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Class 3 Exam > Class 3 Notes > Mathematics for Class 3: NCERT > NCERT Solutions - Give And Take

NCERT Solutions for Class 3 Maths - Give And Take

Page No 30:

Ques 1: Try these on Kittu’s home:

(a) 10 less than 34 is __________.
(b) 53 − 20 = _________
(c) 11 more than 31 is ________.
(d) 11 less than 66 is _________.
(e) 62 + 13 = ________
(f) 23 less than 89 is ________.
(g) 10 and 40 more is ________.
(h) 9 added to 28 gives ________.
(i) The sum of 9 and 44 is ________.
(j) Reducing 98 by 34 gives ________.
(k) 4 and 37 more is ________.
(l) Take 35 away from 83.
We get _______.

Ans:

(a)

We will start from 34.
To find 10 less than 34, we will go 10 steps back or jump down one row.
When we jump 1 row down, we reach 24.
A jump from 34 to 24 is like taking 10 steps backwards from 34.

We can write it like this: 34 − 10 = 24

(b)

We will start from 53.
To subtract 20 from 53, we will jump 2 rows down.
When we jump 2 rows down, we reach 33.
A jump from 53 to 33 is like taking 20 steps backwards from 53.

We can write it like this: 53 − 20 = 33

(c)

We will start from 31.
To find 11 more than 31, we will jump 1 row up from 31 and take 1 step right to reach 42.
This is like taking 11 steps forward from 31.

We can write it like this: 31 + 10 = 41 41 +1 = 42
(d)

We will start from 66.
To find 11 less than 66, we will jump 1 row down from 66 and take 1 step left to reach 55.
This is like taking 11 steps backwards from 66.

We can write it like this: 66 − 10 = 56 56 − 1 = 55

(e)

We will start from 62.
To add 13 to 62, we will jump 1 row up from 62 and take 3 steps right to reach 75.
This is like taking 13 steps forward from 62.

We can write it like this: 62 + 10 = 72 72 + 3 = 75

(f)

We will start from 89.
To find 23 less than 66, we will jump 2 rows down from 89 and take 3 steps left to reach 66.
This is like taking 23 steps backwards from 89.

We can write it like this: 89 − 20 = 69 69 − 3 = 66

(g)

We will start from 10.
To add 40 to 10, we can jump 4 rows up from 10.
When we jump 4 rows up, we reach 50.
A jump from 10 to 50 is like taking 40 steps forward from 10.

We can write it like this: 10 + 40 = 50

(h)

We will start from 28.
To add 9 to 28, we will jump 1 row up from 28 and take 1 step left to reach 37.
This is like taking 9 steps forward from 28.

We can write it like this: 28 + 10 = 38, 38 − 1 = 37

(i)

We will start from 44.
To add 9 to 44, we will jump 1 row up from 44 and take 1 step left to reach 53.
This is like taking 9 steps forward from 44.

We can write it like this: 44 + 10 = 54, 54 − 1 = 53

(j)

We will start from 98.
To reduce 98 by 34, we will jump 3 rows down from 98 and take 4 steps left to reach 64.
This is like taking 34 steps backwards from 98.

We can write it like this: 98 − 30 = 68, 68 − 4 = 64

(k)

We will start from 4.
To add 37 to 4, we will jump 4 rows up from 4 and take 3 steps left to reach 41.
This is like taking 37 steps forward from 4.

We can write it like this: 4 + 40 = 44, 44 − 3 = 41

(l)

We will start from 83.
To take 35 from 83, we will jump 4 rows down and take 5 steps right to reach 48.
This is like taking 35 steps backwards from 83.

We can write it like this: 83 − 40 = 43, 43 + 5 = 48

Page No 34:

Ques 1: See if you can do the same with these sums.

Ans:

Page No 35:

Ques 1: Now work out the steps in your mind. Write the answers directily in the boxes.
33 + 42 =__
19 + 61 =__
__= 48 + 42
__= 33 + 27
__= 34 + 63
__= 53 + 64
55 + 25 =__
67 + 25 =__
72 + 56 =__

Ans:
33 + 42 = 75
19 + 61 = 80
90 = 48 + 42
60 = 33 + 27
97 = 34 + 63
117 = 53 + 64
55 + 25 = 80
67 + 25 = 92
72 + 56 = 128

Page No 40:

2: A shopkeeper Rafi had 153 candles. Paras gave him 237 more candles. How many candles does Rafi have now?

Ans: Number of candles with Rafi = 153
Number of candles given by Paras to Rafi = 237
Total number of candles with Rafi = 237 + 153 = 390