Torsion

A shaft is said to be under pure torsion when it is subjected to two equal and opposite couples in a plane perpendicular to the longitudinal axis of the shaft (that is, twisting couples) so that the magnitude of the twisting moment remains constant along the length of the shaft. The twisting moment (or torque) is the product of the force and the perpendicular distance between the pair of forces.

Torque T = p × d

Magnitude and representation of Torque Magnitude and representation of Torque 

Figure shows a bar or shaft of circular section subjected to torque T. Such a case is one of pure torsion.

Shaft is under pure torsionShaft is under pure torsion
Torsion

Note: J/R is known as the torsional section modulus. GJ is known as the torsional rigidity of the bar or shaft. The relation for shear stress under pure torsion shows that the intensity of shear stress at any point in the cross-section is proportional to its radial distance from the centre; the variation with radial distance is linear.

Variation of Torsional Shear Stress Variation of Torsional Shear Stress 

Basic Relations for a Circular Shaft under Torsion

Shear stress distribution and internal torque

Consider a circular shaft of cross-sectional area A, subjected to an external torque T. The internal resisting couple is the result of shear stresses distributed over the cross-section. Equating internal resisting moment to the applied torque gives the fundamental relation:

τ(r) = T·r / J

where τ(r) is the shear stress at a radial distance r from the centre, and J is the polar moment of inertia (also called polar second moment, or polar moment) of the cross-section about the shaft axis. This relation implies that shear stress is zero at r = 0 and increases linearly to a maximum at the outer radius.

Angle of twist

The angle of twist θ (in radians) of a shaft of length L carrying a torque T is

θ = T L / G J

where G is the modulus of rigidity (shear modulus). This formula is valid for prismatic (constant cross-section) shafts made of linearly elastic, homogeneous material under small deformations.

Polar Moment of Inertia (J)

Polar moment J measures a section's resistance to torsion. For circular sections the standard expressions are:

Solid circular shaft

Solid circular shaft

For a solid circular shaft of diameter d (or radius R = d/2),

J = π d^4 / 32 = π R^4 / 2

Solid circular shaft

Hollow circular shaft

Hollow circular shaft

For a hollow circular shaft with outer diameter D and inner diameter d,

J = π (D^4 - d^4) / 32

Torsional Section Modulus and Maximum Shear Stress

The torsional section modulus Z is defined as

Z = J / c

where c is the outer radius (distance from neutral axis to extreme fibre). The maximum shear stress at the outer surface is

τ_max = T / Z = T·c / J

Shear Stress Distribution in Different Sections

The shear stress distribution for circular shafts is:

  • Solid circular section - shear stress is zero at the centre and increases linearly with radius to a maximum at the outer surface.
  • Hollow circular section - shear stress is minimum at the inner radius and increases linearly to a maximum at the outer radius; there is no shear stress in the hole region.
Shear Stress Distribution in Different Sections
Shear Stress Distribution in Different Sections

Power Transmitted by a Shaft

When a shaft rotates at N revolutions per minute (rpm) and transmits torque T (in N·m), the power P (in watts) transmitted is

P = 2π N T / 60

Power Transmitted by a Shaft

In SI units, P (W) = T (N·m) × angular speed ω (rad/s), where ω = 2πN/60.

Design of Shafts - Limiting Torque from Allowable Shear

In shaft design the resisting couple developed by internal shear stresses must equal the applied torque. Using τ_max = T·c / J, the maximum torque that can be transmitted safely (based on an allowable shear stress τ_allow) is

T_max = τ_allow · J / c

Design of Shafts - Limiting Torque from Allowable Shear

Maximum Torque Transmitted by a Circular Shaft

  1. Circular solid shaft

    The maximum torque transmitted by a circular solid shaft is obtained from the maximum shear stress induced at the outer surface. Substituting J for a solid shaft gives a direct expression for T_max in terms of diameter and allowable shear.

    Maximum Torque Transmitted by a Circular Shaft
  2. Hollow circular shaft

    Torque transmitted by a hollow circular shaft is obtained in the same way as for a solid shaft by using the polar moment of inertia for a hollow section. Hollow shafts are commonly used when weight or material economy is important because they provide higher torsional rigidity per unit weight in many practical cases.

    Maximum Torque Transmitted by a Circular Shaft

Composite Shafts

A composite shaft consists of two or more shaft segments of different materials, diameters or lengths joined together. Two important connection types are:

  • Series connection - shafts are arranged end-to-end so that each segment carries the same torque.
  • Parallel connection - shafts are arranged so that the angle of twist of each shaft is the same (they act in parallel to share torque).

Series connection

When shafts are in series, the torque in each segment is equal to the applied torque. The total angle of twist is the sum of the twists of each segment. For two shafts in series, with the same torque T, lengths L1 and L2, moduli G1 and G2, and polar moments J1 and J2:

θ_AC = θ_AB + θ_BC

and

θ_total = T L1 / (G1 J1) + T L2 / (G2 J2)

Series connection
Series connection

Parallel connection

For shafts loaded so that their angle of twist is the same, torque is shared between the parallel members. The total torque is the sum of individual torques and equality of angles of twist gives a relation between the individual torques:

T = T1 + T2

θ1 = θ2

From θ = T L / G J, we obtain

T1 L1 / (G1 J1) = T2 L2 / (G2 J2)

Parallel connection

Strain Energy Stored in a Shaft under Torsion

The torsional strain energy stored in a shaft is equal to the work done in twisting it from zero torque to the final torque T. For a shaft of length L:

Work done = ∫0^T T' dθ = 1/2 T θ

Using θ = T L / (G J) leads to

U = 1/2 · T · θ = T^2 L / (2 G J) = (G J θ^2) / (2 L)

Strain Energy Stored in a Shaft under Torsion
Strain Energy Stored in a Shaft under Torsion
Strain Energy Stored in a Shaft under Torsion

Torsional Stiffness

Torsional stiffness (denoted K) is the torque required to produce a unit radian twist. For a prismatic shaft of length L:

θ = T L / (G J)

so

K = G J / L

and

T = K θ

Practical Remarks and Applications

  • Shafts in machinery (shafts for motors, gearboxes, axles) are almost always designed using the relations above to ensure the permissible shear stress and permissible angle of twist are not exceeded.
  • Hollow shafts are used to reduce weight while retaining torsional rigidity. For the same material and outer diameter, an optimally chosen hollow shaft can transmit similar torque with less material than a solid shaft.
  • When shafts are subjected to combined bending and torsion, interaction theories (like maximum distortion energy or von Mises) are used for safe design; the pure torsion formulas apply to the torsional component of stress only.
  • Torsional vibration, stress concentrations near shoulders, keyways and fillets, and fatigue under cyclic torque must be considered in detailed design; the basic formulas provide the elastic behaviour and strength limits for static design.

Summary: For circular shafts under pure torsion the central relations are τ(r) = T·r / J, θ = T L / (G J), J expressions for the section (solid or hollow), torsional section modulus Z = J/c, strain energy U = T^2 L / (2 G J) and torsional stiffness K = G J / L. These formulae form the foundation for analysis and design of shafts in civil, mechanical and allied engineering applications.

The document Torsion is a part of the Mechanical Engineering Course Strength of Materials (SOM).
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FAQs on Torsion

1. What is torsion in mechanical engineering?
Ans. Torsion in mechanical engineering refers to the twisting or rotational deformation of a structural element, usually caused by the application of torque. It occurs when a torque is applied to one end of a component while the other end is fixed or restrained, resulting in shear stresses and angular deflection within the material.
2. How is torsion calculated in mechanical engineering?
Ans. Torsion can be calculated in mechanical engineering using the torsion formula, also known as the torsion equation. This equation relates the applied torque (T), the length of the component (L), the polar moment of inertia (J), and the angle of twist (θ). The torsion formula is given as τ = (T * L) / (J * G), where τ represents the shear stress, G is the shear modulus of the material, and θ is the angle of twist.
3. What are some common applications of torsion in mechanical engineering?
Ans. Torsion finds numerous applications in mechanical engineering. Some common examples include the design of shafts and axles in machinery, such as engines and turbines, where torsional strength and rigidity are essential. Torsion is also important in the design of springs, such as torsion springs used in garage doors or clock mechanisms. Additionally, torsion is considered in the design of structures subjected to wind or seismic loads.
4. How does material selection affect torsion in mechanical engineering?
Ans. Material selection plays a crucial role in determining the behavior of a component under torsional load in mechanical engineering. Different materials have varying shear moduli (G), which directly influences the resistance to torsional deformation. Stiffer materials with higher shear moduli, such as steel, exhibit lower angles of twist and are more resistant to torsion. Softer materials, on the other hand, have higher angles of twist and are less resistant to torsional deformation.
5. What are the possible failure modes associated with torsion in mechanical engineering?
Ans. Torsion can lead to several failure modes in mechanical engineering. One common failure mode is shear failure, where excessive shear stress causes the material to fracture along planes perpendicular to the axis of the component. Another failure mode is excessive angle of twist, which can cause a component to deform beyond its allowable limits, resulting in functional failure or even structural collapse. Additionally, fatigue failure due to repeated torsional loading can occur, leading to crack initiation and propagation within the material.
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