In general, potential energy can be defined as the capacity for doing work that arises from position or configuration. In the electrical case, a charge will exert a force on any other charge and potential energy arises from any collection of charges. In this document, we will study electrical potential energy and its calculation in detail.
The electric potential energy of a system of point charges is defined as the work required to assemble this system of charges by bringing them close together, as in the system from an infinite distance.
There are two key elements on which the electric potential energy of an object depends:
The potential energy of a charge q in an external electric field E is different from the potential energy due to its own field. Here, E is generated by external sources, not by q itself. The external sources may be known or unspecified, and we focus only on the external field's influence on q. The charge q is assumed to have a negligible effect on the external field.
If q is brought from infinity (where potential is zero) to a point P in the external field, the work done to move q equals the potential energy of q at that point. The potential energy U of q at a distance vector r is given by:
U = qV(r)
where V(r) is the external potential at r.
For an electron (charge e=1.6×10−19C) moved through a 1-volt potential difference, it gains energy e × ΔV=1.6×10−19 J, which is called 1 electron volt (eV). This unit (eV) is commonly used in atomic and nuclear physics.
Example 1: Suppose we have a point charge Q=+5μC located in space. Calculate the electrical potential energy of this single charged particle at a distance of r=2m from it.
Sol:
The figure shows two + ve charges q1 and q2 separated by a distance r. The electrostatic interaction energy of this system can be expressed as work done in bringing charge q2 from infinity to the given separation from q1.
It can be calculated as
[ – ve sign shows that x is decreasing]
If the two charges are of opposite signs, then potential energy will be negative as:
Example 2: Suppose we have two point charges Q1 = +3μC and Q2=−4μC separated by a distance of d=1m. Calculate the electrical potential energy of this system.
Sol:
When more than two charged particles are there in a system, the interaction energy can be given as the sum of interaction energies of all the different possible pairs of particles. For example, if a system of three particles having charges q1, q2, and q3 is given as shown in figure.
The total interaction energy of this system can be given as:
Example 3: Suppose we have three point charges Q1=+2μC, Q2=−3μC, and Q3=+4μC arranged at the vertices of an equilateral triangle with sides of length d =1m. Calculate the electrical potential energy of this system.
Sol:
so, U = -10k
1. Inside a conductor, electrostatic field is zero
2. At the surface of a charged conductor, electrostatic field must be normal to the surface at every point
3. The interior of a conductor can have no excess charge in the static situation
4. Electrostatic potential is constant throughout the volume of the conductor and has the same value (as inside) on its surface
5. Electric field at the surface of a charged conductor
where is the surface charge density and is a unit vector normal to the surface in the outward direction
Just beneath the surface of the conductor, the electric field is zero, while just outside, it has a magnitude E perpendicular to the surface. The total electric flux through the pill box only comes from the external side, which equals EδS (positive if σ>0, negative if σ<0). Over the small area δS, E and δS are nearly parallel, so the charge enclosed by the pill box is σδS.
Applying Gauss's law:
Simplifying, we get:
E=σ/ϵ0
This equation indicates that the electric field is perpendicular to the surface, pointing outward if σ>0 and inward if σ<0.
6. Electrostatic Shielding
Electrostatic Shielding
Example 4: Assertion: A point charge is placed inside a cavity of the conductor as shown. Another point charge Q is placed outside the conductor as shown. Now as the point charge Q is pushed away from the conductor, the potential difference (VA – VB) between two points A and B within the cavity of sphere remains constant.
Reason: The electric field due to charge on the outer surface of the conductor and outside the conductor is zero at all points inside the conductor
A. Both Assertion and Reason are correct and the Reason is the correct explanation for Assertion
B. Both Assertion and Reason are correct and the Reason is not the correct explanation for Assertion
C. Assertion is correct but Reason is incorrect
D. Assertion is incorrect but Reason is correct
Sol: Option A. As we know that that the electric field inside the conductor is zero, so the field inside the conductor is constant. Therefore the potential between point A and B will remain constant.
Dielectrics are non-conducting substances. They are the insulating materials and are bad conductors of electric current. Dielectric materials can hold an electrostatic charge while dissipating minimal energy in the form of heat. Examples of dielectric are Mica, Plastics, Glass, Porcelain and Various Metal Oxides.
You must also remember that even dry air is also an example of a dielectric.
Dielectrics are of two types:
When we apply an external electric field in a non-polar molecule, all the protons travel towards the direction of the electric field and electrons in opposite direction. Due to the presence of an electric field, this process continues unless the internal forces balance them.
Due to this, there is a creation of two centres of charge. They are Polarised and we call them as the Induced Electric Dipole. The dipole moment is the Induced Electric Dipole Moment.
Applied field is directly proportional to induced dipole moment and is independent of the temperature. The direction of induced dipole moment (x) is parallel to the direction of electric field Ê and for a single polar atom. The Polarisability determines the dynamical response of a bound system to external fields.
It also provides an insight into a molecule‘s internal structure. In a solid, polarisability is the dipole moment per unit volume of the crystal cell:
where ‘a’ is the Atomic Polarisability. The S.I. unit of polarisability is m3 and its dimensions are the same as it’s volume.
When we place a dielectric slab is in an electric field, then the molecule gains the dipole moment. In such cases, we say that the dielectric is polarized. The Electric Polarisation is dipole moment per unit volume of a dielectric material. The polarisation is denoted by P.
PolarizationPolarization Process
When we place a dielectric slab between the parallel plates, the ratio of the applied electric field strength to the strength of the reduced value of electric field capacitor is the Dielectric Constant.
The formula is:
For an insulating material, the dielectric strength is the maximum electric field strength that it can withstand intrinsically without experiencing failure of its insulating properties.
When we apply an external electric field to a dielectric material, we get the Dielectric Polarisation. It is the displacement of charges (positive and negative) upon applying an electric field. The main task of the dielectric polarisation is to relate macroscopic properties to microscopic properties.
Polarisation occurs through the action of an electric field or other external factors, such as mechanical stress, as in the case of piezoelectric crystals. Piezoelectric crystals are those solid materials which accumulate electric charge within them.
Dielectric Polarisation can also arise spontaneously in pyroelectric crystals, particularly in ferroelectrics. Ferroelectricity is a property of certain materials that have a spontaneous electric polarisation that can be reversed by the application of an external electric field.
Example 5. Which of the following is/are non-polar dielectrics?
(a) HCl
(b) Water
(c) Benzene
(d) NH3
Sol: Option C – Benzene. Ammonia and HCl are polar molecules since they have a net dipole moment towards a particular direction. Both water and benzene are non-polar molecules. But water is a conductor of electricity, whereas benzene is a dielectric (insulator).
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1. What is electric potential energy and how is it defined in electrostatics? |
2. How do you calculate the potential energy of a system of two charged particles? |
3. What is the role of dielectrics in electric potential energy? |
4. How does the presence of an external electric field affect the potential energy of a charged particle? |
5. What is the significance of electrostatics in conductors and how does it relate to potential energy? |
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