Real-valued mathematical functions
A real-valued function is a function whose outputs are real numbers. If the domain is a subset X of the real numbers, a real-valued function is written as f : X → R. For each x ∈ X the function assigns a real number f(x).

If f and g are real-valued functions defined on the same domain X ⊂ R, we can combine them by simple algebraic rules to obtain new functions. These operations are defined pointwise: the value of the combined function at x ∈ X is obtained by performing the corresponding arithmetic on f(x) and g(x).
If f : X → R and g : X → R, the sum function f + g : X → R is defined by
(f + g)(x) = f(x) + g(x), for all x ∈ X.
If f : X → R and g : X → R, the difference function f - g : X → R is defined by
(f - g)(x) = f(x) - g(x), for all x ∈ X.
Let f : X → R and let γ be a real number (scalar). The scalar multiple γf : X → R is defined by
(γf)(x) = γ·f(x), for all x ∈ X.
If f : X → R and g : X → R, the product function fg : X → R is defined by
(fg)(x) = f(x)·g(x), for all x ∈ X.
If f : X → R and g : X → R, the quotient (when defined) f/g : X → R is given by
(f / g)(x) = f(x) / g(x), for all x ∈ X with g(x) ≠ 0.
Two functions f, g : A → B are equal if and only if f(x) = g(x) for every x ∈ A. If f and g are equal then their graphs (as subsets of A × B) are the same.
Q.1.

find the value of k
Ans.
We need to consider only one equation.
2k = 6
k = 3
Q.2. Find the values of x and y.

Ans:
2x - 6 = 5
2x = 11
x = 11/2 = 5.5
4 - y = 3
y = 1
Q. Let f(x) = x3 and g(x) = 3x + 1 and a scalar, γ = 6. Find
(a) (f + g)(x) (b) (f - g)(x) (c) (γf)(x) (d) (γg)(x) (e) (fg)(x) (f) (f / g)(x)
Sol:
(f + g)(x) = f(x) + g(x) = x3 + 3x + 1.
(f - g)(x) = f(x) - g(x) = x3 - (3x + 1) = x3 - 3x - 1.
(γf)(x) = γ·f(x) = 6x3.
(γg)(x) = γ·g(x) = 6(3x + 1) = 18x + 6.
(fg)(x) = f(x)·g(x) = x3(3x + 1) = 3x4 + x3.
(f / g)(x) = f(x)/g(x) = x3/(3x + 1), provided 3x + 1 ≠ 0, i.e. x ≠ -1/3.
A binary operation on a non-empty set A is a rule that combines any two elements of A to produce another element of A. Formally, a binary operation * on A is a function * : A × A → A. The inputs are ordered pairs (a, b) with a, b ∈ A, and the output a * b must lie in A.

Closure means: for all a, b ∈ A, the element a * b ∈ A. Closure is part of the definition of a binary operation.
A binary operation * on A is commutative if a * b = b * a for all a, b ∈ A. Example: addition and multiplication of real numbers are commutative.
A binary operation * on A is associative if (a * b) * c = a * (b * c) for all a, b, c ∈ A. Example: addition and multiplication of real numbers are associative.
Let * and o be two binary operations on A. We say * is left-distributive over o if a * (b o c) = (a * b) o (a * c) for all a, b, c ∈ A. Similarly, * is right-distributive over o if (b o c) * a = (b * a) o (c * a) for all a, b, c ∈ A. Example: multiplication is distributive over addition in R.
An element e ∈ A is an identity element for * if a * e = a = e * a for every a ∈ A. If an identity exists it is unique. Example: 0 is the additive identity in R; 1 is the multiplicative identity in R.
For a binary operation * with identity e, an element b ∈ A is an inverse of a ∈ A if a * b = e = b * a. If an inverse exists it is unique for the given a. Example: for multiplication on R \ {0}, the inverse of a is 1/a.
Note:
Q.1. Show that division is not a binary operation in N nor subtraction in N.
Solution.
Let a, b ∈ N.
Consider the operation division (÷): N × N → N given by (a, b) → a / b. For a = 5 and b = 3, a / b = 5/3 which is not a natural number. Therefore division is not a binary operation on N.
Consider subtraction (-): N × N → N given by (a, b) → a - b. For a = 2 and b = 3, a - b = -1 which is not a natural number. Therefore subtraction is not a binary operation on N.
Q.2. Let A = {-1, 1, 2, 3}. Construct the binary table corresponding to the binary operation "multiplication" on A.
Solution.
We list the products of all ordered pairs from A. The binary (multiplication) table has rows and columns indexed by -1, 1, 2, 3 and each cell is the product of the corresponding row and column elements.

Working with algebra of real functions is fundamental for calculus, modelling, and problem solving. Binary operations and their properties are basic building blocks for algebraic structures such as groups, rings and fields which appear in higher mathematics and in competition problems. Recognising where operations are defined, where identities and inverses exist, and which properties (commutativity, associativity, distributivity) hold is essential for manipulating expressions correctly.
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