Worst, Average & Best Cases | Algorithms - Computer Science Engineering (CSE) PDF Download

Introduction

We can have three cases to analyze an algorithm:

1. The Worst Case
2. Average Case 
3. Best Case

Let us consider the following implementation of Linear Search:

C++
// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
// Linearly search x in arr[].
// If x is present then return the index,
// otherwise return -1
int search(int arr[], int n, int x)
{
    int i;
    for (i = 0; i < n; i++) {
        if (arr[i] == x)
            return i;
    }
    return -1;
}
// Driver Code
int main()
{
    int arr[] = { 1, 10, 30, 15 };
    int x = 30;
    int n = sizeof(arr) / sizeof(arr[0]);
    cout << x << " is present at index "
         << search(arr, n, x);
    getchar();
    return 0;
}
// This code is contributed
// by Akanksha Rai

C
// C implementation of the approach
#include <stdio.h>
// Linearly search x in arr[].
// If x is present then return the index,
// otherwise return -1
int search(int arr[], int n, int x)
{
    int i;
    for (i = 0; i < n; i++) {
        if (arr[i] == x)
            return i;
    }
    return -1;
}
/* Driver program to test above functions*/
int main()
{
    int arr[] = { 1, 10, 30, 15 };
    int x = 30;
    int n = sizeof(arr) / sizeof(arr[0]);
    printf("%d is present at index %d", x,
           search(arr, n, x));
    getchar();
    return 0;
}

Java
// Java implementation of the approach
public class GFG {
    // Linearly search x in arr[].  If x is present then
    // return the index, otherwise return -1
    static int search(int arr[], int n, int x)
    {
        int i;
        for (i = 0; i < n; i++) {
            if (arr[i] == x) {
                return i;
            }
        }

        return -1;
    }
    /* Driver program to test above functions*/
    public static void main(String[] args)
    {
        int arr[] = { 1, 10, 30, 15 };
        int x = 30;
        int n = arr.length;
        System.out.printf("%d is present at index %d", x,
                          search(arr, n, x));
    }
}
/*This code is contributed by PrinciRaj1992*/

Python3
# Python 3 implementation of the approach
# Linearly search x in arr[]. If x is present
# then return the index, otherwise return -1
def search(arr, x):
    for index, value in enumerate(arr):
        if value == x:
            return index
    return -1
# Driver Code
arr = [1, 10, 30, 15]
x = 30
print(x, "is present at index",
      search(arr, x))
# This code is contributed
# by PrinciRaj1992

C#
// C# implementation of the approach
using System;
public class GFG {
    // Linearly search x in arr[].  If x is present then
    // return the index, otherwise return -1
    static int search(int[] arr, int n, int x)
    {
        int i;
        for (i = 0; i < n; i++) {
            if (arr[i] == x) {
                return i;
            }
        }
        return -1;
    }
    /* Driver program to test above functions*/
    public static void Main()
    {
        int[] arr = { 1, 10, 30, 15 };
        int x = 30;
        int n = arr.Length;
        Console.WriteLine(x + " is present at index "
                          + search(arr, n, x));
    }
}
/*This code is contributed by PrinciRaj1992*/

PHP
<?php
// PHP implementation of the approach
// Linearly search x in arr[]. If x
// is present then return the index,
// otherwise return -1
function search($arr, $n, $x)
{
    for ($i = 0; $i < $n; $i++)
    {
    if ($arr[$i] == $x)
        return $i;
    }
    return -1;
}
// Driver Code
$arr = array(1, 10, 30, 15);
$x = 30;
$n = sizeof($arr);
echo $x . " is present at index ".
             search($arr, $n, $x);
// This code is contributed
// by Akanksha Rai

Output:
30 is present at index 2

Worst Case Analysis (Usually Done)

In the worst case analysis, we calculate upper bound on running time of an algorithm. We must know the case that causes maximum number of operations to be executed. For Linear Search, the worst case happens when the element to be searched (x in the above code) is not present in the array. When x is not present, the search() functions compares it with all the elements of arr[] one by one. Therefore, the worst case time complexity of linear search would be Θ(n).

Average Case Analysis (Sometimes done)

In average case analysis, we take all possible inputs and calculate computing time for all of the inputs. Sum all the calculated values and divide the sum by total number of inputs. We must know (or predict) distribution of cases. For the linear search problem, let us assume that all cases are uniformly distributed (including the case of x not being present in array). So we sum all the cases and divide the sum by (n+1). Following is the value of average case time complexity.

Best Case Analysis (Bogus)

In the best case analysis, we calculate lower bound on running time of an algorithm. We must know the case that causes minimum number of operations to be executed. In the linear search problem, the best case occurs when x is present at the first location. The number of operations in the best case is constant (not dependent on n). So time complexity in the best case would be Θ(1)
Most of the times, we do worst case analysis to analyze algorithms. In the worst analysis, we guarantee an upper bound on the running time of an algorithm which is good information.
The average case analysis is not easy to do in most of the practical cases and it is rarely done. In the average case analysis, we must know (or predict) the mathematical distribution of all possible inputs.
The Best Case analysis is bogus. Guaranteeing a lower bound on an algorithm doesn’t provide any information as in the worst case, an algorithm may take years to run.
For some algorithms, all the cases are asymptotically same, i.e., there are no worst and best cases. For example, Merge Sort. Merge Sort does Θ(nLogn) operations in all cases. Most of the other sorting algorithms have worst and best cases. For example, in the typical implementation of Quick Sort (where pivot is chosen as a corner element), the worst occurs when the input array is already sorted and the best occur when the pivot elements always divide array in two halves. For insertion sort, the worst case occurs when the array is reverse sorted and the best case occurs when the array is sorted in the same order as output.