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NEET Previous Year Questions (2014-2025): Electric Charges & Fields

2025

Q1: Two identical charged conducting spheres A and B have their centres separated by a certain distance. Charge on each sphere is q and the force of repulsion between them is F. A third identical uncharged conducting sphere is brought in contact with sphere A first and then with B and finally removed from both. New force of repulsion between spheres A and B (Radii of A and B are negligible compared to the distance of separation so that for calculating force between them they can be considered as point charges) is best given as:    [NEET 2025]
(a) F/2 
(b) 3F/8
(c) 3F/5
(d) 2F/3

2024

Q1: A thin spherical shell is charged by some source. The potential difference between the two points C and P (in V) shown in the figure is:            [NEET 2024]
2024(Take 2024 SI Units)
(a) 3 x 105
(b) 1 x 105
(c) 0.5 x 105
(d) Zero

Q2: Two identical rectangular plane sheet A and B each of surface charge density ε0Cm-2 are placed parallel to each other as shown in figure. The electric field at the mid point P will be:           [NEET 2024]

2024(a) 2 NC-1
(b) 1 NC-1
(c) 0.5 NC-1
(d) zero

Q3: Match List-I with List-II:          [NEET 2024]
2024(Here symbols have their usual meaning and R is the radius of the thin shell) 
Choose the correct answer from the options given below: 
(a) A-IV, B-III, C-I, D-II
(b) A-I, B-II, C-III, D-IV
(c) A-IV, B-III, C-II, D-I
(d) A-I, B-III, C-II, D-IV

Q4: A particle of mass m and charge q is placed in a uniform electric field E at t = 0 s. The kinetic energy of the particle after time t is:
(a) Eqm / t
(b) E²q²t² / 2m
(c) 2E²t² / qm
(d) Eq²m / 2t²         [NEET 2024]

Q5: A metal cube of a side 5 cm is charged with 6 μC. The surface charge density on the cube is:          [NEET 2024]
(a) 0.125 × 10⁻³ C m⁻²
(b) 0.25 × 10⁻³ C m⁻²
(c) 4 × 10⁻³ C m⁻²
(d) 0.4 × 10⁻³ C m⁻²

2023

Q1:  If 2023 over a surface, then        [NEET 2023]                                                                                                                                                            
(a) The number of flux lines entering the surface must be equal to the number of flux lines leaving it
(b) The magnitude of the electric field on the surface is constant
(c) All the charges must necessarily be inside the surface
(d) The electric field inside the surface is necessarily uniform

MULTIPLE CHOICE QUESTION

Try yourself: Q3: An electric dipole is placed as shown in the figure.                                                                                                                                                                            
2023
The electric potential at point P due to the dipole is (ε0 = permittivity of free space and 2023

 

A

(3/8) qK × 10V

B

(5/8) qK × 10V

C

(8/5) qK × 10V

D

(8/3) qK × 10V

Q2: An electric dipole is placed at an angle of 30° with an electric field of intensity 2 × 10⁵ NC-1. It experiences a torque equal to 4 N-m. If the dipole length is 2 cm, calculate the magnitude of the charge on the dipole: [NEET 2023]
(a) 2 mC
(b) 8 mC
(c) 6 mC
(d) 4 mC

Q3: According to Gauss's law in electrostatics, the electric flux through a closed surface depends on:      [NEET 2023]
(a) the area of the surface 
(b) the quantity of charges enclosed by the surface 
(c) the shape of the surface 
(d) the volume enclosed by the surface 

Q4: A charge Q μC is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI units):     [NEET 2023]
(a) Q / ε₀ × 10⁻⁶
(b) 2Q / 3ε₀ × 10⁻³
(c) Q / 6ε₀ × 10⁻³
(d) Q / 6ε₀ × 10⁻⁶

2022

Q1: Two point charges -q and +q are placed at a distance of L, as shown in the figure 
2022

The magnitude of electric field intensity at a distance R(R >>L) varies as:                                                                                                                                  
(a) 1/R3

(b) 1/R4
(c) 1/R6
(d) 1/R2

2021

Q1: Polar molecules are the molecules:                                                                                                                                                                                                                
(a) acquire a dipole moment only when the magnetic field is absent.
(b) having a permanent electric dipole moment.
(c) having zero dipole moment.
(d) acquire a dipole moment only in the presence of an electric field due to displacement of charges.

Q2: A dipole is placed in an electric field as shown. In which direction will it move?                                                                                                           
2021
(a) towards the left as its potential energy will decrease.
(b) towards the right as its potential energy will increase.
(c) towards the left as its potential energy will increase.
(d) towards the right as its potential energy will decrease.

2020

Q1: A short electric dipole has a dipole moment of 16×10-9 C m. The electric potential due to the dipole at a point at a distance of 0.6 m from the center of the dipole, situated on a line making an angle of 60° with the dipole axis is:                                                                                  
2020
(a)  400 V 
(b) Zero 
(c) 50 V 
(d) 200 V

MULTIPLE CHOICE QUESTION

Try yourself: Q2: The acceleration of an electron due to the mutual attraction between the electron and a proton when they are 1.6 Å apart is, (me ≈ 9 × 10−31 kg, e = 1.6 × 10−19 C) 2020

A

1024 m/s2

B

1023 m/s2

C

1025 m/s2

D

1022 m/s2

Q2: A spherical conductor of radius 10 cm has a charge of 3.2 × 10-7 C distributed uniformly. What is the magnitude of electric field at a point 15 cm from the centre of the sphere? 2020

(a) 1.28 × 105 N/C
(b) 1.28 × 106 N/C
(c) 1.28 × 107 N/C
(d) 1.28 × 104 N/C

Hence, correct option is (a).

Q3: The electric field at a point on the equatorial plane at a distance r from the centre of a dipole having dipole moment r P is given by (r >> separation of two charges forming the dipole, ε 0 = permittivity of free space)
(a) 2020

(b) 2020

(c) 2020

(d) 2020

2019

Q1: A hollow metal sphere of radius R is uniformly charged. The electric field is due to the sphere at a distance r from the 
center.                                                                                                                                                                                                                                                                                           
(a) Increases as r increases for both r < R and r > R
(b) Zero as r increases for r < R, decreases as r increases for r > R
(c) Zero as r increases for r < R, increases as r increases for r > R
(d) 
Decreases as r increases for both r < R and r > R

Q2: Two parallel infinite line charges with linear charge densities +λ C/m and λl C/m are placed at a distance of 2R in free space. What is the electric field mid-way between the two line charges?                                                                                                                                                                 
(a) Zero
(b)2019
(c)2019
(d)2019

Q3: Two point charges A and B, having charges +Q and -Q respectively, are placed at a certain distance apart, and the force acting between them is F. If 25% charge of A is transferred to B, then the force between the charges becomes :                                                          
(a) F
(b) 9F/16
(c) 16F/9
(d) 4F/3

MULTIPLE CHOICE QUESTION

Try yourself: Q4:  A sphere encloses an electric dipole with charge ± 3 × 10−6 C. What is the total electric flux across the sphere?

A

3 × 106 N-m2 /C

B

− 3 × 10−6 N-m2 /C

C

zero

D

6 × 10−6 N-m2 /C

2018

Q1: An electron falls from rest through a vertical distance h in a uniform and vertically upward-directed electric field E. The direction of the electrical field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest through the same vertical distance h. The time fall of the electron, in comparison to the time fall of the proton is:                                                                                                  
(a) Smaller
(b) 5 times greater
(c) 10 times greater
(d) equal

Q2: A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field2018Due to the force2018its velocity increases from 0 to 6 m/s in one-second duration. At that instant, the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively:  
(a) 2 m/s, 4 m/s
(b) 1 m/s, 3 m/s
(c) 1 m/s, 3.5 m/s
(d) 1.5 m/s, 3 m/s

2017

Q1: Suppose the charge of a proton and an electron differ slightly. One of them is - e and the other is (e + ∆e). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero, then ∆e is of the order [Given mass of hydrogen, mh = 1.67 × 10-27 kg] 
(a) 10-20 C
(b) 10-23 C
(c) 10 -37C
(d) 10 -47C

2016

Q1: Two identical charged spheres suspended from a common point by two mass-less strings of lengths ℓ are initially at a distance d  (d << ℓ) apart because of their mutual repulsion. The charges begin to leak from both spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres, as:                              
(a) v ∝ x-1
(b) v ∝ x1/2
(c) v ∝ x
(d) v ∝ x-1/2

Q2: An electric dipole is placed at an angle of 30° with an electric field of intensity 2 × 105 N C-1. It experiences a torque equal to 4 N m. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.  
(a) 8 mC
(b) 6 mC
(c) 4 mC
(d) 2 mC

2015

Q1:  The electric field in a certain region is acting radially outward and is given by E = Ar. A charge contained in a sphere of radius = a centered at the origin of the field will be given by:                                                                                                                                                                                       
(a)2015
(b)2015
(c)2015
(d)2015

The document NEET Previous Year Questions (2014-2025): Electric Charges & Fields is a part of the NEET Course Physics Class 12.
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FAQs on NEET Previous Year Questions (2014-2025): Electric Charges & Fields

1. What are the key differences between electric field and electric potential in NEET questions?
Ans. Electric field measures the force per unit charge at a point and is a vector quantity, while electric potential measures energy per unit charge and is scalar. Field direction shows where positive charges move; potential tells you the energy work required. Both concepts frequently appear in NEET previous year questions on charges and fields, requiring clear distinction for accurate problem-solving.
2. How do I solve problems on Coulomb's law and electrostatic force between charged particles?
Ans. Coulomb's law states that electrostatic force between two point charges is directly proportional to their product and inversely proportional to the square of distance between them. Use F = kq₁q₂/r² to find magnitude, then apply vector principles for direction. NEET previous year questions often test force combinations and superposition principle when multiple charges interact simultaneously.
3. What's the fastest way to identify if a surface is an equipotential in electric field problems?
Ans. An equipotential surface has constant electric potential throughout; no work is done moving a charge along it. Electric field lines always meet equipotential surfaces at right angles. Conductors in electrostatic equilibrium are equipotential surfaces. Recognising this property helps solve NEET exam questions faster since it eliminates impossible field configurations and simplifies potential calculations significantly.
4. Why do electric field lines never cross each other, and how does this concept help in NEET exams?
Ans. If field lines crossed, the electric field at that point would have two different directions simultaneously, which is physically impossible. Each location has only one field value. Understanding this prevents common mistakes in NEET questions involving field mapping and helps students visualise charge configurations correctly. This conceptual clarity strengthens solutions for complex multi-charge scenarios from previous year papers.
5. How do continuous charge distributions differ from point charges in electric field calculations?
Ans. Point charges use Coulomb's law directly; continuous distributions (lines, surfaces, volumes) require integration of infinitesimal charge elements. Linear charge density (λ), surface charge density (σ), and volume charge density (ρ) replace point charge values. NEET previous year questions test both approaches-mastering integration techniques for uniform and non-uniform distributions ensures confident problem-solving across varied charge geometry scenarios.
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