CBSE Class 7  >  Class 7 Notes  >  Mathematics (Maths) (Old NCERT)  >  RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

Q.1. Multiply:

(i)RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iv)RD Sharma Solutions: Fractions (Exercise 2.2)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

 RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

(iv)

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)


Q.2. Find the product:

(i)RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iv)RD Sharma Solutions: Fractions (Exercise 2.2)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.2) =RD Sharma Solutions: Fractions (Exercise 2.2)

 RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.2)

 RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.2)

 RD Sharma Solutions: Fractions (Exercise 2.2)

(iv)

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)


Q.3. Simplify:

(i)RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)

Ans: 

(i)

RD Sharma Solutions: Fractions (Exercise 2.2)  RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)

RD Sharma Solutions: Fractions (Exercise 2.2) RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)

RD Sharma Solutions: Fractions (Exercise 2.2)  RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)


Q.4. Find:

(i)RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)

Ans: 

(i)RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)= RD Sharma Solutions: Fractions (Exercise 2.2)

=RD Sharma Solutions: Fractions (Exercise 2.2)


Q.5. Which is greater?RD Sharma Solutions: Fractions (Exercise 2.2)

Ans: 

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

convert 2/7 to its equivalent fraction with denominator as 14

RD Sharma Solutions: Fractions (Exercise 2.2)

we know 6 > 4

 RD Sharma Solutions: Fractions (Exercise 2.2)

 RD Sharma Solutions: Fractions (Exercise 2.2)


Q.6. Find:

(i)RD Sharma Solutions: Fractions (Exercise 2.2)

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)

(iv)RD Sharma Solutions: Fractions (Exercise 2.2)

(v)RD Sharma Solutions: Fractions (Exercise 2.2)

(vi)RD Sharma Solutions: Fractions (Exercise 2.2)

(vii)RD Sharma Solutions: Fractions (Exercise 2.2)

(viii)RD Sharma Solutions: Fractions (Exercise 2.2)

(ix)RD Sharma Solutions: Fractions (Exercise 2.2)

Ans: 

(i)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

⇒ Rs 210

(ii)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

⇒ 60 metres

(iii)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

⇒ 18 litres

(iv)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

1 hour =60 minutes

RD Sharma Solutions: Fractions (Exercise 2.2)

(v)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

1 year =12 months

RD Sharma Solutions: Fractions (Exercise 2.2)

(vi)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

1 kg =1000 g

RD Sharma Solutions: Fractions (Exercise 2.2)

(vii)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

1 l =1000 ml

RD Sharma Solutions: Fractions (Exercise 2.2)

(viii)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

1 day =24 hours

RD Sharma Solutions: Fractions (Exercise 2.2)

(ix)RD Sharma Solutions: Fractions (Exercise 2.2)=RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

1 week =7 days

RD Sharma Solutions: Fractions (Exercise 2.2)


Q.7. Shikha plants 5 saplings in a row in her garden. The distance between two adjacent saplings is 3/4m. Find the distance between the first and the last sapling.

Ans:

Distance between the first and second saplings = RD Sharma Solutions: Fractions (Exercise 2.2)m

Distance between the first and third saplings = RD Sharma Solutions: Fractions (Exercise 2.2)

Distance between the first and fourth saplings = RD Sharma Solutions: Fractions (Exercise 2.2)

Distance between the first and fifth saplings  = RD Sharma Solutions: Fractions (Exercise 2.2)


Q.8. Ravish readsRD Sharma Solutions: Fractions (Exercise 2.2)part of a book in 1 hour. How much part of the book will he read inRD Sharma Solutions: Fractions (Exercise 2.2)hours?

Ans: 

RD Sharma Solutions: Fractions (Exercise 2.2)

In 1 hour Ravish readsRD Sharma Solutions: Fractions (Exercise 2.2)  of the book

Part of book Ravish will read in RD Sharma Solutions: Fractions (Exercise 2.2)hours = Part read in 1 hour ×RD Sharma Solutions: Fractions (Exercise 2.2)

Part of book Ravish will read in RD Sharma Solutions: Fractions (Exercise 2.2)hours = RD Sharma Solutions: Fractions (Exercise 2.2)


Q.9. Lipika reads a book forRD Sharma Solutions: Fractions (Exercise 2.2)hours everyday. She reads the entire book in 6 days. How many hours in all were required by her to read the book?

Ans: 

In one day, Lipika reads forRD Sharma Solutions: Fractions (Exercise 2.2) 134hours.

RD Sharma Solutions: Fractions (Exercise 2.2)

Total hours required =RD Sharma Solutions: Fractions (Exercise 2.2)= RD Sharma Solutions: Fractions (Exercise 2.2)= RD Sharma Solutions: Fractions (Exercise 2.2)


Q.10. Find the area of a rectangular park which isRD Sharma Solutions: Fractions (Exercise 2.2)m long andRD Sharma Solutions: Fractions (Exercise 2.2)m broad.

Ans: 

Length of rectangular park =RD Sharma Solutions: Fractions (Exercise 2.2)

⇒Length of rectangular park =RD Sharma Solutions: Fractions (Exercise 2.2)

Width of rectangular park =RD Sharma Solutions: Fractions (Exercise 2.2)

⇒Width of rectangular park =RD Sharma Solutions: Fractions (Exercise 2.2)

Area of rectangular park = Length of rectangular park × Width of rectangular park

Area of rectangular park =RD Sharma Solutions: Fractions (Exercise 2.2)= 775m2


Q.11. If milk is available at RsRD Sharma Solutions: Fractions (Exercise 2.2)per litre, find the cost ofRD Sharma Solutions: Fractions (Exercise 2.2)litres of milk.

Ans: 

Cost of 1 litre milk = Rs.RD Sharma Solutions: Fractions (Exercise 2.2) 

RD Sharma Solutions: Fractions (Exercise 2.2) = RD Sharma Solutions: Fractions (Exercise 2.2)

⇒Cost of 1 litre milk = Rs.RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

Cost ofRD Sharma Solutions: Fractions (Exercise 2.2)litres milk = Cost of 1 litre milk × RD Sharma Solutions: Fractions (Exercise 2.2)

Cost ofRD Sharma Solutions: Fractions (Exercise 2.2)litres milk =RD Sharma Solutions: Fractions (Exercise 2.2)= Rs.RD Sharma Solutions: Fractions (Exercise 2.2)= Rs.RD Sharma Solutions: Fractions (Exercise 2.2)


Q.12. Sharda can walkRD Sharma Solutions: Fractions (Exercise 2.2)km in one hour. How much distance will she cover inRD Sharma Solutions: Fractions (Exercise 2.2) hours?

Ans: 

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

Distance covered by Sharda in 1 hour =RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

Distance covered by Sharda inRD Sharma Solutions: Fractions (Exercise 2.2)hours = Distance covered in 1 hour ×RD Sharma Solutions: Fractions (Exercise 2.2)

⇒ Distance covered by Sharda in RD Sharma Solutions: Fractions (Exercise 2.2)hours =RD Sharma Solutions: Fractions (Exercise 2.2)=20 km


Q.13. A sugar bag contains 30 kg of sugar. After consuming 2/3 of it, how much sugar is left in the bag?

Ans: Total amount of sugar in the bag = 30 kg

RD Sharma Solutions: Fractions (Exercise 2.2)

⇒Amount of sugar consumed = 20 kg

Sugar left in the bag = Total amount of sugar in the bag - Amount of sugar consumed Sugar left in the bag = 30-20 =10 kg


Q.14. Each side of a square isRD Sharma Solutions: Fractions (Exercise 2.2) m long. Find its area.

Ans: 

RD Sharma Solutions: Fractions (Exercise 2.2)

RD Sharma Solutions: Fractions (Exercise 2.2)

Area of square = Side × Side

Area of square =RD Sharma Solutions: Fractions (Exercise 2.2)

⇒Area of square = RD Sharma Solutions: Fractions (Exercise 2.2)


Q.15. There are 45 students in a class and 3/5 of them are boys. How many girls are there in the class?

Ans: 

RD Sharma Solutions: Fractions (Exercise 2.2)

Therefore, 27 students are boys. 

Number of girls=Total number of students in the class - Number of boys

Number of girls = 45 - 27 = 18

Therefore, 18 students are girls.

The document RD Sharma Solutions: Fractions (Exercise 2.2) is a part of the Class 7 Course Mathematics (Maths) Class 7 (Old NCERT).
All you need of Class 7 at this link: Class 7

FAQs on RD Sharma Solutions: Fractions (Exercise 2.2)

1. What is the concept of fractions?
Ans. Fractions represent a part of a whole or a number that is not a whole. They are written in the form of a numerator (the number above the line) and a denominator (the number below the line), separated by a fraction bar.
2. How do you add fractions with different denominators?
Ans. To add fractions with different denominators, first find a common denominator by finding the least common multiple (LCM) of the denominators. Then, convert each fraction to an equivalent fraction with the common denominator. Finally, add the numerators of the fractions and keep the common denominator.
3. Can fractions be simplified?
Ans. Yes, fractions can be simplified. To simplify a fraction, find the greatest common divisor (GCD) of the numerator and denominator, and then divide both the numerator and denominator by the GCD. The simplified fraction will have the same value as the original fraction.
4. How do you multiply fractions?
Ans. To multiply fractions, multiply the numerators together and multiply the denominators together. Simplify the resulting fraction if possible.
5. What is a mixed fraction?
Ans. A mixed fraction is a combination of a whole number and a fraction. It is written in the form of a whole number followed by a fraction. For example, 3 1/2 is a mixed fraction, where 3 is the whole number and 1/2 is the fraction part.
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