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Practice Questions: Ratio & Proportion

Introduction

The main focus of this document is to practice the questions before you go and attempt your nationwide tests @EduRev so that you will be more relating to questions asked in that exam & be more confident about your answers.
All The Best!

Easy Level 


At this level, questions are targeted to improve your knowledge of basic concepts, though easy questions are rare in CAT. 
These are extremely important for conceptual understanding at the foundation level. Try this past year question by yourself first.

Let's start with the Practice Questions

Example 1: If three numbers are in the ratio of 1 : 3 : 5 and half the sum is 9, then the ratio of cubes of the numbers is:
(a) 6 : 12 : 13 
(b) 1 : 3 : 25
(c) 1 : 27 : 125
(d) 3 : 5 : 7

Ans: (c)
Sol: Let the numbers be x, 3x and 5x.

Half of sum = 9 ⇒ Total sum = 18

x + 3x + 5x = 9x = 18
⇒ x = 2

Numbers = 2, 6, 10

Cubes of numbers:
2³ = 8, 6³ = 216, 10³ = 1000

Ratio of cubes = 8 : 216 : 1000

Divide by 8:
= 1 : 27 : 125

Example 2: Three quantities A, B, C are such that AB = KC, where k is a constant. When A is kept constant, B varies directly as C; when B is kept constant, A varies directly C and when C is kept constant, A varies inversely as B. Initially, A was at 5 and A : B : C was 1 : 3 : 5. Find the value of A when B equals 9 at constant C. 
(a) 8
(b) 8.33
(c) 9
(d) 9.5

Ans: (b)
Sol: Corresponding values:
A = 5, B = 15, C = 25

Given relation: AB = kC

Substitute values:
5 × 15 = k × 25
75 = 25k
k = 3

So, AB = 3C

When C is constant at 25 and B = 9:

A × 9 = 3 × 25
A × 9 = 75
A = 75 / 9 = 25 / 3 ≈ 8.33

Example 3: A began a business with Rs. 4,500 and was joined afterwards by B with Rs. 5,400. If the profits at the end of the year were divided in the ratio 2 : 1, then B joined the business after: 
(a) 5 months
(b) 4 months
(c) 6 months
(d) 7 months

Ans: (d)
Sol: A's share ∝ 4500 × 12
B's share ∝ 5400 × n

Profit ratio:

4500 × 12 : 5400 × n

Divide both by 900:

5 × 12 : 6 × n
60 : 6n
10 : n

Given ratio = 2 : 1

10 : n = 2 : 1
n = 5 months

B invested for 5 months

Therefore, B joined after = 12 - 5 = 7 months

MULTIPLE CHOICE QUESTION

Try yourself: X varies jointly as Y and Z; and X = 6 when Y = 3, Z = 2; find X when Y = 5, Z = 7. 

A

8.75 

B

35 

C

D

15

MULTIPLE CHOICE QUESTION

Try yourself: 3650 is divided among 4 engineers, 3 MBAs and 5 CAs such that 3 CAs get as much as 2 MBAs and 3 Engineers as much as 2 CAs. Find the share of an MBA. 

A

300 

B

450 

C

475 

D

None of these

MULTIPLE CHOICE QUESTION

Try yourself: Divide Rs rs.5000 among A, B, C and D so that A and B together get 3/7thof what C and D get together, C gets 1.5 times of what B gets and D gets 4/3 times as much as C. Now the value of what B gets is 

A

500 

B

1000

C

2000 

D

1500

MULTIPLE CHOICE QUESTION

Try yourself: A bag contains Rs. 600 in the form of one rupee, 50 paise and 25 paise coins in the ratio of 3 : 4 : 12. Find the total value (in Rs.) of the 25 paise coins present in the bag. 

A

220

B

225

C

300

D

325

MULTIPLE CHOICE QUESTION

Try yourself: Divide Rs.1400 into three parts in such a way that half of the first part, one-fourth of the second part and one-eighth of the third part are equal. 

A

300, 600, 500 

B

200, 400, 800 

C

100, 400, 1000 

D

None of these

MULTIPLE CHOICE QUESTION

Try yourself: The students in three batches at EduRev are in the ratio 2 : 3 : 5. If 20 students are increased in each batch, the ratio changes to 4 : 5 : 7. The total number of students in the three batches before the increases were 

A

10 

B

90 

C

100 

D

150

Intermediate Level

Almost 70% of questions in CAT are of Medium based questions. Though the conceptually they seem easier, the trick is to solve the calculations faster & we curated problems for you to help you do problems easier.

Example 1: Monthly incomes of X and Y are in the ratio 1 : 3 and their expenses are in the ratio 19 : 40. X saves Rs. 18,860 less than that Y and in total they save Rs. 36,020. The income of X and Y respectively are: 
(a) Rs. 10,480 and Rs. 31440
(b) Rs. 9,000 and Rs. 27,000
(c) Rs. 14,200 and Rs. 42,600
(d) Rs. 18,000 and Rs. 31,440

Ans: (a)
Sol: Let income of X = p
Income of Y = 3p

Let expenses of X = 19q
Expenses of Y = 40q

Savings of X = p - 19q
Savings of Y = 3p - 40q

Total savings:

(p - 19q) + (3p - 40q) = 36,020
4p - 59q = 36,020 ......(1)

Difference in savings:

(3p - 40q) - (p - 19q) = 18,860
2p - 21q = 18,860 ......(2)

Multiply (2) by 2:

4p - 42q = 37,720 ......(3)

Subtract (1) from (3):

(4p - 42q) - (4p - 59q) = 37,720 - 36,020
17q = 1,700
q = 100

Substitute in (1):

4p - 59×100 = 36,020
4p - 5,900 = 36,020
4p = 41,920
p = 10,480

Income of X = ₹10,480
Income of Y = 3p = ₹31,440

Example 2: A student scored marks in the ratio 5 : 4 : 6 : 8 : 7 in five subjects having equal maximum marks. In all, he scored 50% of the maximum marks in all the five subjects taken together. In how many subjects did he score more than 55% of the maximum marks?
(a) 1
(b) 2
(c) 3
(d) 4

Ans: (b)

Sol: Let marks = 5x, 4x, 6x, 8x, 7x

Total obtained = 30x

Since this is 50% of total maximum:

Total maximum = 60x

Maximum per subject = 60x ÷ 5 = 12x

55% of maximum per subject:

= 0.55 × 12x
= 6.6x

Compare each subject:

5x < 6.6x → No
4x < 6.6x → No
6x < 6.6x → No
8x > 6.6x → Yes
7x > 6.6x → Yes

Number of subjects with >55% = 2

Example 3: A person buys some apples and mangoes from the market. The cost price of a mango is twice that of an apple and the selling price of a mango is thrice that of an apple. By selling an apple at twice its cost price, he makes 150% profit on the whole. Find the ratio of the number of mangoes to that of apples that he bought from the market. 
(a) 3 : 5 
(b) 3 : 4 
(c) 1 : 2 
(d) 2 : 3

Ans: (c)
Sol: Let cost of an apple = c
Cost of a mango = 2c

Selling price of an apple = 2c

Selling price of a mango = 3 × 2c = 6c

Let number of apples = x
Number of mangoes = y

Total cost:

= xc + 2yc
= c(x + 2y)

Total revenue:

= 2cx + 6cy
= c(2x + 6y)

Profit:

= Revenue - Cost
= c(2x + 6y - x - 2y)
= c(x + 4y)

Given profit = 150% ⇒ Profit/Cost = 3/2

Intermediate Level

Cross multiply:

2(x + 4y) = 3(x + 2y)
2x + 8y = 3x + 6y
x = 2y

So, y/x = 1/2

Ratio (mangoes : apples) = 1 : 2

MULTIPLE CHOICE QUESTION

Try yourself: The ratio of the first class fare and second class fare is 3 : 1 and that of the number of passengers traveling by the first class and by the second class is 1 : 27. If Rs. 2,700 is collected as fare, then the amount collected from the first class passengers is 

A

Rs. 300 

B

Rs. 729 

C

Rs. 270 

D

Rs. 96.42

MULTIPLE CHOICE QUESTION

Try yourself: The ratios of the incomes and the expenditures of Aishwarya, Babita and Charu are 7 : 9 : 12 and 8 : 9 : 15 respectively. If Aishwarya saves one-fourth of her income, then the ratio of their savings is 

A

56 : 99 : 69 

B

69 : 56 : 99 

C

99 : 56 : 69 

D

99 : 69 : 56

MULTIPLE CHOICE QUESTION

Try yourself: Total expenses of a boarding house are partly fixed and partly varying linearly with the number of boarders. The average expense per boarder is Rs. 700 when there are 25 boarders and Rs. 600 when there are 50 boarders. What is the average expense per boarder when there are 100 boarders? (CAT 1999) 

A

550 

B

580 

C

540 

D

570

MULTIPLE CHOICE QUESTION

Try yourself: Sahil employs 200 men to build a bund. They finish 5/6 of the work in 10 weeks. Because of some natural calamity not only does the work remain suspended for 4 weeks but also half of the work already done is washed away. After the calamity, when the work is resumed, only 140 men turn up. The total time in which the contractor is able to complete the work assuming that there are no further disruptions in the schedule 

A

25 weeks 

B

26 weeks 

C

24 weeks 

D

20 weeks

MULTIPLE CHOICE QUESTION

Try yourself: A bag contains 25 paise, 50 paise and 1 Rupee coins. There are 220 coins in all and the total amount in the bag is Rs160. If there are thrice as many 1 Rupee coins as there are 25 paise coins, then what is the number of 50 paise coins? 

A

60 

B

40 

C

120 

D

80​

MULTIPLE CHOICE QUESTION

Try yourself: A mother divided an amount of Rs 61,000 between her two daughters aged 18 years and 16 years respectively and deposited their shares in a bond. If the interest rate is 20% compounded annually and if each received the same amount as the other when she attained the age of 20 years, their shares are 

A

Rs 35,600 and Rs 25,400 

B

Rs 30500 each 

C

Rs 24,000 and Rs 37000 

D

None of these

MULTIPLE CHOICE QUESTION

Try yourself: 40 men could have finished the whole project in 28 days but due to the inclusion of a few more men, work got done in 3/4 of the time. Find out how many more men were included (in whole numbers). 

A

12 

B

13 

C

14 

D

None of these

Hard Level

Around 25% of these types of questions come in CAT - If your target is above 95%ile, we recommend you solve these questions. 

Example 1: From a full barrel containing 729 litres of honey, we pour off 'a' litre and add water to fill up the barrel. After stirring the solution thoroughly, we pour off 'a' litre of the solution and again add water to fill up the barrel. After the procedure is repeated 6 times, the solution in the barrel contains 64 litres of honey. Find a. 
(a) 243 litres 
(b) 81 litres 
(c) 2.7 litres 
(d) 3 litres 

Ans: (a)
Sol: Initial honey = 729 L

After each operation, fraction of honey remaining:

Hard Level

After 6 repetitions:

Hard Level

Taking sixth root:

Hard Level

\frac{729 - a}{729}Example 2:There are two alloys of gold, silver and platinum. The first alloy is known to contain 40% of platinum and the second alloy 26 % of silver. The percentage of gold is the same in both alloys. Having alloyed 150 kg of the first alloy and 250 kg of the second, we get a new alloy that contains 30 per cent of gold. How many kilograms of platinum is there in the new alloy?

(a) 170 kg 

(b) 175 kg 

(c) 160 kg 

(d) 165 kg

Ans: (a)

Sol: Total weight = 150 + 250 = 400 kg

Gold in new alloy:

30%of400=120kg30\% \text{ of } 400 = 120 \text{ kg}30% of 400=120 kg

Let gold percentage in each alloy = G%

Gold from both alloys:

Hard Level

Composition of alloys

Alloy 1 (150 kg):

Platinum = 40%
Gold = 30%
Silver = 30%

Platinum from alloy 1:

0.40×150=60 Kg

Alloy 2 (250 kg):

Silver = 26%
Gold = 30%

Platinum = 100 - 26 - 30 = 44%

Platinum from alloy 2:

0.44 × 250 = 110 kg

Total platinum in new alloy:  kg60 + 110 = 170 \text{ kg}60+110=170 kg

Answer: (a) 170 kg kg0.40 \times 150 = 60 \text{ kg}

MULTIPLE CHOICE QUESTION

Try yourself: In two alloys, the ratios of nickel to tin are 5 : 2 and 3 : 4 (by weight). How many kilogram of the first alloy and of the second alloy should be alloyed together to obtain 28 kg of a new alloy with equal contents of nickel and tin?

A

9 kg of the first alloy and 22 kg of the second

B

17 kg of the first alloy and 11 kg of the second

C

7 kg of the first alloy and 21 kg of the second

D

8 kg and 20 kg respectively 

MULTIPLE CHOICE QUESTION

Try yourself: Total expenses of running the hostel at Harvard Business School are partly fixed and partly varying linearly with the number of boarders. The average expense per boarder is $70 when there are 25 boarders and $60 when there are 50 boarders. What is the average expense per boarder when there are 100 boarders? 

A

54

B

56 

C

55

D

50 

MULTIPLE CHOICE QUESTION

Try yourself: Gunpowder can be prepared by saltpetre and nitrous oxide. Price of saltpetre is thrice the price of nitrous oxide. Notorious gangster Kallu Bhai sells the gunpowder at Rs 2160 per 10 g, thereby making a profit of 20%. If the ratio of saltpetre and nitrous oxide in the mixture be 2 : 3, find the cost price of saltpetre.

A

Rs 210/gm 

B

Rs 300/gm 

C

Rs 120/gm 

D

None of these

This brings you to the end of practice document, EduRev wishes you the best for your online practice tests on our platform.

The document Practice Questions: Ratio & Proportion is a part of the UPSC Course CSAT Preparation.
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FAQs on Practice Questions: Ratio & Proportion

1. How do I find the ratio of two quantities when one keeps changing in a word problem?
Ans. When quantities change proportionally, identify which quantity is constant and which varies, then set up the ratio using the given values. For instance, if 5 books cost ₹250, the ratio of books to cost remains 5:250 or 1:50. Always simplify the ratio by finding the greatest common divisor, and verify using the relationship between the two quantities.
2. What's the difference between direct proportion and inverse proportion in CBSE practice questions?
Ans. Direct proportion means as one quantity increases, the other increases proportionally (like speed and distance). Inverse proportion means as one increases, the other decreases proportionally (like workers and time needed). Students can identify which applies by checking whether quantities increase together or oppositely, then apply the correct formula accordingly.
3. Why do I get different answers when solving the same ratio problem using different methods?
Ans. Different methods yield identical answers only when applied correctly. Most errors occur from incorrect simplification or misidentifying which quantity represents numerator versus denominator. Always cross-multiply to verify your ratio is equivalent, and ensure you're comparing like quantities (both in same units). Practice questions help reinforce consistent technique across varied scenarios.
4. Can I use proportion to solve missing values in ratios, or do I need a different approach?
Ans. Proportion directly solves for missing values using the cross-multiplication method. If a:b = c:d, then ad = bc. This technique works for all practice questions involving unknown quantities in equivalent ratios. Students should set up the proportion statement first, cross-multiply, then isolate the variable to find the missing term efficiently.
5. How do compound ratios appear in CUET Commerce General Test questions, and what's the quickest way to handle them?
Ans. Compound ratios involve multiplying individual ratios together-if a:b and b:c are given, the compound ratio a:c equals (a/b) × (b/c). To solve quickly, cancel common terms before multiplying remaining numerators and denominators. Many practice questions test this concept implicitly through problems involving three related quantities, requiring students to find relationships between non-adjacent terms.
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