Q.1. Subtract the first rational number from the second in each of the following:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
Ans.
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
Q.2. Evaluate each of the following:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)
(xi)
Ans.
(i)
(ii)
=
(iii)
(iv)
(v)
=
(vi)
=
(vii)
=
(viii)
(ix)
(x)
(xi)
Q.3. The sum of the two numbers is 5/9. If one of the numbers is 1/3, find the other.
Ans: It is given that the sum of two numbers is 5/9, where one of the numbers is 1/3.Let the other number be x.
⇒ x =
⇒ x =
⇒ x =
⇒ x =
Q.4. The sum of two numbers is. If one of the numbers is, find the other.
Ans: It is given that the sum of two numbers is , where one of the numbers is .Let the other number be x.
⇒ x =
⇒ x ==
Q.5. The sum of two numbers is −4/3. If one of the numbers is −5, find the other.
Ans: It is given that the sum of two numbers is −4/3, where one of the numbers is −5.Let the other number be x.
⇒ x =
⇒ x =
⇒ x =
⇒ x =
Q.6. The sum of two rational numbers is −8. If one of the numbers is, find the other.
Ans: It is given that the sum of two rational numbers is −8, where one of the numbers is .Let the other rational number be x.
⇒ x =
⇒ x =
Therefore, the other rational number is.
Q.7. What should be added to −7/8 so as to get 5/9?
Ans: Let x be added to −7/8 so as to get 5/9.
⇒x =
⇒x =
⇒x =
⇒x =
Q.8. What number should be added toso as to get?
Ans:
Let x be added.
⇒x =
⇒x =
⇒x =
⇒x =
⇒x =
Q.9. What number should be added to −5/7 to get −2/3?
Ans:
Let x be added.
⇒x =
⇒x =
⇒x =
⇒x =
⇒x =
Q.10. What number should be subtracted from −5/3 to get 5/6?
Ans:
Let x be subtracted
⇒ x =
⇒ x =
⇒ x =
Q.11. What number should be subtracted from 3/7 to get 5/4?
Ans:
Let, x be subtracted.
⇒ x =
⇒ x =
⇒ x =
Q.12. What should be added toto get?
Ans:
Let x be added.
⇒ x =
⇒ x =
⇒ x =
⇒ x =
Q.13. What should be added toto get 3?
Ans:
Let x be added.
= 3
= 3
⇒ x =
⇒ x =
⇒ x =
⇒ x =
Q.14. What should be subtracted fromto get?
Ans:
Let x be subtracted.
Q.15. Fill in the blanks:
(i)=......
(ii)= -1
(iii)= 3
(iv)= 4
Ans:
(i)
=
(ii)
⇒ x =
⇒ x =
⇒ x =
⇒ x =
⇒ x =
(iii)
⇒ x =
⇒ x =
⇒ x =
⇒ x =
⇒ x =
(iv)
⇒ x =
⇒ x =
⇒ x =
⇒ x =
Q.1. Simplify each of the following and write as a rational number of the form:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Ans:
(i)
=
=
=
(ii)
=
=
=
=
(iii)
=
=
=
(iv)
=
=
=
=
(v)
=
=
=
=
=
(vi)
=
=
=
=
Q.2. Express each of the following as a rational number of the form :
(i)
(ii)
(iii)
(iv)
(v)
Ans:
(i)
=
=
=
=
=
(ii)
=
=
=
=
(iii)
=
=
=
=
(iv)
=
=
=
=
(v)
=
=
=
=
Q.3. Simplify:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Ans:
(i)
Taking the L.C.M. of the denominators:
=
=
= 2
(ii)
Taking the L.C.M. of the denominators:
=
=
=
(iii)
Taking the L.C.M. of the denominators:
=
=
=
=
(iv)
Taking the L.C.M. of the denominators:
=
=
=
(v)
Taking the L.C.M. of the denominators:
=
=
=
(vi)
Taking the L.C.M. of the denominators:
=
=
=
=
Q.1. Multiply:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
Ans:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
Q.2. Multiply:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Ans:
(i)
=
(ii)
(iii)
(iv)
(v)
(vi)
Q.3. Simplify each of the following and express the result as a rational number in standard form:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
Ans:
(i)=
(ii)=
(iii)=
(iv)
(v)
(vi)
(vii)
(viii)
Q.4. Simplify:
(i)-
(ii) +
(iii) -
(iv)+
(v) +
(vi) -
(vii) -
(viii) +
Ans:
(i)-
(ii) +
(iii) -
(iv)+
=
=
=
=
(v) +
=
=
=
=
(vi) -
=
=
=
=
(vii) -
=
=
=
=
(viii) +
=
=
=
=
=
Q.5. Simplify:
(i)+−
(ii)−+
(iii)++
(iv)−+
Ans:
(i)+−
=
=
=
=
(ii)−+
=
=
=
(iii)++
=
=
=
=
(iv)−+
=
=
=
=
Q.1. Verify the property: x × y = y × x by taking:
(i) x =, y =
(ii) x =, y =
(iii) x =2, y =
(iv) x =0, y =
Ans: We have to verify that x × y = y × x.
(i) x =, y =
Hence verified.
(ii) x =, y =
Hence verified.
(iii) x =2, y =
Hence verified.
(iv) x =0, y =
Hence verified.
Q.2. Verify the property: x × (y × z) = (x × y) × z by taking:
(i) x =, y =, z =
(ii) x =0, y =, z =
(iii) x =, y =, z =
(iv) x =, y =, z =
Ans: We have to verify that x × (y × z)=(x × y) × z.
(i) x =, y =, z =
Hence verified.
(ii) x =0, y =, z =
Hence verified.
(iii) x =, y =, z =
Hence verified.
(iv) x =, y =, z =
Hence verified.
Q.3. Verify the property: x × (y + z) = x × y + x × z by taking:
(i) x =, y=, z=
(ii) x =, y=, z=
(iii) x =, y=, z=
(iv) x =, y=, z=
Ans: We have to verify that x × (y + z) = x × y + x × z.
(i) x =, y=, z=
=
=
=
Hence verified.
(ii) x =, y=, z=
=
=
=
Hence verified.
(iii) x =, y=, z=
=
=
=
Hence verified.
(iv) x =, y=, z=
=
=
= 1
Hence verified.
Q.4. Use the distributivity of multiplication of rational numbers over their addition to simplify:
(i)
(ii)
(iii)
(iv)
Ans:
(i)=
(ii)= = -6
(iii)= =
(iv) = =
Q.5. Find the multiplicative inverse (reciprocal) of each of the following rational numbers:
(i) 9
(ii) -7
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix) - 1
(x) 0/3
(xi) 1
Ans:
(i) Multiplicative inverse (reciprocal) of
(ii) Multiplicative inverse (reciprocal) of
(iii) Multiplicative inverse (reciprocal) of
(iv) Multiplicative inverse (reciprocal) of
(v) Multiplicative inverse (reciprocal) of
(vi) Multiplicative inverse (reciprocal) of
(vii) Multiplicative inverse (reciprocal) of
(viii) Multiplicative inverse (reciprocal) of
(ix) Multiplicative inverse (reciprocal) of
(x) Multiplicative inverse (reciprocal) of
(xi) Multiplicative inverse (reciprocal) of
Q.6. Name the property of multiplication of rational numbers illustrated by the following statements:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
Ans:
(i) Commutative property
(ii) Commutative property
(iii) Distributivity of multiplication over addition
(iv) Associativity of multiplication
(v) Existence of identity for multiplication
(vi) Existence of multiplicative inverse
(vii) Multiplication by 0
(viii) Distributive property
Q.7. Fill in the blanks:
(i) The product of two positive rational numbers is always .....
(ii) The product of a positive rational number and a negative rational number is always .....
(iii) The product of two negative rational numbers is always .....
(iv) The reciprocal of a positive rational number is .....
(v) The reciprocal of a negative rational number is .....
(vi) Zero has ..... reciprocal.
(vii) The product of a rational number and its reciprocal is .....
(viii) The numbers ..... and ..... are their own reciprocals.
(ix) If a is reciprocal of b, then the reciprocal of b is .....
(x) The number 0 is ..... the reciprocal of any number.
(xi) Reciprocal ofis .....
(xii) (17 × 12)−1 = 17−1 × .....
Ans:
(i) Positive
(ii) Negative
(iii) Positive
(iv) Positive
(v) Negative
(vi) No
(vii) 1
(viii) -1 and 1
(ix) a
(x) not
(xi) a
(xii) 12−1
Q.8. Fill in the blanks:
(i)
(ii)
(iii)
(iv)
Ans:
(i) −4
x × y = y × x (commutativity)
(ii)
x × y = y × x (commutativity)
(iii)
x × (y + z) = x × y + x × z (distributivity of multiplication over addition)
(iv)
x × (y × z) = (x × y) × z (associativity of multiplication)
Q.1. Divide:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)
Ans:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)
Q.2. Find the value and express as a rational number in standard form:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
Ans:
(i)=
(ii)=
(iii)=
(iv)=
(v)=
(vi)=
Q.3. The product of two rational numbers is 15. If one of the numbers is −10, find the other.
Ans: Let the other number be x.
∴ x × (−10) = 15
or x =
So, the other number is.
Q.4. The product of two rational numbers is. If one of the numbers is, find the other.
Ans: Let the other number be x.
or x =
or x =
or x =
Thus, the other number is.
Q.5. By what number should we multiplyso that the product may be?
Ans: Let the number be x.
x =
x =
Therefore, the other number is.
Q.6. By what number should we multiplyso that the product may be?
Ans: Let the other number be x.
or x =
or x =
or x =
Thus, the other number is .
Q.7. By what number should we multiplyso that the product may be 24?
Ans: Let the number be x.
or x =
or x =
or x = - 39
Thus, the number is −39.
Q.8. By what number shouldbe multiplied in order to produce?
Ans: Let the other number that should be multiplied with to produce be x.
or x =
or x =
or x =
Thus, the number is.
Q.9. Find (x + y) ÷ (x − y), if
(i) x =, y =
(ii) x =, y =
(iii) x =, y =
(iv) x =, y =
(v) x =, y =
Ans:
(i) x =, y =
(ii) x =, y =
(iii) x =, y =
(iv) x =, y =
(v) x =, y =
Q.10. The cost ofmetres of rope is Rs. Find its cost per metre.
Ans: The cost ofmetres of rope is Rs.
=
=
=
=
Q.11. The cost ofmetres of cloth is Rs. Find the cost of cloth per metre.
Ans: The cost ofmetres of cloth is Rs.
=
=
=
=
Thus, or Rs 32.25 is the cost of cloth per metre.
Q.12. By what number shouldbe divided to get?
Ans: Let the number be x.
Thus, the number is.
Q.13. Divide the sum ofandby the product ofand.
Ans:
=
=
=
=
Q.14. Divide the sum ofandby their difference.
Ans:
=
=
=
=
=
Q.15. If 24 trousers of equal size can be prepared in 54 metres of cloth, what length of cloth is required for each trouser?
Ans: Cloth needed to prepare 24 trousers=54 m
∴ Length of the cloth required for each trousers= 54÷24 = 54/24 = 9/4 m =metres.
Q.1. Find a rational number between −3 and 1.
Ans: Rational number between −3 and 1 == -1
Q.2. Find any five rational numbers less than 2.
Ans: We can write:
Integers less than 10 are 0, 1, 2, 3, 4, 5 ... 9.
Hence, five rational numbers less than 2 are.
Q.3. Find two rational numbers betweenand.
Ans: Since both the fractions (and) have the same denominator, the integers between the numerators(−2 and 5) are −1, 0, 1, 2, 3, 4.Hence, two rational numbers between and are 0/9 or 0 and 1/9.
Q.4. Find two rational numbers between 1/5 and 1/2.
Ans:
Rational number between=
Rational number between=
Therefore, two rational numbers betweenare
Q.5. Find ten rational numbers between 1/4 and 1/2.
Ans: The L.C.M of the denominators (2 and 4) is 4.
So, we can write 1/4 as it is.
Also,
As the integers between the numerators 1 and 2 of both the fractions are not sufficient, we will multiply the fractions by 20.
Between 20 and 40, there are 19 integers. They are 21, 22, 23, 24, 25, 26, 27....39, 40.
Thus,are the fractions.We can take any 10 of these.
Q.6. Find ten rational numbers betweenand.
Ans: L.C.M of the denominators (2 and 5) is 10.
We can write,
Since the integers between the numerators (−4 and 5 ) of both the fractions are not sufficient, we will multiply the fractions by 2.
There are 17 integers between −8 and 10, which are −7,−6,−5,−4...................8, 9.These can be written as:
We can take any 10 of these.
Q.7. Find ten rational numbers betweenand.
Ans: The L.C.M of the denominators 5 and 4 of both the fractions is 20.
We can write:
Since the integers between the numerators 12 and 15 are not sufficient, we will multiply both the fractions by 5.
There are 14 integers between 60 and 75. They are 61, 62, 63.......73 and 74.
Therefore,are the 14 fractions.
We can take any 10 of these.
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2. How can I simplify a rational number? |
3. Can a rational number have a decimal representation? |
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