CBSE Class 6  >  Class 6 Notes  >   All Subjects (Old NCERT)  >  Sample Paper 1 - Term 1 Mathematics, Class 6

Sample Paper 1 - Term 1 Mathematics, Class 6

Section A

(Questions 1 to 12 carry 1 mark each)

Q 1. Which of the following statements is shown by the given number line?
Section A
(a) 8 - 5 = 3
(b) 8 + 5 = 13
(c) 3 - 8 = -5
(d) 8 + 3 = 11

Correct Answer is Option (a)
On the given number line, from 8, five steps are moved towards the left.
Thus, the number line represents 8 - 5 = 3.


Q 2. 12 × (45 + 30) =
(a) (12 × 45) + (12 × 30)
(b) 12 × 65
(c) 12 × 45 × 30
(d) (12 × 45) × (12 × 30)

Correct Answer is Option (a)

According to distributive law of multiplication over addition, we have:
12 × (45 + 30) = (12 × 45) + (12 × 30)


Q 3. The sum of 267 + 132 to nearest ten is
(a) 500
(b) 400
(c) 300
(d) 200

Correct Answer is Option (b)
267 can be estimated as 270.
132 can be estimated as 130.
Thus the required estimated sum = 270 + 130 = 400


Q 4. The greatest number that will divide 10 and 18 is
(a) 4
(b) 2
(c) 5
(d) 3

Correct Answer is Option (b)
We have 10 = 2 × 5
18 = 2 × 3 × 3
HCF of 10 and 18 is 2.
Thus, 2 is the required number.


Q 5. Mixed fraction for 5/3 is
(a) Section A
(b) Section A
(c) Section A
(d) Section A

Correct Answer is Option (a)
To convert into mixed fraction first divide numerator by denominator. The quotient is taken as the whole number part of mixed fraction. Remainder obtained is taken as the numerator and divisor as the denominator of the fractional part of the mixed fraction.
Therefore, Section A


Q 6. What does the shaded region in the following figure represent?
Section A(a) Segment of a circle
(b) Radius of a circle
(c) Chord of a circle
(d) Sector of a circle

Correct Answer is Option (d)
A region in the interior of a circle enclosed by an arc on one side and a pair of radii on the other two sides is called a sector of the circle.


7. How many thousands make a crore?
(a) 10
(b) 100
(c) 1000
(d) 10000

Correct Answer is Option (d) 
One crore can be written as 1,00,00,000.
One thousand can be written as 1000.
So, 10000 times one thousand would make one crore.


8. How many whole numbers are there up to 1000?
(a) 1001
(b) 1000
(c) 100
(d) 999

Correct Answer is Option (a)
There are 1000 + 1 = 1001 whole numbers upto 1000.
i.e., 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, ........., 1000


Q 9. (-42) + (-35) =
(a) -7
(b) 7
(c) -77
(d) 41

Correct Answer is Option (c)
(-42) + (-35) = -42 - 35 = -77


Q 10. Which is the fifth multiple of 18?
(a) 80
(b) 90
(c) 72
(d) 180

Correct Answer is Option (b)
Fifth multiple of 18 = 18 × 5 = 90


Q 11. The improper fraction for Section A is________
(a) 10/3
(b) 3/10
(c) 1/3
(d) 3/1

Correct Answer is Option (a)
Section A


Q 12. The English alphabet Z represents a/an ______ curve.
(a) Closed
(b) Open
(c) Polygon
(d) Triangle

Correct Answer is Option (b)
The English alphabet Z represents an open curve.


Section B

Q 13. Evaluate the difference between the place values of two 9's in the number 79520986.

Place value of 9 at the Ten Lakhs place = 9000000
Place value of 9 at the hundreds place = 900
Difference = 9000000 - 900 = 8999100


Q 14. Name all the radii drawn in the given figure.
Section B

Radius of a circle is a line joining the center of circle to any point on the circle. So, the radii drawn in the given figure are OP, OQ and OR.


Q 15. How many vertices do the following shapes have?
Section B
Section B
Section B
Section B

The number of vertices in the given shapes:
(i) Sphere: 0
(ii) Cylinder: 0
(iii) Cone: 1
(iv) Pyramid: 5


Q 16. Anna is standing on a rock that is 7 feet above sea level. She jumps off the rock and hits another rock 3 feet below and then walks 2 feet down. How many feet did she come down in all?

Anna is 7 feet above sea level.
She jumps 3 feet down and walks another 2 feet down. Total distance travelled downwards = 3 + 2 = 5 feet.
Section B


Q 17. Find the sum: (-13) + (-19) + (+15) + (-10).

(-13) + (-19) + (+15) + (-10)
= -13 - 19 + 15 - 10
= -13 - 19 - 10 + 15
= -42 + 15
= -27


Q 18. Write a 9 digit number in Indian system (in Numerals) and then write it in words according to International system.

A 9-digit numeral in Indian system = 94,50,27,983
In International system:
945,027,983: Nine hundred forty five million twenty seven thousand nine hundred eighty three.


Q 19. There is a line on which the points G, H and I lie such that H is in between G and I.
Section B

Section B
Section B
Section B


Q 20. Use divisibility test to determine whether the number 1258 is divisible by 6.

Given number is 1258.
Its unit digit is 8, which is divisible by 2. So, 1258 is divisible by 2.
Sum of its digits = 1 + 2 + 5 + 8 = 16, which is not divisible by 3.
So, 1258 is not divisible by 3.
Since, 1258 is divisible by 2 but not by 3, it is not divisible by 6.


Q 21. Subtract 3 from 8 using a number line.

Starting from zero, a jump of 8 units is made to the right to reach 8. Then, 3 jumps (each of 1 unit i.e. from 8 to 7, 7 to 6, 6 to 5) are taken to the left to reach 5.
Section BSo, we conclude that 8 - 3 = 5


Q 22. Fill in the blanks with appropriate symbols '>" or '<".
(i) -9 ___ -15
(ii) -10 ___ 10
(iii) 0 ___ 3
(iv) -28 ____ 17

(i) -9 > -15
(ii) -10 < 10
(iii) 0 < 3
(iv) -28 < 17


Q 23. In the following triangle, find the measure of ∠X.
Section B

Since the sum of all three angles of a triangle is 180o.
We have, ∠X + ∠Y + ∠Z = 180o 
Or, ∠X + 60o + 50o = 180o 
Or, ∠X + 110= 180o 
Or, ∠X = 180o - 110o 
Hence, ∠X = 70o


Q 24. Complete the following patterns by using the distributive property of multiplication over addition for whole numbers:
101 × 33 = 3333
101 × 333 = 33633
101 × 3333 = ?
101 × 33333 = ?

Using distributive property of multiplication over addition, we have:
101 × 33 = (100 + 1) × 33 = 3300 + 33 = 3333
101 × 333 = (100 + 1) × 333 = 33300 + 333 = 33633
101 × 3333 = (100 + 1) × 3333 = 333300 + 3333 = 336633
101 × 33333 = (100 + 1) × 33333 = 3333300 + 33333 = 3366633


Section C

(Questions 25 to 32 carry 3 marks each)

Q 25. Tanvi bought a notebook for Rs Section C and a pen for Rs Section CHow much money should she pay to the shopkeeper?

Cost of notebook Section C
Cost of pen Section C
LCM of 4 and 5 = (2 × 2 × 5) = 20
Total cost of both the items
Section C
Section C
Section C


Q 26. Arrange the fractions Section C in ascending order.

The given fractions areSection C
Section C
LCM of 3, 6, 9, 12 = (3 x 2 x 3 x 2) = 36
So, we convert each one of given fractions into an equivalent fraction having 36 as denominator.
Now,
Section C
Clearly,
Section C
The given fractions in ascending order are Section C


Q 27. The sum of two numbers is 55 and the H.C.F. and L.C.M. of these numbers are 5 and 120 respectively. Find the sum of the reciprocals of the numbers.

Let the numbers be a and b.
Then, a + b = 55 and ab = 5 × 120 = 600
Therefore, the required sum = Section C


Q 28. Answer the following questions for the given figure.
(a) What are lines p, q, and r called?
(b) What is the point at which they meet called? Label it on the figure.
(c) How many lines can pass through the labeled point?
Section C

(a) Lines p, q and r are intersecting lines.
(b) Point at which the lines meet is called the point of intersection. The point O represents the point of intersection.
Section C(c) Infinite number of lines can pass through the point O (point of intersection).


Q 29. Compare the fractions Section C

Section C
LCM of 12 and 16 = (4 × 3 × 4) = 48
So, we convert each one of Section C into an equivalent fraction having 48 as denominator.
Section C


Q 30. Each corner of a cube is cut off, leaving a triangular face at each corner and an octagonal face in place of each face of the original cube. How many vertices and faces will the new polyhedron have?
Section C

Each of the 8 vertices of the cube has now been replaced by three vertices of a triangle. So, there are now 24 vertices. The cube had 6 square faces. Now those faces are still there but have become octagons. Additionally, there are now 8 new triangular faces. So, there is a total of 14 faces.


Q 31. Solve (-8 + 12 - 2) using number line.

To solve using number line start with -8, move 12 steps right and then back 2 steps as shown below:
Section CSo, we reach at 2, therefore (-8 + 12 - 2) = 2


Q 32. Shweta has made a chart on 'Elementary Shapes'. She develops a pattern for the border using sticks as follows:
Section CSection CFind a rule that helps her find the number of sticks. 

Let the number of triangles be n.
For 1 triangle: Number of sticks = 2 × 1 + 1 = 3 sticks
For 2 triangles: Number of sticks = 2 × 2 + 1 = 5 sticks
∴ Number of sticks used = 2 × n + 1


Section D 

(Questions 33 to 37 carry 4 marks each)

Q 33. The cost of a pen is Rs. Section D  and that of a pencil is Rs. Section D Which costs more and by how much?

Cost of a pen = Section D 
Cost of a pencil = Section D 
Now, converting to like fractions
Section D 
Clearly,
Section D 
Hence, the cost of pen is more than the cost of pencil.
Difference between their cost = Section D 
Section D 
Hence, the cost of pen is more than cost of pencil by Rs. Section D 


Q 34. Name the type of the triangle:
(i) ΔLMN with ∠L = 30°, ∠M = 70° and ∠N= 80°.
(ii) ΔDEF with ∠D= 90°.
(iii) ΔPQR such that PQ = QR = PR = 5 cm.
(iv) ΔXYZ with ∠Y= 90° and XY = YZ.

(i) Scalene triangle. Because none of the angles are equal, none of the sides will also be equal. Hence, it is a scalene triangle.
(ii) Right-angled triangle. Because the given angle is 90°, it is a right-angled triangle.
(iii) Equilateral triangle. Because all the sides of the given triangle are equal, it is an equilateral triangle.
(iv) Isosceles right-angled triangle. Since two sides are equal (XY = YZ) and one angle is 90°, it is an isosceles right-angled triangle.


Q 35. Simplify: 16 - [5 - 2 + {7 of 2 - (6 ÷ 3 × 2 - 1 + 3)}]

16 - [5 - 2 + {7 of 2 - (2 × 2 - 1 + 3)}]
= 16 - [5 - 2 + {7 of 2 - (4 - 1 + 3)}]
= 16 - [5 - 2 + {7 of 2 - 6}
= 16 - [5 - 2 + {8}]
= 16 - 11
= 5


Q 36. Draw a rough figure and label the following statements:
(a) Line l contains point A but not B
(b) Lines p and q intersect at point o
(c) Rays PQ and QR meet to form angle PQR

a. Line l contains point A but not B
Section D 
b. Lines p and q intersect at point O
Section D 
c. Rays PQ and QR meet to form angle PQR
Section D 


Q 37. Subtract the sum of Section D  from the sum of Section D 

Adding Section D 
Section D 
LCM of 3, 9 = 9
Section D 
= 62/9
We also have
Section D 
LCM of 6, 9 = (2 × 3 × 3) = 18
Section D 
= 179/18
Thus,
Section D 
= 55/18
Section D  

The document Sample Paper 1 - Term 1 Mathematics, Class 6 is a part of the Class 6 Course Class 6 All Subjects (Old NCERT).
All you need of Class 6 at this link: Class 6

FAQs on Sample Paper 1 - Term 1 Mathematics, Class 6

1. How do I solve problems on whole numbers and operations for Class 6 Term 1 maths exam?
Ans. Whole number problems require mastering addition, subtraction, multiplication, and division with understanding of properties like commutative and associative laws. Focus on identifying which operation applies to word problems, practise mental maths strategies, and verify answers by reversing operations. Refer to flashcards and MCQ tests on EduRev to strengthen conceptual clarity before attempting sample papers.
2. What are the most important geometry concepts tested in Class 6 Term 1 mathematics sample papers?
Ans. Class 6 geometry emphasizes basic shapes, angles, lines, and symmetry-specifically understanding rays, line segments, angle measurement, and identifying 2D shapes. Students frequently encounter questions on classifying triangles, circles, and quadrilaterals. Practise identifying properties of each shape and their real-world applications through mind maps and visual worksheets to build strong foundational knowledge.
3. Why do I keep making mistakes with fractions and decimals in Class 6 maths assessments?
Ans. Common fraction and decimal errors include misaligning decimal points, incorrectly simplifying fractions, and confusing equivalent fractions. Students often forget that fractions represent parts of a whole. Regular practice with step-by-step examples, comparing fractions using common denominators, and converting between fractions and decimals strengthens accuracy. Use detailed notes and worksheets to identify your specific error patterns.
4. How should I approach data handling and basic statistics questions in CBSE Class 6 Term 1 exams?
Ans. Data handling involves interpreting tables, bar graphs, pictographs, and finding averages or modes. Begin by carefully reading all labels and axes in graphs, then extract exact values rather than estimating. Organize raw data systematically before answering. Practise with varied graph types through PPTs and visual worksheets to build confidence in interpreting real-world data sets accurately.
5. What tricks help me answer ratio and proportion problems correctly in Class 6 mathematics sample papers?
Ans. Ratio and proportion problems require identifying equivalent relationships between quantities. The key trick is converting word problems into fractional or ratio form, then cross-multiplying to solve proportions. Always check if quantities are in the same units before comparing. Practise scaling and scaling-down scenarios with flashcards and MCQ tests to internalize the concept rather than memorizing formulas.
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