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Worksheet Solutions: Fields And Fences - 1

Q: Answer the following Questions.

(i) Shyam grows rice in his farm. Can you help him to find out the length of boundary from the picture given below?
Q: Answer the following Questions.Ans: 22 cm

(ii) Find how much wire is needed to fence the following fields.
(a)
Q: Answer the following Questions.
(b)
Q: Answer the following Questions.
Ans: 
(a) 35 cm
(b) 45 cm

(iii) In the picture given below of a field find the side with longest side.
Q: Answer the following Questions.Ans: 40 cm

(iv) Find the length of the boundary of the following figures if each sq. is 1 sq. cm.
(a) 
Q: Answer the following Questions.

(b) 
Q: Answer the following Questions.
Ans: 
(a) 18 cm
(b) 18 cm

(v) Find the length of boundary in the picture below.
Q: Answer the following Questions.Ans: 28 cm

(vi) Draw and shade a rectangle which covers 40 squares on the given graph paper.
Q: Answer the following Questions.Ans: Students draw themselves.

(vii) Find out the length of the boundary of the hexagon.
Q: Answer the following Questions.Ans: 78 cm

(viii) On the given graph draw two figures which covers the same number of squares.
Q: Answer the following Questions.Ans: Students do this themselves with any shape of their choice.

(ix) Java runs around the outer circle and Maya runs around the inner circle. Can you explain why Java runs more distance than Maya?
Q: Answer the following Questions.Ans: Java runs more distance than Maya because the outer boundary is bigger than the inner boundary.

(x) Find the length of the boundary of this form house.
Q: Answer the following Questions.Ans: 252 m

(xi) Mohan runs around the rectangular field 4 times a day. How much distance do he runs in a day?
Q: Answer the following Questions.Ans: 120 m

(xii) How will you divide this picture into 4 equal pieces. How many number of squares will be there in each piece.
Q: Answer the following Questions.Ans: Each piece will have 5 squares.

(xiii) If the total length of the boundary is 98 cm and length of two sides are 30 cm and 48 cm. Find the length of the third side.
Q: Answer the following Questions.Ans: 20 cm

(xiv) A farmer went to market and bought a fencing wire of 150 m. He wants to put it twice around his form. Is this wire enough?
Q: Answer the following Questions.Ans: This wire is 10 m short from the required wire.

(xv) What will be length of the wire required to fence the triangular field with side 15 m each?
Ans: 45 m

(xvi) Find the length of the boundary of the following figures 
(a) 
Q: Answer the following Questions.
(b) 
Q: Answer the following Questions.
(c) 
Q: Answer the following Questions.
Ans: 
(a) 43 cm
(b) 31 cm
(c) 32 cm

(xvii) Find the length of the boundary with side 5 cm each in the picture below.
Q: Answer the following Questions.Ans: 50 cm

(xviii) Find out which figure will need the longest wire to fence it:
(a)
Q: Answer the following Questions.
(b)
Q: Answer the following Questions.
(c) 
Q: Answer the following Questions.
(d) 
Q: Answer the following Questions.
Ans: Figure B will need longest wire of 50 cm

(xix) Find the length of the wire required to fence the triangular park shown in the picture.
Q: Answer the following Questions.Ans: 81 m

(xx) Draw a shape which covers 24 squares on the graph paper.
Q: Answer the following Questions.Ans: Students can draw any figure - regular or irregular.

The document Worksheet Solutions: Fields And Fences - 1 is a part of the Class 4 Course Worksheets with solutions for Class 4.
All you need of Class 4 at this link: Class 4

FAQs on Worksheet Solutions: Fields And Fences - 1

1. How do you calculate the perimeter of a field with irregular boundaries?
Ans. Perimeter is the total distance around a closed shape, found by adding all outer edges together. For irregular fields, measure each side length and sum them up. If the field has curved boundaries, you'll need to estimate using smaller straight segments or use a measuring tape along the actual fence line for accuracy.
2. What's the difference between area and perimeter when measuring a fenced field?
Ans. Perimeter measures the distance around a field's boundary (how much fencing you need), while area measures the space inside (how much land you have). A field might have a small perimeter but large area, or vice versa. Understanding both helps in planning fencing materials and land usage correctly for CBSE Class 4 geometry problems.
3. How do you find the cost of fencing a rectangular field in these worksheet problems?
Ans. First, calculate the perimeter using the formula: Perimeter = 2 × (length + width). Then multiply the perimeter by the cost per unit length. For example, if perimeter is 100 metres and fencing costs ₹50 per metre, total cost is ₹5,000. Worksheet solutions show this step-by-step approach clearly.
4. Why do some fields need different amounts of fencing even though they look the same size?
Ans. Fields with different shapes have different perimeters despite having equal areas. A long, narrow field requires more fencing than a square field of the same area because perimeter depends on how the dimensions are arranged, not just the total space. This is a common misconception in Class 4 geometry worksheets.
5. What measurement units should I use when solving fields and fences problems for my exam?
Ans. Use consistent units throughout-metres for length and cost calculations in rupees. Never mix units like centimetres and metres in the same problem. Always check worksheet solutions to see which units are specified, as exam answers require proper unit notation for full marks in CBSE assessments.
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