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GATE Past Year Questions: Stress & Strain

Q1: The figure shows a thin cylinder pressure vessel constructed by welding plates together along a line that makes an angle α = 6 0 ∘ with the horizontal. The closed vessel has a wall thickness of 10 m m 10 mm and diameter of 2 m. When subjected to an internal pressure of  200kPa, the magnitude of the normal stress acting on the weld is ______ MPa (rounded off to 1 decimal place).  [GATE ME 2024]
GATE Past Year Questions: Stress & StrainAns:
(12.3 to 12.7)
P = 200kPa = 0.2MPa 
d =2 m 
t =10 mm 
GATE Past Year Questions: Stress & Strain

σa + σl = Pd/4t
= 0.2 x 2 x 103/4 x 10 = MPa
⇒ σc = σ y = -2σ1 = 2 x σ= 2 x 10 = 20MPa//
GATE Past Year Questions: Stress & Strain

σ= σn
GATE Past Year Questions: Stress & Strain cos 2 x 30° + Txy x sin 2 x 30° 
σn = 10 + 20/2 + (10 - 20)/2 cos 60 + 0 = 12.5Mpa


Q1: Ignoring the small elastic region, the true stress (σ)- true strain (ε) variation of a material beyond yielding follows the equation σ = 400 ε 0.3 MPa. The engineering ultimate tensile strength value of this material is ________ MPa. (Rounded off to one decimal place) [GATE ME 2023]
Ans: 
(206 to 207)
Given 
σT = 400 ε 0.3 = 400 εT 0.3 . . . ( i ) 
ε = true strain = εT
n = 0.3 = strain hardening exponent 
The true strain (εT) at the onset of necking equal to the strain hardening exponent i.e. at ultimate tensile point.
So,εT  = n = 0.3 at ultimate point
So, from equation (i)
σT = 400 × (0.3) 0.3 =278.74MPa at ultimate point 
As εT = ln ⁡ (1 + ε) 
So,ε = eεT-1 = e0.3-1=0.35
and σT= σ(1 + ε)
So σ ultimate  = σT/1 + ε + 278.74/1 + 0.35 = 206. 55Mpa


Q2: The principal stresses at a point P in a solid are 70 MPa, -70 MPa and 0. The yield stress of the material is 100 MPa. Which prediction(s) about material failure at P is/are CORRECT?  [GATE ME 2023]
(a) Maximum normal stress theory predicts that the material fails
(b) Maximum shear stress theory predicts that the material fails
(c) Maximum normal stress theory predicts that the material does not fail
(d) Maximum shear stress theory predicts that the material does not fail
Ans:
(b, c)
σ1=70MPa, σ=-70MPa, σ3=0, Syt = 100MPa
For maximum shear stress theory:
GATE Past Year Questions: Stress & Strain
So material will fail As per maximum normal stress theory:
σ1 and sigma 2 > sigma yt
then material will fail
Here 70 & -70 < 100
So material is safe.


Q1: A prismatic bar PQRST is subjected to axial loads as shown in the figure. The segments having maximum and minimum axial stresses, respectively, are  [GATE ME 2021 SET-1 ]
GATE Past Year Questions: Stress & Strain
(a) QR and PQ
(b) ST and PQ
(c) QR and RS
(d) ST and RS
Ans:
(d)
GATE Past Year Questions: Stress & StrainPmax = PST = 25kN
Pmin = PRS = 5kN
Hence, maximum and minimum axial stresses are in ST and RS portions because of prismatic bar.


Q2: The loading and unloading response of a metal is shown in the figure. The elastic and plastic strains corresponding to 200 MPa stress, respectively, are  [GATE ME 2021 SET-1]
GATE Past Year Questions: Stress & Strain(a) 0.01 and 0.01
(b) 0.02 and 0.01
(c) 0.01 and 0.02
(d)0.02 and 0.02
Ans:
(b) 
Elastic strain : Which can be recovered = 0.03 - 0.01 = 0.02 
Plastic strain : Permanent strain = 0.01


Q1: Uniaxial compression test data for a solid metal bar of length 1 m is shown in the figure.

GATE Past Year Questions: Stress & Strain

The bar material has a linear elastic response from O to P followed by a non-linear response. The point P represents the yield point of the material. The rod is pinned at both the ends. The minimum diameter of the bar so that it does not buckle under axial loading before reaching the yield point is _______ mm (round off to one decimal place).  [GATE ME 2020, SET-2]
Ans:
(55 to 58)
For both end pin,
GATE Past Year Questions: Stress & Strain
= 56.94mm


Q2: Bars of square and circular cross-section with 0.5 m length are made of a material with shear strength of 20 MPa. The square bar cross-section dimension is 4 cm x 4 cm and the cylindrical bar cross-section diameter is 4 cm. The specimens are loaded as shown in the figure.

GATE Past Year Questions: Stress & Strain

Which specimen(s) will fail due to the applied load as per maximum shear stress theory?  [GATE ME 2020 SET-1 ]
(a) Tensile and compressive load specimens
(b) Torsional load specimen
(c) Bending load specimen
(d) None of the specimens
Ans: 
(a)
GATE Past Year Questions: Stress & Strainσ = 80 x 103/402 = 50N/mm2
Tmax = σ/2 = 25N/mm2 > 20MPa
GATE Past Year Questions: Stress & Strain= 16N/mm2 <20MPa
σ = 320 x 103/403 = 30N/mm2
6 = σ/2 = 15N/mm2 < 20MPa
Tmax = σ/2

The document GATE Past Year Questions: Stress & Strain is a part of the Mechanical Engineering Course Strength of Materials (SOM).
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FAQs on GATE Past Year Questions: Stress & Strain

1. What's the difference between stress and strain in GATE Mechanical Engineering problems?
Ans. Stress is the internal force per unit area acting on a material, while strain is the resulting deformation expressed as a ratio of change to original dimension. Stress causes strain-the applied load creates stress, which produces measurable strain. Understanding this relationship is fundamental for solving GATE previous year questions on material behaviour under loading conditions.
2. How do I identify whether a GATE past year question involves tensile or compressive stress?
Ans. Tensile stress occurs when forces pull a material apart, creating positive strain and elongation. Compressive stress squeezes material, reducing its length or volume. In GATE problems, examine the force direction relative to the cross-section: pulling forces indicate tension, pushing forces indicate compression. This distinction determines which formulas and failure criteria apply to your calculations.
3. Why do shear stress and shear strain calculations confuse me in GATE exam questions?
Ans. Shear stress acts parallel to a surface, causing angular distortion without volume change, whereas shear strain measures this angular deformation as a ratio. Many students confuse shear with normal stress because shear involves different force directions. GATE questions test whether you correctly apply the shear modulus formula and recognize that shear occurs in torsion, bending, and direct shear applications.
4. What's the relationship between Young's modulus, bulk modulus, and shear modulus in stress-strain GATE problems?
Ans. Young's modulus measures longitudinal stiffness under normal stress, bulk modulus measures volumetric resistance to hydrostatic pressure, and shear modulus measures resistance to angular distortion. These elastic constants relate mathematically; knowing any two lets you calculate the third. GATE past year questions frequently test this interconnection to assess material property understanding.
5. How should I approach solving elastic strain energy questions from previous GATE exams?
Ans. Elastic strain energy represents work stored when a material deforms elastically under stress. Calculate it using energy formulas: U = (stress²/2E) × volume or U = ½Fδ, depending on given data. GATE questions test whether you distinguish elastic energy from plastic deformation and apply the correct formula for different loading scenarios like bending, torsion, and combined stresses.
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