Q1: The Levai type-A train illustrated in the figure has gears with module m = 8 mm/ tooth. Gears 2 and 3 have 19 and 24 teeth respectively. Gear 2 is fixed and internal gear 4 rotates at 20rev/min counter-clockwise. The magnitude of angular velocity of the arm is ______ rev/min. (rounded off to 2 decimal places) [GATE ME 2024]

Ans: 15 to 16
Data given
m8 mm
T2 = 19
T3 = 24
N2 = 0
N4 = 20 rpm
r4 = r2 + 2r3

or, T4 = T2 × 2 T3
i.e.,
T4 = 19 + 2 × 24 = 67
As N2 = 0 So,
x + y = 0 ...(1)
N4 = 20 = y−x × (19/67)
or, y − x × (19/67) = 20 ... (2) By (i) and (ii)
k = -15.58 rpm
= 15.58 clockwise
y = 15.58 counterclockwise
Q1: Two meshing spur gears 1 and 2 with diametral pitch of 8 teeth per mm and an angular velocity ratio ∣ω2∣/∣ω1∣ = 1/4, have their centers 30 mm apart. The number of teeth on the driver (gear 1) is _______ . (Answer in integer) [GATE ME 2023]
Ans: 95.999 to 96.001
Given
R + r = 30 ...(i)
where T = no. of teeth
or T2 = 4T1
Diametrical pitch = 8 teeth/mm = T/D = Pd
and m = D/T = 1/Pd
r = mT/2
As, 
by equation (i) we have

As T2 = 4T1
So, 1/16 (T1 + 4T1) = 30
or σ1 = (30×16)/5 = 96
Q1: A schematic of an epicyclic gear train is shown in the figure. The sun (gear 1) and planet (gear 2) are external, and the ring gear (gear 3) is internal. Gear 1, gear 3 and arm OP are pivoted to the ground at O. Gear 2 is carried on the arm OP via the pivot joint at P, and is in mesh with the other two gears. Gear 2 has 20 teeth and gear 3 has 80 teeth. If gear 1 is kept fixed at 0 rpm and gear 3 rotates at 900 rpm counter clockwise (ccw), the magnitude of angular velocity of arm OP is __________rpm (in integer). [GATE ME 2022 SET-1]
Ans: 600 to 600
Speed of gear 1 N1 = 0,
Speed of gear 3 N3 = 900 rpm,
Speed of Arm Narm = ?,
Teeth of gear 1 z1 = ?
Teeth of gear 2 z2 = 20
Teeth of gear 3 z3 = 80
Teeth of gear 2
z3 = z1 + 2z2
80 = z1 + 2(20)
z1 = 40z
N1 = x + y = 0
⇒ x = -y
N3 = 
= y - (40/80)(x) = 900
⇒ y - (40/80)(-y) = 900
1.5y = 900
= 600 rpm
Q1: A power transmission mechanism consists of a belt drive and a gear train as shown in the figure.
Diameters of pulleys of belt drive and number of teeth (T) on the gears 2 to 7 are indicated in the figure. The speed and direction of rotation of gear 7, respectively, are [GATE ME 2021 SET-2]
(a) 255.68 rpm; clockwise
(b) 255.68 rpm; anticlockwise
(c) 575.28 rpm; clockwise
(d) 575.28 rpm; anticlockwise
Ans: (a)
T3 = 44
T6 = 36
T2 = 18
T4 = 15

⇒ N1 = (150/250) x 2500
N1 = 15,00 = N2

= 255.6818 = N7 (Clockwise)
Gear 5 is idler.
Q1: The sun (S) and the planet (P) of an epicyclic gear train shown in the figure have identical number of teeth
If the sun (S) and the outer ring (R) gears are rotated in the same direction with angular speed ωS and ωR, respectively, then the angular speed of the arm AB is [GATE ME 2020 SET-2]
(a) 
(b) 
(c) 
(d) 
Ans: (a)
rs + 2rp = rR
⇒ Ts + 2Tp = TR (TP = TS)
3TP = TR
⇒ 3TP = TR
y + x = ωS
y − (x/3) = ωR
Substract by,
4x/3 = (ωS - ωR)
x = 3/4 (ωS - ωR)
y = ωS - x = ωS - (3/4)(ωS - ωR)

Q2: A balanced rigid disc mounted on a rigid rotor has four identical point masses, each of 10 grams, attached to four points on the 100 mm radius circle shown in the figure.
The rotor is driven by a motor at uniform angular speed of 10 rad/s. If one of the masses gets detached then the magnitude of the resultant unbalance force on the rotor is ______ N. (round off to 2 decimal places). [GATE ME 2020 SET-1]
Ans: 0.09 to 0.11
ω = 10rad/s, r = 100mm = 0.1m
If one mass is detached then
Now, unbalance tone, F = mrω2
= (10/1000) x 0.1 x (10)2 = (10×0.1×100)/1000
= 0.1 N
Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:In the gear train shown gear 3 is carried on arm 5, Gear 3 meshes with gear 2 and gear 4. The number of teeth on gear 2, 3 and 4 are 60, 20, and 100, respectively. If gear 2 is fixed and gear 4 rotates with an angular velocity of 100 rpm in the counterclockwise direction, the angular speed of arm 5 (in rpm) is
[2016,Set-1]
Explanation
Given T2 = 60
N2 = 0
T3 = 20
T4 = 100
N2 = 100 rpm (ccw)
Relative velocity equation

1.6Na = 100
Na = 62.5 rpm (ccw)
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:A gear train is made up of five spur gears as shown in the figure. Gear 2 is driver and gear 6 is driven member. N2, N3, N4, N5 and N6 represent number of teeth on gears 2,3,4,5 and 6 respectively. The gear(s) which act(s) as idler(s) is/are
[2015,Set-3]
Explanation
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:The number of degree of freedom of the planetary gear train shown in the figure is
[2015,Set-2]
Explanation
A planetary gear train has 2 DOF and hence requires two input to get desired output.
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:Gear 2 rotates at 1200 rpm is counter clockwise direction and engages with Gear 3 and Gear 4 mounted on the same shaft. Gear 5 engages with Gear 4. The numbers of teeth on Gears 2, 3, 4 and 5 are 20, 40, 15 and 30, respectively. The angular speed of Gear 5 is 
[2014,Set-3]
Explanation

⇒ N5 =1200 x 0.25 = 300 rpm ccw.
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:A compound gear train with gears P, Q, R and S has number of teeth 20,40,15 and 20 respectively.Gears Q and P are mounted on the same shaft as shown in the figure below. The diameter of the gear Q is twice that of the gear R. If the module of the gear R is 2 mm, the centre distance in mm between gears Pand S is
[2013]
Explanation
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:For the epicyclic gear arrangement shown in the figure, ω2 = 100 rad/s clockwise (cw) and ωarm = 80 rad/s counter clockwise (ccw). The angular velocity ω5 (in rad/s) is
[2010]
Explanation
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:An epicyclic gear train is shown schematically in the adjacent figure. The sun gear 2 on the input shaft is a 20 teeth external gear. The planet gear 3 is a 40 teeth external gear. The ring gear 5 is a 100 teeth internal gear. The ring gear 5 is fixed and the gear 2 is rotating at 60 rpm ccw(ccwcounterclockwise and cw- clockwise).
The arm 4 attached to the output shaft will rotate at
[2009]
Explanation
T2 = 20; T3 = 40; T5 = 100


Solving (1) and (2), we get
y + 5y = 60
⇒ y = 10 rpm ccw
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:The arm OA of a epicyclic gear train shown in figure revolves counter clockwise about Owith an angular velocity of 4 rad/s. Both gear are of same size. The angular velocity of gears C, if the sun gear B is fixed is
[1995]
Explanation

Given : y = – 4 [CCW]
N + y = 0 [Sun gear B is fixed]
∴ N = – y
= 4 rad/sec
Speed of gear C = – 4 – 4 = – 8 rad/sec.
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:The sun gear in the figure is driven clockwise at 100 rpm. The ring gear is held stationary. For the number of teeth shown on the gears, the arm rotates at
[1993]
Explanation
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:A spur gear has pitch circle diameter D and number of teeth T. The circular pitch of the gear is[2019,Set 2]
Explanation
Circular pitch, Pc = πD/T
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:A spur gear with 200 full depth teeth is transmitting 20 kW at 200 rad/s. The pitch circle diameter of the gear is 100 mm. The magnitude of the force applied on the gear in the radial direction is[2019, Set 1]
Explanation
Given : ϕ = 20°
P = 20 k W, ω = 200 r ad/s
Pitch Circle Diameter = 100 mm
Now, force on radial direction (Fr),


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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:It is desired to avoid interference in a pair of spur gears having a 20° pressure angle. With increase in pinion to gear speed ratio, the minimum number of teeth on the pinion[2014,Set-4]
Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:The following are the data for two crossed helical gears used for speed reduction:
Gear I : Pitch circle diameter in the plane of rotation 80 mm and helix angle 30°
Gear II : Pitch circle diameter in the plane of rotation 120 mm and helix angle 22.5°If the input speed is 1440 rpm, the output speed in rpm is
[2012]
Explanation
For helical gears

∴ N2 = 1440 x 0.625 = 900 rpm
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Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:Tooth interference in an external involute spur gear pair can be reduced by[2010]
Question for GATE Past Year Questions: Gears & Gear Trains
Try yourself:A 1.5 kW motor is running at 1440 rev/min. It is to be connected to a stirrer running at 36 rev/min. The gearing arrangement suitable for this application is[2000]
Explanation
Power of motor = 1.5 kW
N = 1440 rev/min
Speed of stirrer = 36 rev/min

∴ Worm gear is used.
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