Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7  >  RD Sharma Solutions: Integers (Exercise 1.2)

Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 PDF Download

Q.1. Divide:

(i) 102 by 17

(ii) −85 by 5

(iii) −161 by −23

(iv) 76 by −19

(v) 17654 by −17654

(vi) (−729) by (−27)

(vii) 21590 by −10

(viii) 0 by −135

Ans: 

(i) 102  ÷ 17 =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = 6

(ii) −85  ÷  5 = −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = − 17

(iii) −161  ÷ ( − 23)  = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7=  7

(iv) 76   ÷  − 19 =  −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = − 4

(v) 17654   ÷  (− 17654) =  − Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7|= −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= − 1

(vi) (−729)  ÷  (− 27) = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7=  27

(vii) 21590   ÷  − 10 = −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= − 2159

(viii) 0  ÷ (−135) = −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= −Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= 0


Q.2. Fill in the blanks:

(i) 296 ÷ ... = −148

(ii) −88 ÷ ... = 11

(iii) 84 ÷ ... = 12

(iv) ....... ÷ −5 = 25

(v) ....... ÷ 156 = −2

(vi) ....... ÷ 567 = −1

Ans: 

(i) 296  ÷ −148 = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= 2

∴ 296 ÷ (−2) = −148

(ii) − 88  ÷ 11 =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = - 8

∴ −88 ÷ −8 = 11

(iii) 84  ÷ 12 = Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = 7

(iv) 25 × (−5) = −125

∴ −125 ÷ −5 = 25

(v) 156 × (−2) = −312

∴ −312 ÷ 156 = −2

(vi) 567 × (−1) = −567

∴ −567 ÷ 567 = −1


Q.3. Which of the following statements are true?

(i) 0 ÷ 4 = 0

(ii) 0 ÷ (−7) = 0

(iii) −15 ÷ 0 = 0

(iv) 0 ÷ 0 = 0

(v) (−8) ÷ (−1) = −8

(vi) −8 ÷ (−2) = 4

Ans: 

(i)

LHS =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= 0

= RHS

Because LHS is equal to RHS, the equation is true.

(ii)

LHS =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= -0 = 0

= RHS

Because LHS is equal to RHS, the equation is true.

(iii)

LHS =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= Not defined
≠RHS

Because LHS is not equal to RHS, the equation is false.

(iv) 

LHS =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7= Not defined

≠RHS

Because LHS is not equal to RHS, the equation is false.

(v)

LHS =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = 8

≠ RHS

Because LHS and RHS are not equal, the equation is false.

(vi)

LHS =Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 = 4

= RHS 

Because LHS is equal to RHS, the equation is true.

The document Integers (Exercise 1.2) RD Sharma Solutions | Mathematics (Maths) Class 7 is a part of the Class 7 Course Mathematics (Maths) Class 7.
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FAQs on Integers (Exercise 1.2) RD Sharma Solutions - Mathematics (Maths) Class 7

1. What are integers?
Ans. Integers are whole numbers that can be positive, negative, or zero. They do not have any fractional or decimal part. Examples of integers include -3, 0, and 5.
2. How are integers represented on a number line?
Ans. Integers are represented on a number line by marking points at equal intervals. Positive integers are represented to the right of zero, while negative integers are represented to the left of zero. Zero itself is also an integer and is represented by a point on the number line.
3. What is the difference between positive and negative integers?
Ans. Positive integers are greater than zero and are represented by numbers like 1, 2, 3, etc. Negative integers are smaller than zero and are represented by numbers like -1, -2, -3, etc. The sign of the integer indicates its direction on the number line.
4. How can integers be added and subtracted?
Ans. Integers can be added by simply combining their numerical values. To subtract integers, we change the sign of the integer being subtracted and then add it to the other integer. This can be visualized on a number line as moving in the opposite direction.
5. Can integers be multiplied and divided?
Ans. Yes, integers can be multiplied and divided. When multiplying integers, the sign of the product depends on the signs of the integers being multiplied. In division, the sign of the quotient depends on the signs of the dividend and divisor.
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