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RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7 PDF Download

Q.1. Which of the following is a vulgar fraction?
(a) 3/10
(b) 13/10

(c) 10/3
(d) none of these
Ans.
(c) 10/3
10/3 is a vulgar fraction, because its denominator is other than 10, 100, 1000, etc.

Q.2. Which of the following is an improper fraction?
(a) 7/10

(b) 7/9
(c) 9/7
(d) none of these
Ans.
(c) 9/7
9/7 is an improper fraction, because its numerator is greater than its denominator.

Q.3. Which of the following is a reducible fraction?
(a) 105/112
(b) 104/121
(c) 77/72
(d) 46/63
Ans. 
(a) 105/112
A fraction that is reducible can be reduced by dividing both the numerator and denominator by a common factor.
(105÷7)/(112÷7) =15/16
Thus, 105/112 is a reducible fraction.

Q.4. 2/3, 4/6, 6/9, 8/12 are
(a) like fractions
(b) irreducible fractions
(c) equivalent fractions
(d) none of these
Ans.
(c) equivalent fractions
Equivalent fractions are those which are the same but look different.
Thus, 2/3, 4/6=2/3, 6/9=2/3, 8/12=2/3 are equivalent fractions.

Q.5. Which of the following statements is true?
(a) 9/16 = 13/24
(b) 9/16 < 13/24
(c) 9/16 > 13/24
(d) none of these
Ans.
(c) 9/16 > 13/24
The two fraction are 9/16 and 13/24.
By cross multiplication, we have:
9 × 24 = 216 and 13 × 16 = 208
However, 216 > 208
∴ 9/16 > 13/24

Q.6. Reciprocal ofRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7is
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

(b)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(d) none of these
Ans.
(d) none of these
Reciprocal ofRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7= Reciprocal of 7/4 = 4/7

Q.7. (3/10+8/15)=?
(a) 11/10

(b) 11/15
(c) 5/6
(d) none of these
Ans.
(c) 5/6
(3/10+8/15) =(9+16) / 30 [∵ LCM of 10 and 15 = 30]
= 25/30
= 5/6

Q.8.RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7= ?
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

(b) 1/12
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

(d) 11/12
Ans.
(d) 11/12
RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7= (13/4−7/3)
= (39−2812)39-2812 [∵ LCM of 4 and 3 = 12]
= 11/12

Q.9. 36÷1/4=?
(a) 9

(b) 1/9
(c) 1/144
(d) 144
Ans.
(d) 144
36÷1/4=36×4 [∵ Reciprocal of 1/4 = 4]
= 144

Q.10. By what number shouldRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7be multiplied to getRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7?
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(b) 5/7
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(d) 1/7
Ans.
(b) 5/7
Required number =RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
= 13/7÷13/5
= 13/7×5/13 [∵ Reciprocal of 13/5 = 5/13]
= 5/7

Q.11. By what number shouldRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7be divided to get 2/3?
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(b)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(c) 4/9
(d)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
Ans. (d)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
Required number =RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7÷2/3
= 3/2÷2/3
= 3/2×3/2 [∵ Reciprocal of 2/3 = 3/2]
= 9/4
=RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

Q.12.RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7 ÷2/3=?
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

(b)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(d) none of these
Ans.
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7÷2/3=8/5÷2/3
= 8/5×3/2 [∵ Reciprocal of 2/3 = 3/2]
= (4×3)/5
= 12/5
=RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

Q.13.RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7= ?
(a) 1

(b) 2
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(d)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
Ans. (d)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7= 11/5÷6/5
= 11/5×5/6 [∵ Reciprocal of 6/5 = 5/6]
= 11/6
=RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

Q.14. The reciprocal ofRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7is
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7

(b)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7
(d) 3/5
Ans. 
(d) 3/5
Reciprocal of 123123 = Reciprocal of 5353 = 3535

Q.15. Which one of the following is the correct statement?
(a) 2/3 < 3/5 < 14/15
(b) 3/5 < 2/3 < 14/15
(c) 14/15 < 3/5 < 2/3
(d) none of these
Ans.
(b) 3/5 < 2/3 < 14/15
The given fractions are 3/5, 2/3 and14/15.
LCM of 5, 3 and 15 = 15
Now, we have:
2/3×5/5=10/15, 3/5×3/3=9/15 and 14/15×1/1=14/15
Clearly, 9/15 <10/15<14/15
∴ 3/5 < 2/3 < 14/15

Q.16. A car runs 16 km using 1 litre of petrol. How much distance will it cover inRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7litres of petrol?
(a) 24 km
(b) 36 km
(c) 44 km
(d)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7km
Ans. (c) 44 km
Distance covered by the car onRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7L of petrol =(16 ×RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7) km
= (16 × 11/4) km
= (4 × 11) km = 44 km

Q.17. Lalit reads a book forRS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7hours every day and reads the entire book in 6 days. How many hours does he take to read the entire book?
(a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7hours

(b)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7hours
(c)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7hours
(d)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7hours
Ans. (a)RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7hours
Time taken by Lalit to read the entire book = (6 × RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7) h
= (6×7/4) h
= (21/2) h
=RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7h

The document RS Aggarwal Solutions: Integers (Exercise 2D) | Mathematics (Maths) Class 7 is a part of the Class 7 Course Mathematics (Maths) Class 7.
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