Scheduling is used to schedule resources in time to finish the tasks. Forecast demand plays a key role to determine the plan for the output.
It is the order in which jobs pass through the machines or workstations.
Johnson’s rule (Sequencing of n jobs on 2 machines)
Let, Ai = processing time of ith job on machine 1, Bi = processing time of ith job on machine 2, these problems are solved by Johnson’s rule and steps involved are:
(i) Find out the minimum of Ai and Bi.
(ii) If the minimum is for a particular job on machine A then, perform that job at the start or beginning.
(iii) If the minimum is for a particular job on machine B then, perform that job in the last.
(iv) Strike-off the job which is assigned so that it can’t be considered again.
(v) Continue in the similar manner until all the jobs are assigned.
Example: The above algorithm is illustrated with the following example.
Consider two machines and six jobs flow shop scheduling problem. Using Johnson’s algorithm, obtain the optimal sequence which will minimize the make span.
Step-1: Finding Sequence. Min Processing time of 1 min for job 6 on m1 and for job 3 on m2. Place job 6 first and job 3 at last. Continue this procedure. The sequence obtained is-
Step-2: Using this sequence, the make span for the jobs can be determined by the time in and time out:
Total flow time = 11 + 16 + 24 + 30 + 33 + 36 = 150
Avg. flow time = 150 / 6 = 25
Idle time for M1 = 1 minute.
Idle time for M2 = 1 + 2 = 3 minute.
Make span time of shop = 36 minute.
Sequencing of n jobs on 3 machines (Jackson Rule)
(i) Check (min)M1 ≥ (max)M2
(min)M3 ≥ (max)M2, At least one must satisfy.
(ii) Convert to two machines problem by adding machine 1 and 2,then machine 2 and solve using Johnson’s rule.
Assembly line is a special case of product layout in which the operations pertaining to assembly of different parts at few station line (product) layout is useful for high volume, single type of manufacturing activity. The aim of assembly line is to divide total work content into different work station. Such that idle time is minimized utilization is optimized.
Where, Tsi = Station time at station
i, n = Total number of stations
TC = Total cycle time.
Where, (Tsi)max = Maximum station time.
Note: If smoothness index is low, it means line balancing is good.
Method of line balancing- Largest candidate rule steps are:
Example: Let us consider the precedence diagram of 13 work elements shown below. The time each work element is at the top of each node. In a tabular form, this precedence diagram is represented as follows.
Total work content = 68 min
Largest work element time = 10 min
Thus, cycle time (TC) must satisfy TC ≥ 10 min
For minimum cycle time of 10 min, number of stations would be 68/10 = 6.8
Therefore, we must take stations lesser than this. Let us select 5 stations design. For 5
stations, the station time should be nearly equal to 68/5 = 13.6 min
List work elements in descending order of their work element.
Here, the final cycle time is the maximum station time which is 16 min.
Balance delay =x 100% = 15%
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1. What is the difference between scheduling and sequencing in the context of mechanical engineering? |
2. How does assembly line balancing contribute to efficient manufacturing processes? |
3. What are some common challenges faced in scheduling mechanical engineering projects? |
4. How can scheduling and sequencing be applied in the automotive industry? |
5. What are some techniques used for assembly line balancing in mechanical engineering? |
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