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GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering PDF Download

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Q1:The figure shows a wheel rolling without slipping on a horizontal plane with angular velocity  ω1 A rigid bar PQ is pinned to the wheel at P while the end Q slides on the floor. What is the angular velocity   ω1  of the bar PQ?      (2023)

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
(a) ω2 =2ω1.

(b) ω2 = ω1.
(c) ω2 = 0.5 ω1
(d) ) ω2 = 0.25 ω1

Ans:(d)

Sol: 

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

As Disc (Link 2) roll without slipping on Link 1 (surface) so their I-centre of rotation lies on point of contact to avoid relative motion in between them. So  I12.   lies on point of contact. Link 2 and 3 have instantaneous center of rotation at I 13  due to fixed surface  of Link 1.

As per point Plies on link 2 and 3 both so, point P has same velocity for Link 2 and 3 both. 

As per Kennedy's theorem, if three plane bodies have relative motion among themselves, their I-centre must lie on a straight line.
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q2: The Whitworth quick return mechanism is shown in the figure with link lengths as follows: OP = 300 mm, OA = 150 mm, AR = 160 mm, RS = 450 mm.      (2021 Set 1) 

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
The quick return ratio for the mechanism is ________(round off to one decimal place).

(a) 1
(b) 2
(c) 2.5

(d) 3.5

Ans:( 2)

Sol: 

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q3:  The crank of a slider-crank mechanism rotates counter-clockwise (CCW) with a constant angular velocity 𝜔ω, as shown. Assume the length of the crank to be r.       (2019 Set2 )
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Using exact analysis, the acceleration of the slider in the y direction, at the instant shown, where the crank is parallel to x-axis, is given by

(a) -ω2r

(b) 2ω2r
(c) ω2r
(d) -2ω2r

Ans:(c)

Sol:

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q4:A slider crank mechanism is shown in the figure. At some instant, the crank angle is  45 ∘  and a force of 40 N is acting towards the left on the slider.  The length of the crank is 30 mm and the connecting rod is 70 mm.  .Ignoring the effect of gravity, friction and inertial forces, ,the magnitude of the crankshaft torque (in Nm) needed to keep the mechanism in equilibrium is _________ (correct to two decimal places).      (2018 Set1)
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

(a) 0.12

(b) 0.56

(c) 1.12

(d) 2.52

Ans:(c)
Sol:

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q5: In a certain slider-crank mechanism, lengths of crank and connecting rod are equal. If the crank rotates with a uniform angular speed of 14 rad/s and the crank length is 300 mm, the maximum acceleration of the slider (in m/s 2 ) in__________      (2015 Set 2) 

(a) 117.6m/s

(b) 215.4m/s
(c) 125.2m/s
(d) 458.6m/s

Ans:(a)
Sol:

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q6: A slider-crank mechanism with crank radius 60 mm and connecting rod length 240 mm is shown in figure. The crank is rotating with a uniform angular speed of 10 rad/s, counter clockwise. For the given configuration, the speed (in m/s) of the slider is _______      (2014Set 3)
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

(a) 0.2m/s

(b) 0.9m/s

(c) 0.6m/s

(d)  9.5m/s

Ans:(c) 

Sol: 

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

From the given configuration,
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q7: An offset slider-crank mechanism is shown in the figure at an instant. Conventionally, the Quick Return Ratio (QRR) is considered to be greater than one. The value of QRR is _______       (2014 Set 1)
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

(a) 1.25

(b) 2.15

(c) 3.25

(d) 4.51

Ans: (a)

Sol:
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q8: A slider crank mechanism has slider mass of 10 kg, stroke of 0.2 m and rotates with a uniform angular velocity of 10 rad/s. The primary inertia forces of the slider are partially balanced by a revolving mass of 6 kg at the crank, placed at a distance equal to crank radius. Neglect the mass of connecting rod and crank. When the crank angle (with respect to slider axis) is 30 o  the unbalanced force (in newton)  normal to the  slider  axis is _______      (2014 Set 1)

(a)30N

(b) 20N

(c) 10N

(d) 40N

Ans: (a) 

Sol :
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q9: For a four-bar linkage in toggle position, the value of mechanical advantage is:      (2006)
(a)0

(b) 0.5

(c) 1

(d)∞
Ans: (b)
Sol: 

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

ω 4  of the output link DC becomes zero at the extreme positions.   The extreme positions of the linkage are known as  "Toggle position".
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

Q10: For a mechanism shown below, the mechanical advantage for the given configuration is      (2004)
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

(a)0

(b) 0.5

(c) 1

(d)∞

Ans: (d)
Sol:

Mechanical advantage
GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

since output link is a slider

Hence,𝜔 output =0 

∴ Mechanical advantage =∞

Question for GATE Past Year Questions: Slider - Crank Mechanism
Try yourself:For a mechanism shown below, the mechanical advantage for the given configuration is

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

[2004]

View Solution

Question for GATE Past Year Questions: Slider - Crank Mechanism
Try yourself:Consider the triangular formed by the connecting rod and the crank of an IC engine as the two sides of the triangle. If the maximum area of this triangle occurs when the crank is 75°, the ratio of connecting rod length to crank radius to

[1998]

View Solution

Question for GATE Past Year Questions: Slider - Crank Mechanism
Try yourself:The cross head velocity in the slider crank mechanism, for the position shown in figure

GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering

[1997]

View Solution

The document GATE Past Year Questions: Slider - Crank Mechanism | Theory of Machines (TOM) - Mechanical Engineering is a part of the Mechanical Engineering Course Theory of Machines (TOM).
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FAQs on GATE Past Year Questions: Slider - Crank Mechanism - Theory of Machines (TOM) - Mechanical Engineering

1. What is a slider-crank mechanism in mechanical engineering?
Ans. A slider-crank mechanism is a mechanical linkage that converts rotary motion into linear motion, or vice versa. It consists of a crank, a connecting rod, and a slider that moves back and forth in a straight line.
2. How is the displacement of the slider calculated in a slider-crank mechanism?
Ans. The displacement of the slider in a slider-crank mechanism can be calculated using the following formula: Displacement = Crank Length * (1 - cos(θ)), where θ is the angle of rotation of the crank.
3. What are the applications of a slider-crank mechanism?
Ans. Slider-crank mechanisms are commonly used in internal combustion engines, reciprocating pumps, and reciprocating compressors. They are also used in various types of machinery where linear motion is required.
4. How does a slider-crank mechanism differ from a four-bar linkage mechanism?
Ans. A slider-crank mechanism has a fixed pivot point, while a four-bar linkage mechanism has four movable pivot points. The slider-crank mechanism is simpler and more compact, making it ideal for applications where space is limited.
5. What are the advantages of using a slider-crank mechanism in mechanical systems?
Ans. Some advantages of using a slider-crank mechanism include simplicity in design, efficient power transmission, and the ability to convert rotary motion into linear motion with high precision. Additionally, slider-crank mechanisms are easy to manufacture and maintain.
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