Anything that exhibits inertia is known as matter. The quantity of matter is its mass. Example: chalk table. In simple language, anything which has mass and occupies space is called matter.
Matter can exist in three physical states viz. solid, liquid, and gas.
The constituent particles of matter in these three states can be represented as shown in the figure:
A Representation of the Solid, Liquid, and Gas States
Because of such an arrangement of particles, different states of matter exhibit the following characteristics:
Note: These three states of matter are interconvertible by changing the conditions of temperature and pressure.


This classification of matter is based upon the chemical composition of various substances. According to this matter can be further divided into two types, pure substance, and mixture.
Mixtures are also of two types, homogenous mixtures and heterogeneous mixtures.
Classification of Matter
➢ Elements


➢ Mixture
There are two types of mixture:
(a) Homogeneous
(b) Heterogenous
Table: Comparison between Homogeneous and Heterogeneous mixtures
Table: Comparison between Compound and Mixtures
Try yourself: Which one of the following is not an element?
Try yourself: The most abundant element on the earth’s crust is:
Try yourself: Which one of the following is not a mixture?
Try yourself: Which one if the following is not a metalloid?
Many times in the study of chemistry, one has to deal with experimental data as well as theoretical calculations.
There are meaningful ways to handle the numbers conveniently and present the data realistically with certainty to the extent possible like:
➢ Scientific Notation
Scientific Notation
Example: We can write 232.508 as 2.32508 × 102 in scientific notation. Similarly, 0.00016 can be written as 1.6 × 10-4.
Thus, we can write 232.508 as 2.32508 × 102 in scientific notation. Note that while writing it, the decimal had to be moved to the left by two places and the same is the exponent (2) of 10 in the scientific notation.
Similarly, 0.00016 can be written as 1.6 × 10-4. Here the decimal has to be moved four places to the right and (- 4) is the exponent in the scientific notation.
➢ Multiplication and Division for Exponential Numbers

➢ Addition and Subtraction for Exponential Numbers
Example: If the true value for a result is 2.00 g.
(a) Student 'A' takes two measurements and reports the results as 1.95 g and 1.93 g.
These values are precise as they are close to each other but are not accurate.
(b) Another student repeats the experiment and obtains 1.94 g and 2.05 g as the results for two measurements.
These observations are neither precise nor accurate.
(c) When a third student repeats these measurements and reports 2.01g and 1.99 g as the result.
These values are both precise and accurate.
Examples:
Q.1. Which of the following options is not correct?
(a) 8008 = 8.008 x 103
(b) 208 = 3
(c) 5000 = 5.0 x 103
(d) 2.0034 = 4
Ans: (d)
Solution:
2.0034 = 4
Q.2. Exponential notation in which any number can be represented in the form, Nx 10n here N is termed as
(a) non -digit term
(b) digit term
(c) numeral
(d) base term
Ans: (b)
Solution:
In exponential notation N × 10n, N is a number called digit term which varies between 1.000 and 9.000....
Q.3. In scientific notation,0.00016 can be written as
(a) 1.6 x 10-4
(b) 1.6 x 10-3
(c) 1.6 x 10-2
(d) 1.6 x 10-1
Ans: (a)
Solution:
0.00016 can be written as 1.6 × 10-4 in scientific notation
4. Addition of 6.65 x 104 and 8.95 x 103, in terms of scientific notation will be
(a) 7.545 104
(b) 75.45 10 3
(c) 754.5 102
(d) 75.45 100
Ans: (a)
Solution:
6.65 × 104 + 8.95 × 103
= (6.65 + 0.895) × 104 = 7.545 × 104
Q.5. The substraction of two numbers
2.5 x 10-2 -4.8 x 10 -3 gives the following value.
(a) 2.02 x 10-3
(b) 2.02 x 10-2
(c) 2.02 x 10-1
(d) 2.02 x 100
Ans: (b)
Solution:
2.5 × 10-2 - 4.8 × 10-3
= 2.5 × 10-2 - (0.48 × 10-2) = 2.02 × 10-2
Q.6. A refers to the closeness of various measurements for the same quantity. B is the agreement of a particular value to the true value of the result. A and B respective are
(a) A → Significant figures, B → accuracy
(b) A → accuracy, B → precision
(c) A → Precision, B → accuracy
(d) A → significant figures, → precision
Ans: (c)
Q.7. Which of the following statement is/are true?
(a) Every experimental measurement has zero amount of uncertainty associated with it
(b) One would always like the result to be precise and accurate
(c) Precision and accuracy are often referred to while we talk about the measurement
(d) Both (b) and (c)
Ans: (d)
Solution: Every experimental measurement has some amount of uncertainty associated with it.
Try yourself: Which of the following statement is correct?
Try yourself: Two students X and Y report the weight of the same substance as 5.0g and 5.00g respectively. Which of the following statements is correct?

Example: How unit of work / energy i.e. joule, in S.I. system is related with unit erg in C.G.S system?
Dimension of work = force x displacement = MLT-2 × L = ML2T-2
1 joule = 1 kg (1 metre)2 × (1sec)-2
⇒ 1 × Kg × 1000 gm/1Kg × [1 metre × 100 cm/1 metre] × [1 sec]-2
⇒ 100 gm × (100)2 × 1 em2 × (1 sec)-2
⇒ 1000 × 10000 × 1 gm × 1 cm2 × 1 sec-1
⇒ 1 joule = 107 erg
Similarly, we can deduce other conversion factor for other quantity in different unit by the dimensional analysis method.
Another interesting example is the conversion of liter - atmosphere to joule (the SI unit of energy) by multiplying with two successive unit factors.
Thus,
1 L atm × (10-3 m3/1L) × 101.325 Pa/1 atm
= 101. 325 Pa M3
Knowing that Pa = N/m2,
we can write
101.325 Pa m3 = 101.325 (N/m2) m3
= 101.325 N m = 101.325 J
Hence, 1 L atm = 101.325 J
➢ Mass and Weight
➢ Volume
Some Volume Measuring Devices
➢ Density
Relationship between Density, Mass and Volume
➢ Temperature
There are three common scales to measure temperature:
1. °C (degree Celsius)
2. °F (degree Fahrenheit)
3. K (kelvin)
Here, K is the SI unit.
Conversion Formulas:
Note: Temperature below 0 °C (i.e. negative values) are possible in the Celsius scale but in the Kelvin scale, the negative temperature is not possible.
Temperature Kelvin scale
Example 1. What is the mass of 1 L of mercury in grams and in kilograms if the density of liquid mercury is 13.6 g cm-3?
Solution. We know the relationship, 1 L = 1000 cm3 and
Also, density = mass/volume
We can write, mass = (volume) (density)
Therefore, the mass of 1 L of mercury is equal to
The mass in kilograms can be calculated as
(Remember,
are conversion factors with which we have to multiply for getting our answer in appropriate units).
Example 2. How unit of velocity i.e. kilometer/hour is related to unit meter/second.
Solution. We know the relationship, velocity = total displacement/total time

Prefixes in S.I. system
Name | Symbol | Quantity |
yotta | Y | 1024 |
zetta | Z | 1021 |
exa | E | 1018 |
peta | P | 1015 |
tera | T | 1012 |
giga | G | 109 |
mega | M | 106 |
kilo | k | 103 |
hecto | h | 102 |
deca | da | 10 |
deci | d | 10-1 |
centi | c | 10-2 |
miIIi | m | 10-3 |
micro | M | 10-6 |
nano | n | 10-9 |
pico | P | 10-12 |
fempto | f | 10-15 |
atto | a | 10-18 |
zepto | z | 10-21 |
yocto | y | 10-24 |
Try Yourself!
Try yourself: The temperature at which both the Celsius and Fathrenheit scales will have the same reading is
Try yourself: Pressure is determined as force per unit area of surface. The SI unit of pressure, pascal is as shown below:
1Pa = 1Nm-2
If the mass of air at sea level is 1034 g cm-2, the pressure in pascal is
Try yourself: The prefix femto stands for
Try yourself: N kg-1 is the unit of
Try yourself: Which of the following is correct?
Try yourself: The units, nanometer, Fermi, Angstrom and attometre, Arrangement in decreasing order are expressed as
Try yourself: Dimensions of pressure are same as that of