CBSE Class 7  >  Class 7 Notes  >  Mathematics (Maths) (Old NCERT)  >  RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

Q.1. Compare the following fractions by using the symbol > or < or =:

(i)RD Sharma Solutions: Fractions (Exercise 2.1) 

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: First, we need to find the LCM of denominators in each case. After that, we will equate the denominators in order to compare the two fractions. 

(i) LCM of 9 and 13 is 117.

Now make both fraction equivalent with denominator as 117

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

we know 91 > 72

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii) both fraction have same denominator as 9

we know 11 > 5

RD Sharma Solutions: Fractions (Exercise 2.1)

(iii) LCM of 41 and 30 is 1230 

Now convert both fraction to their equivalent fractions with denominator as 1230

RD Sharma Solutions: Fractions (Exercise 2.1)

we know 

1110 > 779

RD Sharma Solutions: Fractions (Exercise 2.1)

(iv) LCM of 15 and 105 is 105.

Now convert fraction to its equivalent fractions with denominator as 105

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.2. Arrange the following fractions in ascending order:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)

LCM of the denominators 8, 6, 4 and 3 is 24.

Now, convert all fractions into their equivalent fractions with denominator 24.

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

We know:

8 < 9 < 12 < 18 < 20

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)

LCM of the denominators 8, 12, 16 and 3 is 48.

Now, convert all fractions into their equivalent fractions with denominator 48.

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

we know

15 < 18 < 24 < 64

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.3. Arrange the following fractions in descending order:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)

LCM of the denominators 5, 10, 15 and 20 is 60.

Now, convert all fractions to their equivalent fractions with denominator 60.

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

We know:

51 > 48 > 44 > 42

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)

LCM of the denominators 7, 35, 14 and 28 is 140.

Now, convert all fractions to their equivalent fractions with denominator 140.

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

We know:

90 > 65 > 44  > 40

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.4. Write five equivalent fractions ofRD Sharma Solutions: Fractions (Exercise 2.1).

Ans: Five equivalent fractions ofRD Sharma Solutions: Fractions (Exercise 2.1)  are:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(v)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.5. Find the sum:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.1) 

LCM of 8,10  is 40.

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 5,4 is 20.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.1) 

LCM of 6,4 is 24.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)

RD Sharma Solutions: Fractions (Exercise 2.1) orRD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 15,10 and 5 is 30.

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.6. Find the difference of

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 24 and 16 is 48.

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 3 and 1 is 3.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 20,25 is 100.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 10 and 15 is 30.

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.7. Find the difference:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.1) 

LCM of 7 and 11 is 77.

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.1) 

LCM of 1 and 9 is 9.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 1 and 3 is 3.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iv)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 10 and 15 is 30.

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.8. Simplify:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.1) 

LCM of 3.6 and 9 is 18.

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 2 and 1 is 2.

RD Sharma Solutions: Fractions (Exercise 2.1)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 6,8 and 12 is 24.

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.9. What should be added toRD Sharma Solutions: Fractions (Exercise 2.1)to get 12?

Ans: 

Let x be the required fraction.

According to the question:

RD Sharma Solutions: Fractions (Exercise 2.1)

 RD Sharma Solutions: Fractions (Exercise 2.1)

 RD Sharma Solutions: Fractions (Exercise 2.1)

 RD Sharma Solutions: Fractions (Exercise 2.1)


Q.10. What should be added toRD Sharma Solutions: Fractions (Exercise 2.1)to getRD Sharma Solutions: Fractions (Exercise 2.1)?

Ans: 

Let x be the required fraction.

According to the question:

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

LCM of 5 and 15 is 15.

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.11. Suman studies forRD Sharma Solutions: Fractions (Exercise 2.1)hours daily. She devotesRD Sharma Solutions: Fractions (Exercise 2.1)hours of her time for Science and Mathematics. How much time does she devote for other subjects?

Ans: Suman studies forRD Sharma Solutions: Fractions (Exercise 2.1) hours daily. Therefore, we have

RD Sharma Solutions: Fractions (Exercise 2.1) hours = RD Sharma Solutions: Fractions (Exercise 2.1)

She studies science and mathematics forRD Sharma Solutions: Fractions (Exercise 2.1)hours. Therefore, we have

RD Sharma Solutions: Fractions (Exercise 2.1)hours = RD Sharma Solutions: Fractions (Exercise 2.1)

Time devoted to other subjects = Total study time - Time devoted to science and mathematics 

=RD Sharma Solutions: Fractions (Exercise 2.1)= RD Sharma Solutions: Fractions (Exercise 2.1)

= RD Sharma Solutions: Fractions (Exercise 2.1)


Q.12. A piece of wire is of lengthRD Sharma Solutions: Fractions (Exercise 2.1)m. If it is cut into two pieces in such a way that the length of one piece isRD Sharma Solutions: Fractions (Exercise 2.1)m, what is the length of the other piece?

Ans: Let the length of second piece be x.

Total length of wire = Length of one piece + Length of second piece

RD Sharma Solutions: Fractions (Exercise 2.1)

 RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)


Q.13. A rectangular sheet of paper isRD Sharma Solutions: Fractions (Exercise 2.1)cm long andRD Sharma Solutions: Fractions (Exercise 2.1)cm wide. Find its perimeter.

Ans: 

Perimeter of rectangle = 2(length + width)

RD Sharma Solutions: Fractions (Exercise 2.1)

=RD Sharma Solutions: Fractions (Exercise 2.1)

=RD Sharma Solutions: Fractions (Exercise 2.1)

=RD Sharma Solutions: Fractions (Exercise 2.1)

=RD Sharma Solutions: Fractions (Exercise 2.1)cm


Q.14. In a "magic square", the sum of the numbers in each row, in each column and along the diagonal is the same. Is this a magic  square?

4/119/112/11
3/115/117/11
8/111/116/11

Ans: Sum along columns and rows:

RD Sharma Solutions: Fractions (Exercise 2.1)

Sum along diagonals :

RD Sharma Solutions: Fractions (Exercise 2.1)

Since, all the sums in the square   are equal along rows,columns and diagonals,it is a magic square.


Q.15. The cost of Mathematics book is RsRD Sharma Solutions: Fractions (Exercise 2.1) and that of Science book is RsRD Sharma Solutions: Fractions (Exercise 2.1). Which costs more and by how much? 

Ans: Cost of mathematics book =RD Sharma Solutions: Fractions (Exercise 2.1)

Cost of Science book =RD Sharma Solutions: Fractions (Exercise 2.1)

We know        

82 < 103

RD Sharma Solutions: Fractions (Exercise 2.1)

Thus, Mathematics book costs more.Difference in the cost of Mathematics and Science book = cost of Mathematics book-Cost of Science book

=RD Sharma Solutions: Fractions (Exercise 2.1)

=RD Sharma Solutions: Fractions (Exercise 2.1) = = RsRD Sharma Solutions: Fractions (Exercise 2.1)

So, Mathematics book costs more by RsRD Sharma Solutions: Fractions (Exercise 2.1)


Q.16. (i) Provide the number in boxRD Sharma Solutions: Fractions (Exercise 2.1)and also give its simplest from in each of the following:

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

Ans: 

(i)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

(ii)RD Sharma Solutions: Fractions (Exercise 2.1)

RD Sharma Solutions: Fractions (Exercise 2.1)

The document RD Sharma Solutions: Fractions (Exercise 2.1) is a part of the Class 7 Course Mathematics (Maths) Class 7 (Old NCERT).
All you need of Class 7 at this link: Class 7

FAQs on RD Sharma Solutions: Fractions (Exercise 2.1)

1. What are fractions?
Ans. Fractions are numbers that represent a part of a whole. They consist of a numerator and a denominator, where the numerator represents the number of equal parts considered and the denominator represents the total number of equal parts in the whole.
2. How do you add fractions with different denominators?
Ans. To add fractions with different denominators, first find a common denominator by finding the least common multiple (LCM) of the denominators. Then, convert each fraction so that they have the same denominator. Finally, add the numerators together and keep the common denominator unchanged.
3. How do you simplify fractions?
Ans. To simplify a fraction, find the greatest common divisor (GCD) of the numerator and denominator. Divide both the numerator and denominator by their GCD to get the simplest form of the fraction.
4. Can fractions be converted into decimals?
Ans. Yes, fractions can be converted into decimals. To convert a fraction into a decimal, divide the numerator by the denominator using long division or a calculator. The resulting decimal may either terminate (such as 0.5) or be a repeating decimal (such as 0.333...).
5. How do you compare fractions?
Ans. To compare fractions, make sure they have the same denominator. If they don't, find a common denominator by finding the LCM. Then, compare the numerators of the fractions. The fraction with the larger numerator is greater, while the fraction with the smaller numerator is smaller.
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