as,
where,
Here the two given points are A(5,−6) and B(−1,−4).
Since, the y-axis divided the given line, so the x coordinate will be 0.
Thus the given points are divided by the y-axis in the ratio.
The co-ordinates of this point (x, y) can be found by using the earlier mentioned formula.
Thus the co-ordinates of the point which divides the given points in the required ratio are.
Let A (−3, 2); B (−5,−5); C (2,−3) and D (4, 4) be the vertices of a quadrilateral. We have to prove that the quadrilateral ABCD is a rhombus.
So we should find the lengths of sides of quadrilateral ABCD.
All the sides of quadrilateral are equal. Hence ABCD is a rhombus.
We have to find the lengths of the medians of a triangle whose co-ordinates of the vertices are A (0,−1); B (2, 1) and C (0, 3).
So we should find the mid-points of the sides of the triangle.
In general to find the mid-point of two pointsand we use section formula as,
Therefore mid-point P of side AB can be written as,
Now equate the individual terms to get,
So co-ordinates of P is (1, 0)
Similarly mid-point Q of side BC can be written as,
Now equate the individual terms to get,
So co-ordinates of Q is (1, 2)
Similarly mid-point R of side AC can be written as,
Now equate the individual terms to get,
So co-ordinates of R is (0, 1)
Therefore length of median from A to the side BC is,
Similarly length of median from B to the side AC is,
Similarly length of median from C to the side AB is
We have to find the lengths of the medians of a triangle whose co-ordinates of the vertices are A (5, 1); B (1, 5) and C (−3,−1).
So we should find the mid-points of the sides of the triangle.
In general to find the mid-point of two pointsand we use section formula as,
Therefore mid-point P of side AB can be written as,
Now equate the individual terms to get,
So co-ordinates of P is (3, 3)
Similarly mid-point Q of side BC can be written as,
Now equate the individual terms to get,
So co-ordinates of Q is (−1, 2)
Similarly mid-point R of side AC can be written as,
Now equate the individual terms to get,
So co-ordinates of R is (1, 0)
Therefore length of median from A to the side BC is,
Similarly length of median from B to the side AC is,
Similarly length of median from C to the side AB is
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