NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement

# NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement | Physics Class 11 PDF Download

## 2024

Q1: In a vernier callipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If  1MSD represents  0.1mm, the vernier constant (in cm) is:       [2024]
(a)
(b)
(c) 00N
(d) 10(N + 1)
Ans:
(b)
V.C = MSD $−$ VSD ..... (1)
given : (N + 1)$VSD=$N MSD
..... (2)
From (1) and (2)

Q2: The quantities which have the same dimensions as those of solid angle are:      [2024]
(a) strain and angle
(b) stress and angle
(c) strain and arc
(d) angular speed and stress
Ans:
(a)
Solid angle  has dimensions
Strain $=$ has dimensions
Angle measured in radians is also dimensionless

Q3: A force defined by  acts on a particle at a given time t. The factor which is dimensionless, if α and β are constants, is:      [2024]
(a) βt / α
(b) αt / β
(c) αβt
(d) αβ / t
Ans:
(b)
From principle of homogeneity

## 2023

Q1: A metal wire has mass (0.4 ± 0.002) g, radius (0.3 ± 0.001) mm and length (5 ± 0.02) cm. The maximum possible percentage error in the measurement of density will nearly be     [2023]
(a) 1.2%
(b) 1.3%
(c) 1.6%
(d) 1.4%
Ans:
(c)

Question for NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement
Try yourself:Q2: The errors in the measurement which arise due to unpredictable fluctuations in temperature and voltage supply are      [2023]

Q3:  The diameter of a spherical bob, when measured with vernier callipers yielded the following values :   3.33 cm,3.32 cm,3.34 cm,3.33 cm and  3.32 cm. The mean diameter to appropriate significant figures is :
(a) 3.328 cm
(b) 3.3 cm
(c) 3.33 cm
(d) 3.32 cm
Ans:
(c)

Q4: The mechanical quantity, which has dimensions of reciprocal of mass (M−1) is :    [2023]
(a) angular momentum
(b) coefficient of thermal conductivity
(c) torque
(d) gravitational constant
Ans:
(d)

## 2022

Q1: The physical quantity that has the same dimensional formula as pressure is       [2022]
(a) Coefficient of viscosity
(b) Force
(c) Momentum
(d) Young's modulus of elasticity
Ans:
(d)

Q2: The percentage error in the measurement of g is : (Given that  , s)
(a) 7%
(b) 2%
(c) 5%
(d) 3%
Ans:
(d)

Q3: The dimensions [MLT–2A–2 ] belong to the              [2022]
(a) Self-inductance
(b) Magnetic permeability
(c) Electric permittivity
(d) Magnetic flux

Ans: (b)
Solution:
The dimensional formula of magnetic permeability is [MLT–2A–2 ]

Q4: The area of a rectangular field (in m) of length 55.3 m and breadth 25 m after rounding off the value for correct significant digits is                           [2022]
(a) 1382

(b) 1382.5
(c) 14 * 10
(d) 138 * 10
1
Ans: (c)
Solution:

= 55.3 × 25 m2
= 1382.5 m2
= 14 × 102 m2
(Rounding off of two significant figures)

Q5: Match List-I with List-II

Choose the correct answer from the options given below                 [2022]
(a) (a) - (ii), (b) - (iv), (c) - (i), (d) - (iii)

(b) (a) - (ii), (b) - (iv), (c) - (iii), (d) - (i)

(c) (a) - (iv), (b) - (ii), (c) - (i), (d) - (iii)

(d) (a) - (ii), (b) - (i), (c) - (iv), (d) - (iii)
Ans: (a)
Solution:

Question for NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement
Try yourself:Q6: Plane angle and solid angle have       [2022]

## 2021

Q1: A Screw Guage gives the following readings when used to measure the diameter of a wire.
Main scale reading = 0.0 mm
Circular scale reading = 52 divisions
Given that: 1 mm on the main scale corresponds to 100 divisions of the circular scale.
The diameter of the wire from the above data is:
[2021]
(a) 0.026 cm
(b) 0.005 cm
(c) 0.52 cm
(d) 0.052 cm
Ans:
(d)
Solution: Diameter of wire,

Q2: If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.    [2021]
(a) [F][A][T-1]
(b) [F][A-1][T]
(c) [F][A][T]
(d) [F][A][T2]
Ans:
(d)
Solution:

Q3: If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of :    [2021]
(a) [M] [L0] [T0]
(b) [M2] [L–2] [T–1]
(c) [M2] [L–1] [T0]
(d) [M] [L–1] [T–1]
Ans:
(c)
Solution:

E = energy = [ML2T–2]
G = Gravitational constant = [M–1L3T–2]
So,
E/G = [E]/[G]
= ML2T–2/M–1L3T–2
= [M2L-1T0]

## 2020

Q1: A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale.   [2020]
The pitch of the screw gauge is :
(a) 0.25 mm
(b) 0.5 mm
(c) 1.0 mm
(d) 0.01 mm
Ans:
(b)
Least count of screw gauge =

Q2: Taking into account of the significant figures, what is the value of 9.99 m-0.0099 m?    [2020]
(a) 9.980 m
(b) 9.9 m
(c) 9.9801 m
(d) 9.98 m

Ans: (d)

As per rule
least no. of place in decimal portion of any number 9.98

Q3: Dimensions of stress are :   [2020]
(a) [ML2T-2]
(b) ML0T-2]
(c) ML-1T-2]
(d) MLT-2]
Ans:
(c)

Q4: The energy required to break one bond in DNA is 10-20 J. This value in eV is nearly :   [2020]
(a) 0.6
(b) 0.06
(c) 0.006
(d) 6
Ans:
(b)

## 2019

Q1: In an experiment, the percentage of error occurred in the measurement of physical quantities A, B, C and D are 1%, 2%, 3% and 4% respectively. Then the maximum percentage of error in the measurement X, where  will be     [2019]
(a)
(b) 16 %
(c) -10 %
(d) 10 %
Ans:
(b)
Given

= 2% + 1%+ 1%+ 12%= 16%

## 2018

Q1: A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of – 0.004 cm, the correct diameter of the ball is :-    [2018]
(a) 0.521 cm
(b) 0.525 cm
(c) 0.053 cm
(d) 0.529 cm

Ans: (d)
Solution:
= MSR + VSR × LC + zero error
= 0.5 cm + 25 × 0.001 cm + 0.004 cm
= 0.529 cm

## 2017

Q1: A physical quantity of the dimensions of length that can be formed out of  is velocity of light, G is universal constant of gravitation and e is charge] :-    [2017]

(a)
(b)
(c)
(d)
Ans: (d)
Solution:

## 2016

Q1: Planck's constant (h), speed of light in vacuum (c) and Newton's gravitional constant (G) are three fundamental constants. Which of the following combinations of these has the dimension of length ?           [2016]
(a)
(b)
(c)
(d)
Ans:
(a)
According to question,
$∝$ hp cq Gr
[M0LT0] = [ML2T-1]p [LT-1]q [M-1L3T-2]r
Equating power both sides, we get
p - r = 0        ......(1)
2p + q + 3r = 1        ......(2)
- p - q - 2r = 0        ......(3)
Solving equation (1), (2), (3), we get

## 2015

Q1: If dimensions of critical velocity vc of a liquid flowing through a tube are expressed as  where η,ρ and r are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by
(a) 1, −1, −1
(b) 1, 1, 1
(c) 1, −1, −1
(d) −1, −1, 1                  [2015]
Ans:
(c)

Put dimensions of various quantities,
[M0LT-1] = [ML-1T-1]x [ML-3T0]y [M0LT0]z
= [Mx + y L- x - 3y + z T- x]
Equating power both sides, we get
x + y = 0;
- x - 3y + z = 1;
- x = - 1
On solving, we get
x = 1, y = -1, z = -1

Question for NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement
Try yourself:Q2: If energy (E), velocity (V) and time (T) are chosen as the fundamental quantities, the dimensional formula of surface tension will be:    [2015]

## 2014

Q1: If force (F), velocity (V) and time(T) are taken as fundamental units, then the dimensions of mass are:    [2014]
(a) [F V−1 T−1]
(b) [F V−1 T]
(c) [F V T−1]
(d) [F V T−2]
Ans:
(b)
Solution:
The document NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement | Physics Class 11 is a part of the NEET Course Physics Class 11.
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## Physics Class 11

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## FAQs on NEET Previous Year Questions (2014-2024): Physical World, Units & Measurement - Physics Class 11

 1. What is the concept of physical world in the context of NEET exam?
Ans. The concept of physical world in the NEET exam refers to the study of the basic principles and laws that govern the physical universe, including topics such as motion, energy, and forces.
 2. How are units important in the field of measurements for the NEET exam?
Ans. Units are crucial in measurements for the NEET exam as they provide a standard of comparison and ensure that measurements are accurate and consistent across different experiments and studies.
 3. What are the common measurement units used in the NEET exam for physical quantities?
Ans. Common measurement units used in the NEET exam for physical quantities include meters for length, kilograms for mass, seconds for time, and Newtons for force, among others.
 4. How does understanding the physical world and units help in solving NEET exam questions?
Ans. Understanding the physical world and units is essential for solving NEET exam questions as it enables students to apply the correct principles and formulas to solve problems accurately and efficiently.
 5. Why is it important for NEET aspirants to have a strong grasp of the concepts related to physical world, units, and measurements?
Ans. Having a strong grasp of these concepts is crucial for NEET aspirants as questions related to physical world, units, and measurements are frequently asked in the exam, and a good understanding of these topics can significantly improve performance and scores.

## Physics Class 11

102 videos|411 docs|121 tests

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