Haloalkanes are hydrocarbons in which hydrogen in a normal alkane is replaced by a halogen (group 17 elements). The physical properties of haloalkanes are mostly like a normal covalent compound. Halogens not being much reactive functional group as a carboxyl group or aldehyde doesn’t affect the overall physical properties by much. Still, few differences can be seen as we move down in the homologous series of the haloalkanes group due to the difference in atomic masses of the compound.
Alkyl halides are colourless when pure but bromides and iodides develop colour when exposed to light because they decompose into halogens.
The stability of the haloalkanes having the same alkyl group decreases in the order: R−F > R−Cl > R−Br > R−I since the strength of the C−X bond decreases in the order: C−F > C−Cl > C−Br > C−I
The dipole moment of methyl halides follows the order: CH3Cl > CH3F > CH3Br > CH3I. Due to the very small size of F, fluorides have lower dipole moments than chlorides.
Haloalkanes and Haloarenes can be prepared from other organic compounds by numerous methods. Different methods of preparation include conversion of alcohols to alkyl halides, the addition of halogens to alkenes, and hydrohalogenation of alkenes. The preparation techniques were so reliable and efficient that they became an inevitable part of industrial chemistry.
There are primarily 4 different types of preparation techniques of Haloalkanes and Haloarenes.
So let’s learn about the methods of preparation of Haloalkanes and Haloarenes.
Alkyl halides can easily be prepared from alcohols upon the addition of halides. In this reaction, the hydroxyl group of alcohol is replaced with the halogen atom attached to the other compound involved. This reaction requires a catalyst for primary and secondary alcohols whereas it doesn’t require any catalyst for tertiary alcohols.
The general reaction looks like this: ROH + HX → RX + H2O
a. Reaction with HCl:
b. Reaction with Bromine: CH3CH2OH + HBr → CH3CH2Br + H2O
c. Reaction with Phosphorous Halide:
d. Reaction with Thionyl Chloride:
The addition of hydrogen halides to alkenes follows either Markovnikov’s rule or exhibit the Kharash effect. All the electrophilic addition reactions of alkenes following the Markovnikov rule are known as Markovnikov addition reactions. A general example of such reaction is given below:
In free radical halogenation, we get a mixture of mono-substituted, di-substituted, tri-substituted, and even tetra-substituted halo-alkanes (alkyl halides). Since we require only one type of alkyl halide and not all in the form of a mixture, So this method is not used.
In this reaction, an alkyl chloride or alkyl bromide reacts with sodium iodide in acetone to form alkyl iodides.
The solubility difference of alkyl halides in acetone is used for driving the reaction in the forward direction. We know that sodium iodide is soluble in acetone but NaCl or NaBr are insoluble. Therefore, they precipitate out in the reaction which is easy to remove from the reaction mixture.
In this reaction, alkyl fluorides formation is possible by heating of Alkyl fluorides RBr/RCl. The reaction is carried out in the presence of metallic fluoride such as SbF3, Hg2F2, AgF, CoF2.
Aryl halides can be prepared by electrophilic aromatic substitution of arenes with halogens in the presence of a Lewis acid.
Mechanism of Electrophilic Substitution Reaction:
Sandmeyer’s Reaction is a two-step method that includes:
Primary aromatic amine reacts with sodium nitrite in the presence of cold mineral acid to form the diazonium salt. In this case, HNO2 is prepared within the reaction by reacting sodium nitrite and HX at a temperature of 273-278K.
Mechanism of the Sandmeyer’s Reaction:
101 videos|287 docs|123 tests
|
1. What are some physical properties of haloalkanes and haloarenes? |
2. How are haloalkanes and haloarenes prepared? |
3. What is a common method of preparation for haloalkanes and haloarenes? |
4. What are some key differences between haloalkanes and haloarenes in terms of physical properties? |
5. Can haloalkanes and haloarenes form hydrogen bonds with other molecules? |
|
Explore Courses for NEET exam
|