Physics Exam  >  Physics Notes  >  Basic Physics for IIT JAM  >  Gauss's Law|Electric field due to continuous charge distributions

Gauss's Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM PDF Download

Introduction
1. Gauss's law was suggested by Karl Frederich Gauss(1777-1855) who was German scientist and mathematician.
2. Gauss's law is basically the relation between the charge distribution producing the electrostatic field to the behavior of electrostatic field in space.
3. Gauss's law is based on the fact that flux through any closed surface is a measure of total amount of charge inside that surface and any charge outside that surface would not contribute anything to the total flux.
4. Before we look further to study Gauss's law in detail let's study electric field due to continuous charge distributions.
Electric field due to continous charge distributions
1. So far as in the previous chapter we have discussed force and field due to discrete charges.
2. We now assume that charges on a surface are located very close togather so that such a system of charges can be assumed to have continous distribution of charges.
3. In a system of closely spaced charges, total charge could be continously distributed along some line, over a surface or throughout a volume.
4. First divide the continous charge distribution into small elements containing Δq amount of charge as shown in fig 1
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM
5. Electric field at point A due to element carrying charge Δq is
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM                        (1)
6. where r is the distance of element under consideration from point A and rˆis the unit vector in the direction from charge element towards point A.
7. Total electric field at point A due to all such charge elements in charge distribution is
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM                        (2)
where index i refers to the ith charge element in the entire charge distribution.
8. Since the charge is distributed continuously over some region , the sum becomes integral. Hence total field at A within the limit Δq→0 is,
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM         (3)
and integration is done over the entire charge distribution.
9. If a charge q is uniformly distributed along a line of length L, the linear charge density λ is defined by λ=q/L                                (4)
and the unit of λ is Coulumb/meter(C/m). 
10. For charge distributed non-uniformly over a line, linear charge density is 
λ = dq/dL                                                         (5)
where dQ is the amount of charge in a small length element dL.
11. For a charge Q uniformly distributed over a surface of area A, the surface charge density σ is
σ = q/A                                                           (6)
and unit of surface charge density is C/m2. For non uniform charge distributed over a surface charge density is 
σ = dq/dA                                                       (7)
where dA is a small area element of charge dQ.
12. Similarly for uniform charge distributions volume charge density is 
ρ = q/V                                                            (8)
and for non uniform distribution of charges
ρ=dq/dV                                                          (9)
and unit of volume charge distribution is C/m3.
Gauss's Law
1. We already know about electric field lines and electric flux. Electric flux through a closed surface S is
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM                                               (10)
which is the number of field lines passing through surface S.
2. Statement of Gauss's Law
“ELectric flux through any surface enclosing charge is equal to q/ε0 , where q is the net charge enclosed by the surface” 
mathematically,
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM                                                  (11)

where qenc is the net charge enclosed by the surface and E is the total electric field at each point on the surface under consideration.
3. It is the net charge enclosed in the surface that matters in Gauss's law but the total flux of electric field Edepends also on the surface choosen not merely on the charge enclosed.
4. So if you have information about distribution of electric charge inside the surface you can find electric flux through that surface using Gauss's Law.
5. Again if you have information regarding electric fluxthrough any closed surface then total charge enclosed by that surface can also be easily calculated using Gauss's Law.
6. Surface on which Gauss's Law is applied is known as Gaussian surface which need not be a real surface.
7. Gaussian surface can be an imaginary geometrical surface which might be empty space or it could be partially or fully embedded in a solid body.
8. Again consider equation 11
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM                                                     
In left hand side of above equation E·da is scalar product of two vectors namely electric field vector E and area vector da. Area vector da is defined as the vector of magnitude |da| whose direction is that of outward normal to area element da. So,da=nˆda where nˆ is unit vector along outward normal to da. 
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM                                         (12)
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM
Figure 1
From above discussion we can conclude that,
(1) If both E and surface area da at each points are perpendicular to each other and has same magnitude at all points of the surface then vector E has same direction as that of area vector as shown below in the figure.
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM

Figure 2
since E is perpendicular to the surface 
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM
(2) If E is parallel to the surface as shown below in the figure
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM
Figure 3
Gauss`s Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM
and integral is also zero for zero value of electric field vector E at all points on the surface.

The document Gauss's Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM is a part of the Physics Course Basic Physics for IIT JAM.
All you need of Physics at this link: Physics
210 videos|156 docs|94 tests

FAQs on Gauss's Law-Electric field due to continuous charge distributions - Basic Physics for IIT JAM

1. What is Gauss's Law?
Ans. Gauss's Law is a fundamental principle in electromagnetism, which relates the electric field to the distribution of electric charges. It states that the total electric flux through any closed surface is equal to the total enclosed charge divided by the permittivity of the medium.
2. How is Gauss's Law used to calculate electric fields?
Ans. Gauss's Law provides a convenient method to calculate the electric field due to continuous charge distributions. By choosing a closed surface, called a Gaussian surface, that encloses the charges of interest, the electric flux through this surface can be calculated. Using Gauss's Law, the electric field can then be determined by dividing the total enclosed charge by the permittivity of the medium.
3. Can Gauss's Law be applied to point charges?
Ans. Yes, Gauss's Law can be applied to point charges. For a single point charge, the electric field can be calculated using a Gaussian surface in the form of a sphere centered around the charge. The electric flux through this surface will be proportional to the enclosed charge, allowing the electric field to be determined.
4. What are continuous charge distributions?
Ans. Continuous charge distributions refer to situations where the charge is spread out over a region instead of being concentrated at specific points. Examples of continuous charge distributions include charged wires, charged plates, or charged spheres. Gauss's Law can be used to calculate the electric field due to these distributions by choosing an appropriate Gaussian surface.
5. How does Gauss's Law relate to the concept of electric flux?
Ans. Gauss's Law relates the concept of electric flux to the distribution of electric charges. Electric flux is a measure of the electric field passing through a closed surface. Gauss's Law states that the total electric flux through any closed surface is equal to the total enclosed charge divided by the permittivity of the medium. This allows us to determine the electric field by analyzing the electric flux through a chosen Gaussian surface.
210 videos|156 docs|94 tests
Download as PDF
Explore Courses for Physics exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Related Searches

past year papers

,

study material

,

Exam

,

mock tests for examination

,

MCQs

,

Objective type Questions

,

Important questions

,

ppt

,

Viva Questions

,

Extra Questions

,

Free

,

Semester Notes

,

Gauss's Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM

,

shortcuts and tricks

,

Gauss's Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM

,

pdf

,

Summary

,

video lectures

,

practice quizzes

,

Gauss's Law|Electric field due to continuous charge distributions | Basic Physics for IIT JAM

,

Previous Year Questions with Solutions

,

Sample Paper

;