A shaft is said to be under pure torsion when it is subjected to two equal and opposite couples in a plane perpendicular to the longitudinal axis of the shaft (that is, twisting couples) so that the magnitude of the twisting moment remains constant along the length of the shaft. The twisting moment (or torque) is the product of the force and the perpendicular distance between the pair of forces.
Torque T = p × d
Magnitude and representation of Torque Figure shows a bar or shaft of circular section subjected to torque T. Such a case is one of pure torsion.
Shaft is under pure torsion
Note: J/R is known as the torsional section modulus. GJ is known as the torsional rigidity of the bar or shaft. The relation for shear stress under pure torsion shows that the intensity of shear stress at any point in the cross-section is proportional to its radial distance from the centre; the variation with radial distance is linear.
Variation of Torsional Shear Stress Consider a circular shaft of cross-sectional area A, subjected to an external torque T. The internal resisting couple is the result of shear stresses distributed over the cross-section. Equating internal resisting moment to the applied torque gives the fundamental relation:
τ(r) = T·r / J
where τ(r) is the shear stress at a radial distance r from the centre, and J is the polar moment of inertia (also called polar second moment, or polar moment) of the cross-section about the shaft axis. This relation implies that shear stress is zero at r = 0 and increases linearly to a maximum at the outer radius.
The angle of twist θ (in radians) of a shaft of length L carrying a torque T is
θ = T L / G J
where G is the modulus of rigidity (shear modulus). This formula is valid for prismatic (constant cross-section) shafts made of linearly elastic, homogeneous material under small deformations.
Polar moment J measures a section's resistance to torsion. For circular sections the standard expressions are:

For a solid circular shaft of diameter d (or radius R = d/2),
J = π d^4 / 32 = π R^4 / 2


For a hollow circular shaft with outer diameter D and inner diameter d,
J = π (D^4 - d^4) / 32
The torsional section modulus Z is defined as
Z = J / c
where c is the outer radius (distance from neutral axis to extreme fibre). The maximum shear stress at the outer surface is
τ_max = T / Z = T·c / J
The shear stress distribution for circular shafts is:


When a shaft rotates at N revolutions per minute (rpm) and transmits torque T (in N·m), the power P (in watts) transmitted is
P = 2π N T / 60

In SI units, P (W) = T (N·m) × angular speed ω (rad/s), where ω = 2πN/60.
In shaft design the resisting couple developed by internal shear stresses must equal the applied torque. Using τ_max = T·c / J, the maximum torque that can be transmitted safely (based on an allowable shear stress τ_allow) is
T_max = τ_allow · J / c

The maximum torque transmitted by a circular solid shaft is obtained from the maximum shear stress induced at the outer surface. Substituting J for a solid shaft gives a direct expression for T_max in terms of diameter and allowable shear.

Torque transmitted by a hollow circular shaft is obtained in the same way as for a solid shaft by using the polar moment of inertia for a hollow section. Hollow shafts are commonly used when weight or material economy is important because they provide higher torsional rigidity per unit weight in many practical cases.

A composite shaft consists of two or more shaft segments of different materials, diameters or lengths joined together. Two important connection types are:
When shafts are in series, the torque in each segment is equal to the applied torque. The total angle of twist is the sum of the twists of each segment. For two shafts in series, with the same torque T, lengths L1 and L2, moduli G1 and G2, and polar moments J1 and J2:
θ_AC = θ_AB + θ_BC
and
θ_total = T L1 / (G1 J1) + T L2 / (G2 J2)


For shafts loaded so that their angle of twist is the same, torque is shared between the parallel members. The total torque is the sum of individual torques and equality of angles of twist gives a relation between the individual torques:
T = T1 + T2
θ1 = θ2
From θ = T L / G J, we obtain
T1 L1 / (G1 J1) = T2 L2 / (G2 J2)

The torsional strain energy stored in a shaft is equal to the work done in twisting it from zero torque to the final torque T. For a shaft of length L:
Work done = ∫0^T T' dθ = 1/2 T θ
Using θ = T L / (G J) leads to
U = 1/2 · T · θ = T^2 L / (2 G J) = (G J θ^2) / (2 L)



Torsional stiffness (denoted K) is the torque required to produce a unit radian twist. For a prismatic shaft of length L:
θ = T L / (G J)
so
K = G J / L
and
T = K θ
Summary: For circular shafts under pure torsion the central relations are τ(r) = T·r / J, θ = T L / (G J), J expressions for the section (solid or hollow), torsional section modulus Z = J/c, strain energy U = T^2 L / (2 G J) and torsional stiffness K = G J / L. These formulae form the foundation for analysis and design of shafts in civil, mechanical and allied engineering applications.
| 1. What is torsion in mechanical engineering? | ![]() |
| 2. How is torsion calculated in mechanical engineering? | ![]() |
| 3. What are some common applications of torsion in mechanical engineering? | ![]() |
| 4. How does material selection affect torsion in mechanical engineering? | ![]() |
| 5. What are the possible failure modes associated with torsion in mechanical engineering? | ![]() |