Class 10 Exam  >  Class 10 Notes  >  RD Sharma Solutions for Class 10 Mathematics  >  Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8)

Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics PDF Download

Page No 3.29

Q.8. Solve the following systems of equations graphically:
2x + 3y = 4
x − y + 3 = 0

Ans. The given equations are:
2x + 3y = 4   ...(i)
x − y + 3 = 0   ...(ii)
Putting x = 0 in equation (i), we get:
⇒ 2 x 0 + 3y = 4
⇒ y = 4/3
x = 0, y = 4/3
Putting y = 0  in equation (i), we get:
⇒ 2x + 3 x 0 = 4
⇒ x = 2
x = 2, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,4/3) and B(2,0) from table
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation….(ii):
x - y = -3   ….(ii)
Putting x = 0  in equation (ii) we get:
⇒ 0 - y = -3
⇒ y = 3
x = 0, y = 3
Putting y = 0 in equation (ii), we get:
⇒ 0 - y = - 3
⇒ y = 3
x = 0, y = 3
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,3) and D(-3,0) from table
The two lines intersect at points P(-1,2)
Hence, x = - 1 and y = 2 is the solution.

Q.9. Solve the following systems of equations graphically:
2x − 3y + 13 = 0
3x − 2y + 12 = 0

Ans. The given equations are:
2x − 3y + 13 = 0   ...(i)
3x − 2y + 12 = 0   ...(ii)
Putting x = 0 in equation (i), we get
⇒ 2 x 0 - 3y = - 13
⇒ y = 13/3
x = 0, y = 13/3
Putting y = 0 in equation (ii) we get
⇒ 2x - 3 x 0 = - 13
⇒ x = - 13/2
x = - 13/2, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,13/2) and B(-13/2,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation….(ii):
3x - 2y = -12   ….(ii)
Putting x = 0 in equation (ii) we get:
⇒ 3x 0 - 2y = - 12
⇒ y = 6
x = 0, y = 6
Putting y = 0 in equation (ii), we get:
⇒ 3x - 2 x 0 = - 12
⇒ x = -4
x = -4, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,6)and D(-4, 0) from table.
The two lines intersect at points P(-2, 3)
Hence, x = - 2 and y = 3 is the solution.

Q.10. Solve the following systems of equations graphically:
2x + 3y + 5 = 0
3x − 2y − 12 = 0

Ans. The given equations are
2x + 3y + 5 = 0….(i)
3x - 2y - 12 = 0….(ii)
Putting x = 0 in equation (i), we get:
⇒ 2 x 0 + 3y = -5
⇒  y = - 5/3
Putting y = 0 in equation (i), we get:
⇒ 2x + 3 x 0 = -5
⇒ x = -5/2
x = -5/2, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation  ….(ii):
3x - 2y = 12  ….(ii)
Putting x = 0 in equation (ii) we get:
⇒ 3 x 0 - 2y = 12
⇒ y = -6
x = 0, y = - 6
Putting y = 0 in equation (ii), we get:
⇒ 3x - 2 x 0 = 12
⇒ x = 4
x = 4, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points from table.
The two lines intersects at points P(2,-3)
Hence, x = 2 and y = -3 is the solution.

Q.11. Show graphically that each one of the following systems of equations has infinitely many solutions:
2x + 3y = 6
4x + 6y = 12

Ans. The given equations are
2x + 3y = 6  ….(i)
4x + 6y = 12  ...(ii)
Putting x = 0 in equation (i), we get:
⇒ 2 x 0 +3y = 6
⇒ y = 2
x = 0, y = 2
Putting y = 0 in equation (i), we get:
⇒ 2x + 3x = 6
⇒ x = 3
x = 3, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,2) and B(3,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation ….(ii):
4x + 6y = 12 ….(ii)
Putting x = 0 in equation (ii) we get:
⇒ 4x 0 + 6y = 12
⇒ y = 2
x = 0, y = 2
 Putting y = 0 in equation (ii) we get:
⇒ 4x + 6 x 0 = 12
⇒ x = 3
x = 3, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,2),D(3,0) from table.
Thus the graph of the two equations coincide
Consequently, every solution of one equation is a solution of the other.
Hence the equations have infinitely many solutions.

Q.12. Show graphically that each one of the following systems of equations has infinitely many solutions:
x − 2y = 5
3x − 6y = 15

Ans. The given equations are
x - 2y = 5 .....(i)
3x - 6y = 15 .....(ii)
Putting x = 0 in equation (i), we get:
⇒ 0 - 2y = 5
⇒ y = -5/2
x = 0, y = -5/2
Putting y = 0  in equations (i) we get:
⇒ x - 2 x 0 = 5
⇒ x = 5
x = 5, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,-5/2) and B (5,0) from table
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation ...(ii)
3x - 6y = 15 ...(ii)
Putting x = 0 in equations (ii), we get:
⇒ 3 x 0 - 6y = 15
⇒ y = -5/2
x = 0, y = -5/2
Putting y = 0 in equation (ii), we get:
⇒ 3x - 6 x 0 = 15
⇒ x = 5
x = 5, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,-5/2) and D(5,0) from table.
Thus the graph of the two equations coincide
Consequently, every solution of one equation is a solution of the other.
Hence the equations have infinitely many solutions.

Q.13. Show graphically that each one of the following systems of equations has infinitely many solutions:
3x + y = 8
6x + 2y = 16
Ans. 
The given equations are
3x + y = 8 ...(i)
6x + 2y = 16   ...(ii)
Putting x = 0 in equation (i), we get:
⇒ 3x + 0 + y = 8
⇒ y = 8
x = 0, y = 8
Putting y = 0 in equation (i), we get:
⇒ 3x + 0 = 8
⇒ x = 8/3
x = 8/3,  y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,8) and B(8/3,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation….(ii):
6x + 2y = 16 ….(ii)
Putting x = 0 in equations (ii) we get:
⇒ 6 x 0 + 2y = 16
⇒ y = 8
x = 0, y = 8
Putting y = 0 in equation (ii), we get:
⇒ 6x + 2 x 0 = 16
⇒ x = 8/3
x = 8/3, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,8), D(8/3,0) from table.
Thus the graph of the two equations coincide
Consequently, every solution of one equation is a solution of the other.
Hence the equations have infinitely many solutions.

Q.14. Show graphically that each one of the following systems of equations has infinitely many solutions:
x − 2y + 11 = 0
3x − 6y + 33 = 0

Ans. The given equations are
x − 2y + 11 = 0   ...(i)
3x − 6y + 33 = 0   ...(ii)
Putting x = 0  in equation (i), we get:
⇒ 0 - 2y = -11
⇒ y = 11/2
x = 0, y = 11/2
Putting y = 0  in equation (i), we get:
⇒ x - 2x = -11
⇒ x = -11
x = -11, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,11/2),(-11,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation….(ii):
3x - 6y = -33….(ii)
Putting x = 0 in equation (ii) we get:
⇒ 3 x 0 - 6y = -33
⇒ y = 11/2
x = 0, y = 11/2
Putting y = 0 in equation (ii), we get
⇒ 3x - 6 x 0 = -33
⇒ x = -11
x = -11, y = 0
Draw the graph by plotting the two points C(0,11/2),D(-11,0) from table.
Thus the graph of the two equations are coincide
Consequently, every solution of one equation is a solution of the other.
Hence the equations have infinitely many solutions.

Q.15. Show graphically that each one of the following systems of equations is in-consistent (i.e. has no solution) :
3x − 5y = 20
6x − 10y = −40

Ans. The given equations are
3x - 5y = 20   ....(i)
6x − 10y = −40    ....(ii)
Putting x = 0  in equation (i) we get:
⇒ 3 x 0 - 5y = 20
⇒ y = - 4
x = 0, y = -4
Putting y = 0 in equation (i) we get
⇒ 3x - 5 x 0 = 20
⇒ x = 20/3
x = 20/3, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,-4), B(20/3,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Graph of the equation  ...(ii):
6x - 10y = -4  ...(ii)
Putting x = 0 in equation (ii) we get:
⇒ 6 x 0 - 10y = -4
⇒ y = 2/5
x = 2/5,  y = 0
Putting y = 0 in equation (ii) we get:
⇒ 6x - 10 x 0 = -4
⇒ x = -2/3
x = -2/3, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,-4), D(20/3,0) from table.
Here we see that the two lines are parallel
Hence the given system of equations has no solution.

Q.16. Show graphically that each one of the following systems of equations is in-consistent (i.e. has no solution) :
x − 2y = 6
3x − 6y = 0
Ans. 
The given equations are
x − 2y = 6  ...(i)
3x − 6y = 0  ...(ii)
Putting x = 0 in equation (i), we get:
⇒ 0 - 2y = 6
⇒ y = -3
⇒ x = 0, y = -3
Putting y = 0 in equation (i) we get:
⇒ x- 2 x 0 = 6
⇒ x = 6
⇒ x = 6, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
The graph of (i) can be obtained by plotting the two points A(0,-3), B(6,0)
Graph of the equation….(ii):
3x - 6y = 0 ….(ii)
Putting x = 0 in equation (ii) we get:
⇒ 3 x 0 - 6y = 0
⇒ y = 0
⇒ x = 0, y = 0
Putting y = 1 in equation (ii), we get:
⇒ 3x - 6 x 1 = 0
⇒ x = 2
⇒ x = 2, y = 1
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,0)D(2,1) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Here the two lines are parallel and so there is no point in common
Hence the given system of equations has no solution.

Q.17. Show graphically that each one of the following systems of equations is in-consistent (i.e. has no solution) :
2y − x = 9
6y − 3x = 21
Ans. 
The given equations are
2y - x = 9   ....(i)
6y − 3x = 21   ....(ii)
Putting x = 0 in equation (i), we get:
⇒ 2y - 0 = 9
⇒ y = 9/2
⇒ x = 0, y = 9/2
Putting y = 0 in equation (i) we get:
⇒ 2x - x = 9
⇒ x = -9
⇒ x = -9, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points A(0,9/2), B(-9,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
6y - 3x = 21   ....(ii)
Putting x = 0 in equation (ii) we get:
⇒ 6y - 3 x 0 = 21
⇒ y = 7/2
⇒ x = 0,  y = 7/2
Putting y = 0 in equation (ii) we get:
⇒ 6 x 0 - 3x = 21
⇒ y = 7/2
∴ x = - 7, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,7/2),D(-7, 0) from table.
Here two lines are parallel and so don’t have common points
Hence the given system of equations has no solution.

Q.18. Show graphically that each one of the following systems of equations is in-consistent (i.e. has no solution) :
3x − 4y − 1 = 0

Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Ans. The given equations are
3x - 4y - 1 = 0    ....(i)
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
6x - 8y + 15 = 0    ....(ii)
Putting x = 0 in equation (i), we get:
⇒ 3 x 0 - 4y = 1
⇒ y = -1/4
⇒ x = 0, y = -1/4
Putting y = 0 in equation (i), we get:
⇒ 3x - 4 x 0 = 1
⇒ x = 1/3
⇒ x = 1/3, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
The graph of (i) can be obtained by plotting the two points A(0, -1/4), B(1/3,0).
6x - 8y = - 15   ....(ii)
Putting x = 0 in equation we (ii) get:
⇒ 6 x 0 - 8y = - 15
⇒ y = 15/8
⇒ x = 0,  y = 15/8
Putting y = 0 in equation (ii), we get:
⇒ 6x - 8 x 0 = - 15
⇒ x = - 15/6
⇒ x = -5/2, y = 0
Use the following table to draw the graph.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Draw the graph by plotting the two points C(0,15/8), D(-5/2,0) from table.
Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics
Here, the two lines are parallel.
Hence the given system of equations is inconsistent.

The document Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) | RD Sharma Solutions for Class 10 Mathematics is a part of the Class 10 Course RD Sharma Solutions for Class 10 Mathematics.
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FAQs on Chapter 3 - Pair Of Linear Equations In Two Variables, RD Sharma Solutions - (Part-8) - RD Sharma Solutions for Class 10 Mathematics

1. What is the concept of a pair of linear equations in two variables?
Ans. A pair of linear equations in two variables consists of two linear equations that contain two variables, typically denoted as x and y. These equations can be represented graphically as two straight lines on a coordinate plane.
2. How can we solve a pair of linear equations in two variables algebraically?
Ans. There are several methods to solve a pair of linear equations algebraically, such as the substitution method, the elimination method, and the cross-multiplication method. These methods involve manipulating the equations to eliminate one variable and solve for the remaining variable.
3. What is the significance of finding the solution to a pair of linear equations in two variables?
Ans. Solving a pair of linear equations in two variables helps in finding the point of intersection of the two lines represented by the equations. This point represents the solution to the system of equations and can be used to solve real-world problems related to the given situation.
4. Can a pair of linear equations in two variables have more than one solution?
Ans. Yes, a pair of linear equations in two variables can have one unique solution, no solution (inconsistent system), or infinitely many solutions (dependent system), depending on the nature of the equations and their relationship to each other.
5. How can we verify the solution to a pair of linear equations in two variables?
Ans. To verify the solution to a pair of linear equations in two variables, substitute the values of the variables obtained from the solution into both equations. If the values satisfy both equations simultaneously, then the solution is correct.
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